/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 a) Graph the function. b) Draw... [FREE SOLUTION] | 91Ó°ÊÓ

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a) Graph the function. b) Draw tangent lines to the graph at points whose \(x\) -coordinates are \(-2,0\), and \(1 .\) c) Find \(f^{\prime}(x)\) by determining \(\lim _{h \rightarrow 0} \frac{\int(x+h)-f(x)}{h}\). d) Find \(f^{\prime}(-2), f^{\prime}(0)\), and \(f^{\prime}(1)\). How do these slopes compare with those of the lines you drew in part (b)? $$f(x)=\frac{1}{x}$$

Short Answer

Expert verified
1. Graph f(x)=1/x. 2. Draw tangent lines at x=-2, 0, and 1. 3. Derivative: f'(x)=-1/x^2. 4. Slopes are -1/4 (x=-2), undefined (x=0), -1 (x=1).

Step by step solution

01

- Graph the Function

Graph the function given by the equation: \[ f(x) = \frac{1}{x} \] Sketch the hyperbola, noting that it has vertical and horizontal asymptotes at \( x = 0 \) and \( y = 0 \), respectively.
02

- Draw Tangent Lines

For each specified x-coordinate (-2, 0, and 1), identify the points on the graph and draw tangent lines to the curve at these points.
03

- Find the Derivative

To find the derivative function \( f^{\text{prime}} (x) \), use the limit definition of the derivative: \[ f^{\text{prime}} (x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \] Substituting \( f(x) = \frac{1}{x} \) yields: \[ f^{\text{prime}} (x) = \lim_{h \to 0} \frac{\frac{1}{x+h} - \frac{1}{x}}{h} \] Simplify the expression inside the limit: \[ f^{\text{prime}} (x) = \lim_{h \to 0} \frac{\frac{x - (x+h)}{x(x+h)}}{h} = \lim_{h \to 0} \frac{-h}{h x(x+h)} = \lim_{h \to 0} \frac{-1}{x(x+h)} \] Evaluating the limit gives: \[ f^{\text{prime}} (x) = \frac{-1}{x^2} \]
04

- Compute Derivative Values at Special Points

Evaluate the derivative \( f^{\text{prime}} (x) \) at the specified x-coordinates. \[ f^{\text{prime}} (-2) = \frac{-1}{(-2)^2} = \frac{-1}{4} \] \[ f^{\text{prime}} (0) \text{ is undefined since division by zero is undefined.} \] \[ f^{\text{prime}} (1) = \frac{-1}{1^2} = -1 \]
05

- Compare Slopes of Tangent Lines

Compare the slopes of the tangent lines drawn in Step 2 to the derivative values found in Step 4. The slopes from the derivative values are: - at \( x = -2 \): \( \frac{-1}{4} \) - at \( x = 0 \): undefined - at \( x = 1 \): \( -1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

tangent lines
To begin understanding tangent lines, imagine a point touching a curve only at one specific place. This touching line is your tangent line. It represents the slope or steepness of the curve at that point.
When we talk about tangent lines in functions, we refer to drawing them on the graph at given x-coordinates. In our example, for the function \( f(x) = \frac{1}{x} \), we aim to draw tangent lines at \(-2, 0\), and \(1\).
Suppose you plot the graph and choose a point like \(x = -2\). Approximating the slope there will give you the right tangent. Likewise, do it for other points.
It's crucial to understand tangent lines visually to help with grasping how derivatives behave and change across different parts of a function.
limit definition of derivative
The derivative measures how a function changes as its input changes. The limit definition of the derivative tells us how to find it exactly.
For a function \(f(x)\), the derivative is found using the formula:
\[ f^{\text{prime}} (x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]
This formula is crucial because it calculates the precise rate of change or slope of the function at any point. Let's break it down: The value \(h\) represents a tiny change in \(x\).
  • When \(x\) shifts by \(h\), the corresponding shift in \(f(x)\) gets measured.
  • The smaller \(h\) becomes, the closer \(f(x+h) - f(x)\) approximates the exact change rate at \(x\).
    Keep this in mind for understanding the behavior of functions closely.
calculating derivatives
Calculating derivatives follows from the limit definition, but let's simplify processes used in practice. For the function \(f(x) = \frac{1}{x}\), let's derive its derivative step by step:
Start with the limit definition:
\[ f^{\text{prime}}(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]
Substitute \(f(x) = \frac{1}{x}\):
\[ f^{\text{prime}}(x) = \lim_{h \to 0} \frac{\frac{1}{x+h} - \frac{1}{x}}{h} \]
Simplify the fraction within the limit:
\[ f^{\text{prime}}(x) = \lim_{h \to 0} \frac{\frac{x - (x+h)}{x(x+h)}}{h} = \lim_{h \to 0} \frac{-h}{h \cdot x \(x+h\)} = \lim_{h \to 0} \frac{-1}{x \(x+h\)} \]
Finally, solve the limit:
\[ f^{\text{prime}}(x) = \frac{-1}{x^2} \]
This result tells us how \(f(x) = \frac{1}{x}\) changes at any given \(x\) point. After that, calculate specific values like \(f^{\text{prime}}(-2), f^{\text{prime}}(0)\), and \(f^{\text{prime}}(1)\).
Note: \(f^{\text{prime}}(0)\) is undefined since \(-1\) divided by \(0\) is not possible.
graphing functions
Graphing functions helps visualize their behavior and properties. Let's consider \(f(x) = \frac{1}{x}\).
This particular function is a hyperbola, a unique type of curve with two branches. To accurately graph it, remember some key points:
- \(x = 0\) is a vertical asymptote, meaning the function approaches this line but never intersects it.
- Similarly, \(y = 0\) is a horizontal asymptote.
  • Sketch the curve by drawing two parts approaching these asymptotes.
  • This visualization aids in understanding how values rapidly change near \(x = 0\).
Practicing graphing various functions can immensely deepen your understanding of their dynamics.
For our example, adding tangent lines at \(-2, 0, 1\) on your graph will enhance your insight into how derivatives represent slopes at specific points.

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Most popular questions from this chapter

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