Chapter 6: Problem 60
In Problems , verify each inequality without evaluating the integrals. $$ \int_{2}^{4} x d x \leq \int_{2}^{4} x^{2} d x $$
Short Answer
Expert verified
Yes, the inequality is verified because \( x \leq x^2 \) for \( x \geq 1 \).
Step by step solution
01
Understand the Given Inequality
The inequality to verify is \( \int_{2}^{4} x \, dx \leq \int_{2}^{4} x^{2} \, dx \). This means we need to show that the integral of \( x \) over the interval [2,4] is less than or equal to the integral of \( x^2 \) over the same interval.
02
Compare the Functions
Consider the functions \( f(x) = x \) and \( g(x) = x^2 \). For \( x \in [2, 4] \), it is noticeable that \( f(x) \leq g(x) \) because for any \( x \geq 1 \), \( x \leq x^2 \). This is the comparison which will help us verify the inequality without evaluating the integrals.
03
Use the Property of Integrals
A property of definite integrals states that if \( f(x) \leq g(x) \) for all \( x \) in \([a,b]\), then \( \int_{a}^{b} f(x) \, dx \leq \int_{a}^{b} g(x) \, dx \). Since we established in Step 2 that \( f(x) \leq g(x) \) over \([2, 4]\), it follows that \( \int_{2}^{4} x \, dx \leq \int_{2}^{4} x^{2} \, dx \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
In calculus, a definite integral represents the accumulation of quantities, such as areas under a curve, for a specific interval indicated by the lower and upper summation limits. Understanding definite integrals is crucial since they help calculate the net area between the x-axis and the curve of the function over a specified interval.
\[ \int_{a}^{b} f(x) \, dx \]This notation signifies the definite integral of a function \( f(x) \) from \( a \) to \( b \). Here, \( a \) and \( b \) are the bounds, or limits of integration, and \( f(x) \) is the function being integrated.
\[ \int_{a}^{b} f(x) \, dx \]This notation signifies the definite integral of a function \( f(x) \) from \( a \) to \( b \). Here, \( a \) and \( b \) are the bounds, or limits of integration, and \( f(x) \) is the function being integrated.
- The definite integral measures how much the function accumulates between \( a \) and \( b \).
- Unlike indefinite integrals, definite integrals result in a specific numerical value.
- They can represent areas under curves when \( f(x) \) is positive, but also handle curves below the x-axis by considering areas as negative.
Comparison of Functions
When working with inequalities involving integrals, comparing functions within the same range is a fundamental step. As we saw in our exercise, comparing the functions \( f(x) = x \) and \( g(x) = x^2 \) illustrates this. For any value \( x \geq 1 \), \( x \leq x^2 \), implying \( f(x) \leq g(x)\)in the interval \( [2, 4]\).To compare functions effectively:
- Identify intervals where one function consistently stays above or below the other.
- Determine the function behavior (increasing or decreasing) over the interval.
- Use algebraic inequalities when necessary to confirm comparisons.
Properties of Integrals
Definite integrals showcase several properties that simplify calculation and aid in problem-solving. One such essential property is the comparison property, which is critical in verifying integral inequalities. The property asserts:\[ \text{If } f(x) \leq g(x) \text{ for } x \in [a, b], \text{ then } \int_{a}^{b} f(x) \, dx \leq \int_{a}^{b} g(x) \, dx.\]This property comes into play when one can visually or algebraically verify that one function dominates another over a certain interval. Some other notable properties of integrals include:
- Linearity: \( \int_{a}^{b} [cf(x) + dg(x)] \, dx = c\int_{a}^{b} f(x) \, dx + d\int_{a}^{b} g(x) \, dx \). This shows how integrals distribute over addition.
- Reversal of limits: \( \int_{a}^{b} f(x) \, dx = -\int_{b}^{a} f(x) \, dx \). Reversing the limits flips the integral's sign.
- Zero Width Interval: \( \int_{a}^{a} f(x) \, dx = 0 \). Integrating over a zero-width interval results in zero.