/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Find the equilibria of the follo... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the equilibria of the following differential equations. $$ \frac{d x}{d t}=x^{8}-1 $$

Short Answer

Expert verified
The equilibria are at \( x = 1 \) and \( x = -1 \) (real), with additional complex solutions given by eighth roots of unity.

Step by step solution

01

Set the Differential Equation to Zero

To find the equilibria, set the differential equation \( \frac{dx}{dt} = x^8 - 1 \) equal to zero, because equilibria occur when the rate of change is zero.
02

Solve the Resulting Algebraic Equation

Solve the equation \( x^8 - 1 = 0 \). This can be rewritten as \( x^8 = 1 \).
03

Find the Real Solutions

To find the real solutions to \( x^8 = 1 \), note that \( x = 1 \) and \( x = -1 \) satisfy this equation, since both elevate to a positive power that results in 1.
04

Consider Complex Solutions

Because \( x^8 = 1 \) is a complex equation too, the complete solution for \( x \) involves all eighth roots of unity, which are complex numbers in the form \( e^{2\pi i k/8} \) for \( k = 0, 1, ..., 7 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are mathematical equations that relate a function with its derivatives. These equations play a fundamental role in various fields like physics, engineering, and economics. The primary aim of solving differential equations is to find unknown functions that fulfill the given equation. They are broadly classified into two types—ordinary differential equations (ODEs) and partial differential equations (PDEs). While ODEs involve functions of a single variable, PDEs deal with functions of multiple variables. In our case, the equation \( \frac{d x}{d t} = x^8 - 1 \) is an ordinary differential equation. To find the equilibrium points, one sets the rate of change, represented by \( \frac{d x}{d t} \), to zero, because equilibrium points occur where the function is constant, meaning no change over time.
Roots of Unity
Roots of unity are fundamental when dealing with complex numbers and polynomial equations, particularly when these equations have solutions over the complex number field. The \( n \)-th roots of unity are solutions to the equation \( z^n = 1 \), where \( z \) is a complex number. In the context of our differential equation, when set into a form where complex solutions are valid \( x^8 = 1 \), we discover that there are not just real solutions like \( x = 1 \) and \( x = -1 \), but also complex solutions. These solutions can be represented by the formula \( e^{2\pi i k/8} \) for \( k = 0, 1, ..., 7 \). They form a circle in the complex plane, with each one equally spaced around the unit circle centered at the origin. These roots of unity denote the eighth roots of 1, which include the aforementioned real roots as well as other non-real complex numbers.
Stability Analysis
Stability analysis is a method used to determine whether equilibrium points of a differential equation are stable or unstable. This involves analyzing how the system behaves over time in the vicinity of these points. For first-order differential equations like \( \frac{d x}{d t} = x^8 - 1 \), this often involves checking the sign of the derivative around the equilibrium points. If we assess the derivative \( \frac{d^2 x}{d t^2} \) at solutions such as \( x = 1 \) and \( x = -1 \), positive derivatives suggest instability while negative derivatives suggest stability. For complex-valued equilibrium points, the analysis can become more intricate, often involving linear approximations or numerical simulations to predict system behavior. The aim is to understand whether small perturbations around an equilibrium will die out, reinforcing the equilibrium, or grow, leading the system away from equilibrium.

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Most popular questions from this chapter

Suppose that \(N(t)\) denotes the size of a population at time \(t\). The population evolves according to the logistic equation, but in addition, predation reduces the size of the population so that the rate of change is given by $$ \frac{d N}{d t}=g(N) $$ where $$ g(N)=N\left(1-\frac{N}{50}\right)-\frac{9 N}{5+N} $$ The first term on the right-hand side describes the logistic growth; the second term describes the effect of predation. (a) Make the vector field plot for this differential equation. (b) Find all equilibria of \((8.38)\). (c) Use your vector field plot in (a) to determine the stability of the equilibria you found in (b). (d) Repeat your analysis from part (c) but now use the method of eigenvalues to determine the stability of the equilibria you found in (b).

Bite strength varies as animals grow, which may mean that the animal's diet must change. Christiansen and Adolfsson (2005) studied the relationship between the strength of animal teeth with skull size in carnivores from the cat and dog families. They found that tooth strength \(S\), and skull length \(L\), were related in a power law: $$ S=C L^{2.85} $$ where \(C\) is some constant. Find the relationship between the relative rates of growth of \(S\) and \(L\) (i.e., between \(\frac{1}{S} \frac{d S}{d t}\) and \(\left.\frac{1}{L} \frac{d L}{d t}\right)\).

Homeostasis Sterner and Elser (2002) studied the relationship between the amount of nitrogen in an animal's body and the amount of nitrogen present in the food that it eats. Many animals maintain homeostasis (balance), that is, they control their own nitrogen content. As the amount of nitrogen present in their food increases, the amount of nitrogen in the animal's body increases more slowly. If the amount of nitrogen in the animal is \(N\) and the amount of nitrogen in its food is \(F\), Sterner and Elser argue that: $$ \frac{1}{N} \frac{d N}{d t}=\frac{\sigma}{F} \frac{d F}{d t} $$ where \(\sigma\) is a constant. (a) Show that if \(\sigma=1\), then \(N \propto F ;\) that is, the nitrogen content of the animal increases in proportion to its food. This is called absence of homeostasis. (b) If \(\sigma=0\), then \(N\) is a constant, independent of \(F\). This is called homeostasis (the animal maintains a balanced amount of nitrogen, independent of its food). (c) Show that if \(0<\sigma<1\), then, if \(F\) doubles, \(N\) also increases but by a factor less than 2 .

Find all equilibria, and, by calculating the eigenvalue of the differential equation, determine which equilibria are stable and which are unstable. $$ \frac{d x}{d t}=x e^{-x} $$

For make vector field plots of each of the differential equations. Find any equilibria of each differential equation and use your vector field plot to classify whether each equilibrium is stable or unstable. $$ \frac{d N}{d t}=N \ln (2 / N), N>0 $$

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