Chapter 6: Problem 96
Compute the indefinite integrals. $$ \int\left(\frac{1}{\sqrt{x}}+\frac{1}{\sqrt{e^{x}}}\right) d x $$
Short Answer
Expert verified
The integral is \( 2\sqrt{x} - 2e^{-x/2} + C \).
Step by step solution
01
Simplify the Integral Expression
First, break down the given integral expression into two separate integrals. The expression \( \int \left( \frac{1}{\sqrt{x}} + \frac{1}{\sqrt{e^x}} \right) dx \) can be rewritten as two individual integrals: \( \int \frac{1}{\sqrt{x}} \, dx + \int \frac{1}{\sqrt{e^x}} \, dx \).
02
Solve the First Integral
Focus on solving the first integral \( \int \frac{1}{\sqrt{x}} \, dx \). This integral is equivalent to \( \int x^{-1/2} \, dx \). Using the power rule for integration, \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), where \( n = -\frac{1}{2} \), we get \( \frac{x^{1/2}}{1/2} + C = 2x^{1/2} + C \). Thus, the result is \( 2\sqrt{x} + C_1 \).
03
Solve the Second Integral
Now solve the second integral \( \int \frac{1}{\sqrt{e^x}} \, dx \). This can be rewritten as \( \int e^{-x/2} \, dx \). Recognizing this as the integral of an exponential function, we use the formula \( \int e^{ax} \, dx = \frac{1}{a}e^{ax} + C \). Here, \( a = -\frac{1}{2} \), so the solution is \( \frac{1}{-1/2} e^{-x/2} + C = -2e^{-x/2} + C_2 \).
04
Combine the Results
Add the results from Step 2 and Step 3, as the original problem was a sum of two integrals. Combine \( 2\sqrt{x} + C_1 \) and \( -2e^{-x/2} + C_2 \) to get: \( 2\sqrt{x} - 2e^{-x/2} + C \), where \( C \) is a constant representing the sum of \( C_1 \) and \( C_2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule for Integration
The power rule for integration is a fundamental technique in calculus. If you have a function of the form \( x^n \), you can easily find its indefinite integral using this rule. The formula for the power rule is:
- \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \)
Exponential Functions
Exponential functions are a class of functions that involve the constant \( e \), the base of the natural logarithm, and exponents. These functions are unique because they have a constant relative rate of change; they grow or decay at a rate proportional to their value at any point. The general form of an exponential function is:
- \( f(x) = e^{ax} \)
- \( \int e^{ax} \, dx = \frac{1}{a}e^{ax} + C \)
Integration Techniques
Integration is about finding a function whose derivative equals a given function. To do this effectively, one must be familiar with various integration techniques. These methods transform complex integrals into simpler ones that are more manageable. Some basic techniques include:
- Substitution: Used when an integral contains a function and its derivative. You replace a part of the integral to simplify it.
- Integration by Parts: Useful when integrating products of functions. It's based on the product rule for differentiation.