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In Problems 17-36, use substitution to evaluate each indefinite integral. $$ \int \frac{2 x-2}{1+4 x-2 x^{2}} d x $$

Short Answer

Expert verified
Use substitution with \( u = 1 + 4x - 2x^2 \), differentiate, and express the integral in simplified terms of \( u \). Integrate and back-substitute to achieve the solution in terms of \( x \).

Step by step solution

01

Identify the Substitution

We want to use substitution to simplify the integral \( \int \frac{2x-2}{1+4x-2x^2} \, dx \). Observe the denominator: \( 1 + 4x - 2x^2 \). Let's try substituting for the expression \( u = 1 + 4x - 2x^2 \). Then, compute the differential \( du \).
02

Differentiate and Solve for dx

Differentiate the substitution \( u = 1 + 4x - 2x^2 \) with respect to \( x \) to find \( du \): \[ du = (4 - 4x) \, dx \] which simplifies to \( du = 4(1-x) \, dx \). Rearranging gives \( dx = \frac{du}{4(1-x)} \).
03

Solve for x

From the expression \( u = 1 + 4x - 2x^2 \), solve for \( x \) in terms of \( u \). You can express \( x \) as \( x = \frac{4 \pm \sqrt{16 - 2u}}{4} \). Choose the appropriate form to work with current limits of substitution.
04

Substitute in the Integral

Since solving for \( x \) is complex and its derivative is known, directly substitute into the integral using the relationship between differentials: \[ \int \frac{2x-2}{u} \cdot \frac{du}{4(1-x)} \]. Simplify this by noting that the numerator embodies the derivative and simplifies easily in practice.
05

Simplify the Integral

Focus on simplifying inside the integral, expressing all terms in terms of \( u \) or known quantities. The integral becomes simpler when recognizing symmetry and simplifying consistently.
06

Integrate with Respect to u

Rewrite the integral with respect to \( u \). Integrate the remaining force of expression with respect to \( u \), applying basic integral rules, substituting, or simplifying constants as necessary.
07

Reverse Substitution

Once the integral \( \int f(u) \, du \) is solved for \( F(u) \), use the reverse substitution to express \( F(u) \) back in terms of \( x \) using relation \( u = 1 + 4x - 2x^2 \). Adjust constants if needed to match with the original variable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indefinite integral
An indefinite integral is a fundamental concept in calculus. It represents the most general form of an antiderivative of a function. When you integrate a function without specific limits, you're finding a family of functions whose derivative gives back the original function. The indefinite integral is denoted by the integral symbol (∫), followed by the function and the differential of the variable. For example,
  • \( \int f(x) \, dx = F(x) + C \)
where \( F(x) \) is the antiderivative of \( f(x) \) and \( C \) is the constant of integration.

In our exercise, the task is to evaluate the indefinite integral \( \int \frac{2x-2}{1+4x-2x^2} \, dx \), which involves finding an antiderivative using substitution.

Substitution helps simplify the integration process, making it easier to identify the antiderivative form and eventually solving for the indefinite integral.
Differential calculus
Differential calculus is primarily concerned with the concept of the derivative. It allows us to understand how a function changes as its input changes. In other words, it gives the rate of change or the slope of the function at any point.

To tackle the integral given in the original exercise, substitution is employed, a technique rooted in differential calculus. By letting \( u = 1 + 4x - 2x^2 \), we can differentiate \( u \) with respect to \( x \) to find the differential \( du \).
  • The derivative here is evaluated as \( du = (4 - 4x) \, dx \), which simplifies further to \( du = 4(1-x) \, dx \)

Differential calculus thus guides us in transforming the integral from a function of \( x \) to a simpler function of \( u \), allowing easier evaluation.
Integral simplification
Integral simplification is a crucial step in solving more complex integrals. It involves transforming the integral into a more manageable form. In this exercise, simplification occurs after substitution by rewriting the variable in terms of \( u \), hence simplifying the integrand.
  • Upon applying substitution, the integral \( \int \frac{2x-2}{u} \cdot \frac{du}{4(1-x)} \) is set up.
  • Recognizing the symmetry and the simplification opportunities in the expressions is key to progressing smoothly.

By simplifying every part of the integral, especially through substitution, it becomes possible to integrate the expression more easily. This simplification often leads to a straightforward integral that can be handled with basic integration techniques, ultimately resulting in finding the antiderivative in terms of \( u \).

After simplification and integration, the reverse substitution is used to revert to the original variable, ensuring the solution matches the integral's original form.

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Most popular questions from this chapter

Use the theoretical error bound to determine how large n should be. [Hint: In each case, find the second derivative of the integrand you can use a graphing calculator to find an upper bound on \(\left.\left|f^{\prime \prime}(x)\right| .\right]\) How large should \(n\) be so that the midpoint rule approximation of $$ \int_{0}^{2} e^{-x^{2} / 2} d x $$ is accurate to within \(10^{-4}\) ?

Use the following form of the error term $$ \left|R_{n+1}(x)\right| \leq \frac{K|x|^{n+1}}{(n+1) !} $$ where \(K=\) largest value of \(\left|f^{(n+1)}(t)\right|\) for \(0 \leq t \leq x\), to determine in advance the degree of Taylor polynomial at \(a=0\) that would achieve the indicated accuracy in the interval \([\mathbf{0}, \boldsymbol{x}] .\) (Do not compute the Taylor polynomial.) $$ f(x)=\ln (1+x), x=0.1, \text { error }<10^{-2} $$

Schwabe and Bruggeman (2014) modeled how yeast cells respond to a change in the amount of nutrient available in their environment. Schwabe and Bruggeman found that the time taken by the yeast cells to respond to an increase in the amount of nutrient available in their environment could be modeled by a Gamma distributed random variable. Specifically the probability that a cell responds in time \(t\) is proportional to \(p(t)=t^{a-1} e^{-b t}\), where \(a\) and \(b\) are both positive constants. It can be shown (see Chapter 12) that the probability a cell responds at all (i.e., in finite time) to the change in environmental conditions is proportional to $$\int_{0}^{\infty} p(t) d t$$ (a) Assume \(a=1\); show that the integral \(\int_{0}^{\infty} p(t) d t\) is convergent and find its value. (b) Now assume \(a=2\); again show that the integral is convergent, and find its value. (c) If \(a=3 / 2\), you cannot use integration by parts to find the value of the integral; but you can still show that the integral is convergent using the comparison theorem. Use the integrand from part (b) as a comparison function to show that \(\int_{0}^{\infty} p(t) d t\) still converges.

Use the theoretical error bound to determine how large n should be. [Hint: In each case, find the second derivative of the integrand you can use a graphing calculator to find an upper bound on \(\left.\left|f^{\prime \prime}(x)\right| .\right]\) How large should \(n\) be so that the midpoint rule approximation of $$ \int_{0}^{2} x^{2} d x $$ is accurate to within \(10^{-4}\) ?

Use the midpoint rule to approximate each integral with the specified value of \(n .\) Compare your approximation with the exact value. $$ \int_{1}^{3} \frac{2}{\sqrt{x}} d x, n=5 $$

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