Chapter 5: Problem 27
. Show that \(f(x)=|x|\) has a local minimum at \(x=0\) but \(f(x)\) is not differentiable at \(x=0\).
Short Answer
Expert verified
The function has a local minimum at \( x=0 \) but is not differentiable there due to a discontinuous derivative.
Step by step solution
01
Identify the Function Behavior
The function given is the absolute value function, \[ f(x) = |x| \]. This function is defined such that \[ f(x) = \begin{cases} -x, & \text{if } x < 0 \ x, & \text{if } x \geq 0 \end{cases} \]. The function consists of two linear pieces, \( -x \) for negative values of \( x \) and \( x \) for non-negative values of \( x \).
02
Checking for Local Minimum at x=0
To determine if there is a local minimum at \( x = 0 \), observe the function values around \( x = 0 \). For \( x < 0 \), \( f(x) = -x \) which increases as \( x \) approaches 0 from the left. Similarly, for \( x \geq 0 \), \( f(x) = x \) also increases as \( x \) moves away from 0. Hence, \( f(x) \geq f(0) \) for all \( x \), and thus \( f(x) \) has a local minimum at \( x = 0 \).
03
Differentiability Check at x=0
A function is differentiable at a point if the derivative exists at that point. To check if \( f(x) \) is differentiable at \( x=0 \), consider calculating the derivative from the left and right. The derivative from the left, \( x < 0 \), would be \( f'(x) = -1 \) and from the right, \( x \geq 0 \), would be \( f'(x) = 1 \). Since the left-hand derivative and the right-hand derivative at \( x = 0 \) do not agree, \( f(x) \) is not differentiable at \( x = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
local minimum
In mathematics, a local minimum is a point where a function takes the smallest value in its immediate surroundings. For a function like the absolute value function, \( f(x) = |x| \), this can be easily observed around \( x = 0 \). If we evaluate \( f(x) \) at values slightly less than and greater than zero, we notice the behavior of the function.
- For \( x < 0 \), \( f(x) = -x \) reflects a positive slope approaching 0, meaning it decreases moving towards zero.
- Conversely, for \( x \geq 0 \), \( f(x) = x \), which indicates a positive slope continuing from zero as x increases.
absolute value function
The absolute value function, \( f(x) = |x| \), is a distinct and important mathematical concept. Its definition accommodates two situations based on whether \( x \) is negative or non-negative. Formally, it is expressed as:
- \( f(x) = -x \) when \( x < 0 \)
- \( f(x) = x \) when \( x \geq 0 \)
differentiability criteria
Differentiability is a measure of a function's smoothness at a point. For a function to be differentiable at a particular point, the left-hand derivative and right-hand derivative at this point must be equal. The absolute value function \( f(x) = |x| \) , however, displays non-differentiability at \( x = 0 \) due to differing derivatives from either side:
- When approaching 0 from the left \( (x < 0) \), the derivative is \( f'(x) = -1 \).
- When approaching 0 from the right \( (x \geq 0) \), the derivative is \( f'(x) = 1 \).