Chapter 7: Problem 15
Compute the Taylor polynomial of degree \(n\) about \(x=0\) for each function and compare the value of the function at the indicated point with the value of the corresponding Taylor polynomial. $$ f(x)=\tan x, n=2, x=0.1 $$
Short Answer
Expert verified
The Taylor polynomial \(P_2(x)\) is \(x\), and at \(x=0.1\), it approximates \(\tan(0.1)\) well since both values are close: 0.1 and 0.10033.
Step by step solution
01
Recall the Taylor Polynomial Formula
The Taylor polynomial of degree \(n\) for a function \(f(x)\) about \(x=0\) is given by:\[P_n(x) = f(0) + f'(0)x + \frac{f''(0)x^2}{2!} + \cdots + \frac{f^{(n)}(0)x^n}{n!}\]Since \(n=2\), we need to calculate up to the second derivative of \(f(x)\).
02
Calculate the Derivatives at Zero
Let's compute the derivatives of \(f(x) = \tan(x)\) and evaluate them at \(x = 0\).- \(f(x) = \tan(x)\), so \(f(0) = \tan(0) = 0\).- \(f'(x) = \sec^2(x)\), so \(f'(0) = \sec^2(0) = 1\).- \(f''(x) = 2\sec^2(x)\tan(x)\), so \(f''(0) = 2\cdot 1 \cdot 0 = 0\).
03
Form the Second-Degree Taylor Polynomial
Substitute the derivatives evaluated at \(x=0\) into the Taylor polynomial:\[P_2(x) = 0 + 1\cdot x + \frac{0\cdot x^2}{2} = x\]Thus, the Taylor polynomial of degree 2 for \(\tan(x)\) about \(x=0\) is \(P_2(x) = x\).
04
Evaluate the Function and Polynomial at the Given Point
Now we compare the value of \(f(x)\) and \(P_2(x)\) at \(x=0.1\):- \(f(0.1) = \tan(0.1) \approx 0.10033\).- \(P_2(0.1) = 0.1\).
05
Compare Values
We see that the Taylor polynomial value \(P_2(0.1) = 0.1\) is very close to the actual function value \(f(0.1) \approx 0.10033\). This suggests that the polynomial is a good approximation near \(x=0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor series
A Taylor series is a powerful tool in mathematics used to express a function as an infinite sum of terms. These terms are calculated from the values of the function's derivatives at a specific point. The basic idea is to approximate complex functions with polynomials, which are easier to compute and understand. For a function, the Taylor series centered around a particular point (like zero) is constructed using:
- The function's value at that point.
- All derivatives of the function at that point.
derivatives
Derivatives are fundamental in calculus, representing the rate at which a function changes at a certain point. For the Taylor series, derivatives are crucial because they form the coefficients of the polynomial's terms. In the exercise, calculating derivatives of \(f(x) = \tan x\) gives us:
- First derivative: \(f'(x) = \sec^2(x)\), which indicates the slope or rate of change of the tangent function.
- Second derivative: \(f''(x) = 2\sec^2(x)\tan(x)\), which provides information about the curvature or concavity of the function.
approximation
In mathematics, approximation allows us to represent complicated expressions in a simpler form. Taylor polynomials serve as approximations to the actual functions. These polynomials give insights into the function's behavior near a specific point.
- In the exercise, the second-degree polynomial \(P_2(x) = x\) approximates \(f(x) = \tan x\).
- Such approximation is particularly useful when a quick estimate is needed, or when evaluating the precise function is cumbersome.
function evaluation
Function evaluation is an essential concept that involves calculating the output of a function for a given input. In the case of Taylor polynomials, it entails comparing the values of the function and the polynomial at a specific point.
- For this exercise, we evaluated both \(f(0.1) = \tan(0.1) \approx 0.10033\) and the polynomial \(P_2(0.1) = 0.1\).
- This comparison helps us gauge how well the polynomial approximates the function near the point of expansion.