Chapter 9: Problem 47
Use a rotation matrix to rotate the vector \(\left[\begin{array}{r}5 \\\ -3\end{array}\right]\) clockwise by the angle \(\pi / 2\).
Short Answer
Expert verified
The vector rotated clockwise by \( \pi/2 \) is \( \begin{bmatrix} 3 \\ 5 \end{bmatrix} \).
Step by step solution
01
Identify the Rotation Matrix
When rotating a 2D vector by an angle \theta clockwise, we use the following rotation matrix: \[ R = \begin{bmatrix} \cos(\theta) & \sin(\theta) \ -\sin(\theta) & \cos(\theta) \end{bmatrix} \]. Since we are rotating by \( \pi/2 \) clockwise, \( \theta = -\pi/2 \). Substitute \( \theta \) into the rotation matrix: \[ R = \begin{bmatrix} \cos(-\pi/2) & \sin(-\pi/2) \ -\sin(-\pi/2) & \cos(-\pi/2) \end{bmatrix} \].
02
Compute the Cosine and Sine Values
Recall that \( \cos(-\pi/2) = 0 \) and \( \sin(-\pi/2) = -1 \). Substitute these values into the matrix: \[ R = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \].
03
Multiply the Rotation Matrix by the Vector
We multiply the rotation matrix \( R \) by the vector \( \mathbf{v} = \begin{bmatrix} 5 \ -3 \end{bmatrix} \). Perform the matrix multiplication: \[ R\mathbf{v} = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} 5 \ -3 \end{bmatrix} = \begin{bmatrix} (0)(5) + (-1)(-3) \ (1)(5) + (0)(-3) \end{bmatrix} = \begin{bmatrix} 3 \ 5 \end{bmatrix} \].
04
Interpret the Result
The result of the multiplication gives the coordinates of the rotated vector. Hence, the vector \( \begin{bmatrix} 5 \ -3 \end{bmatrix} \) rotated by \( \pi/2 \) clockwise is \( \begin{bmatrix} 3 \ 5 \end{bmatrix} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Rotation
Vector rotation in 2D space can be visualized as turning a point around the origin on a coordinate plane. Imagine you have a vector like an arrow, starting from the origin (0,0) and pointing to (5, -3). By rotating the vector, you change its direction while keeping the arrow's base fixed at the origin.
To achieve this mathematically, we use a rotation matrix. A rotation matrix helps to systematically adjust the vector's components (its x and y parts). In our case, when we rotate a vector by an angle \( \theta \), we apply the rotation matrix:
To achieve this mathematically, we use a rotation matrix. A rotation matrix helps to systematically adjust the vector's components (its x and y parts). In our case, when we rotate a vector by an angle \( \theta \), we apply the rotation matrix:
- \( \begin{bmatrix} \cos(\theta) & \sin(\theta) \ -\sin(\theta) & \cos(\theta) \end{bmatrix} \)
2D Transformations
2D transformations are operations that move or change objects within a two-dimensional plane. These transformations can include scaling, translation, and rotation, among others.
For rotation, specifically, the point or vector is rotated around a specified axis. In a 2D plane, this axis is the origin, (0,0). When performing a transformation, keeping track of angles is essential, as they determine how much rotation is applied.
Using the rotation matrix provides a straightforward method to achieve a precise transformation. By multiplying the original vector by the rotation matrix:
For rotation, specifically, the point or vector is rotated around a specified axis. In a 2D plane, this axis is the origin, (0,0). When performing a transformation, keeping track of angles is essential, as they determine how much rotation is applied.
Using the rotation matrix provides a straightforward method to achieve a precise transformation. By multiplying the original vector by the rotation matrix:
- We adjust the x and y coordinates of the vector
- Achieve a new orientation, while maintaining the vector's magnitude
Clockwise Rotation
When we talk about clockwise rotation, we refer to the direction in which the hands of a clock move, from the top to the right, then down, and finally back to the top again. For a mathematical rotation, the angle rotates in the same direction.
In the exercise, we rotate a vector by an angle of \( \frac{\pi}{2} \) clockwise, which is equivalent to -90 degrees. This specific operation shifts the position of our vector on the 2D plane. When we input an angle \( \theta = -\frac{\pi}{2} \) into the rotation matrix:
In the exercise, we rotate a vector by an angle of \( \frac{\pi}{2} \) clockwise, which is equivalent to -90 degrees. This specific operation shifts the position of our vector on the 2D plane. When we input an angle \( \theta = -\frac{\pi}{2} \) into the rotation matrix:
- \( \begin{bmatrix} \cos(-\frac{\pi}{2}) & \sin(-\frac{\pi}{2}) \ -\sin(-\frac{\pi}{2}) & \cos(-\frac{\pi}{2}) \end{bmatrix} = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \)