/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Find the general antiderivative ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the general antiderivative of the given function. $$ f(x)=5\left(1-x^{2}\right) $$

Short Answer

Expert verified
The general antiderivative is \( \int f(x) \, dx = 5x - \frac{5}{3}x^3 + C, \) where \( C \) is a constant.

Step by step solution

01

Understand the Function

We need to find the general antiderivative, or indefinite integral, of the function given by \[ f(x) = 5(1-x^2). \]This requires us to apply the rules of integration to each part of the expression inside the function.
02

Separate the Function

Identify the separate terms in the expression. Distribute the factor of 5 across the parentheses:\[ f(x) = 5 \times 1 - 5 \times x^2 = 5 - 5x^2. \]Now we have two terms that we will integrate separately.
03

Integrate Each Term

Now, integrate each term separately using basic integration rules. The integral of a constant \(5\) with respect to \(x\) is \(5x\). The integral of \(-5x^2\) with respect to \(x\) is \[-\frac{5}{3}x^{3},\] since the power rule for integration states \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\).
04

Combine the Integrals

Add the results from integrating each term:\[ \int f(x) \, dx = 5x - \frac{5}{3}x^3 + C, \]where \(C\) is the constant of integration that comes from the indefinite integral. This is the general form of the antiderivative.
05

Verify the Antiderivative

Differentiate the antiderivative to verify that it produces the original function:\[ \frac{d}{dx}(5x - \frac{5}{3}x^3 + C) = 5 - 5x^2. \]Since the result matches the original function \(f(x)\), our antiderivative is correct.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration
Integration is a core aspect of calculus, often described as the reverse process of differentiation. While differentiation involves finding the rate of change, integration involves finding the original function given its derivative. This means it helps us find functions when we know their rate of change, like measuring the area under curves on a graph.
The process of integration allows us to add up small quantities, which can be thought of as a summation of tiny parts to find a whole. This technique is applied in physics to calculate quantities like mass, area, and volume. In mathematics, it can be used to solve various functional equations. One of the most fundamental methods used in integration is applying specific rules which help simplify and solve integrals for different forms of functions.
For any given function, integration helps us determine an antiderivative, providing a way to recover the function that was initially differentiated.
Indefinite Integral
The term indefinite integral refers to finding an entire family of antiderivatives for a function. Instead of producing a numeric answer like in definite integrals, indefinite integrals yield a function, expressed in terms of a variable plus a constant. This constant, often denoted as "C," is crucial because it represents any constant that, when differentiated, would disappear (since the derivative of a constant is zero).
In practice, computing the indefinite integral involves applying integration techniques to each part of a function separately and then summing the results. The result is expressed as an antiderivative with the constant of integration. To verify the correctness, we can differentiate this antiderivative. If our function reappears, our indefinite integral computation is correct.
Indefinite integrals are fundamental in real-world applications like computing displacement from velocity or reconstructing original price functions from cost functions.
Power Rule for Integration
The power rule for integration is a corner-stone technique used to integrate terms of the form \(x^n\). This rule simplifies integrating polynomial functions.
The power rule states that the integral of \(x^n\) with respect to \(x\) is \( \frac{x^{n+1}}{n+1} + C \), provided that \(neq -1\). The addition of \(C\), the constant of integration, acknowledges the family of functions that differ only by a constant.
Applying the power rule requires careful attention to the exponent \(n\):
  • Increase the power of \(x\) by one, yielding \(x^{n+1}\).
  • Divide by the new power \(n+1\).
  • Add the constant of integration \(C\).
In practical scenarios, this rule transforms complex polynomial expressions into integrable forms, making it easier to derive general antiderivatives. This essential tool is employed whenever determining the antiderivatives of polynomial functions to reconstruct original functions from their derivatives.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the general antiderivative of the given function. $$ f(x)=2 \sin \left(\frac{\pi}{2} x\right)-3 \cos \left(\frac{\pi}{2} x\right) $$

Use the Newton-Raphson method to solve the equation $$ \sin x=\frac{1}{2} x $$ in the interval \((0, \pi)\).

A commonly used model for the density-dependent dynamics of a population is the recurrence equation: $$N_{t+1}=R N_{t}^{b}$$ where \(b, R>0\) are constants that take different values depending on the species of organism that is being modeled and its habitat. When \(b=1\), the model predicts that the population will grow exponentially. (a) Show that the population has a non-trivial equilibrium point (that is \(N \neq 0\) ), that you should determine. (b) Show that if \(-11\) ? Let \(b=2\) and \(R=1\), so \(N_{t+1}=N_{t}^{2}\). Find all of the equilibria of the recursion relation, and determine which (if any) are stable. (d) Calculate the first ten terms of the recursion relation \(N_{t+1}=\) \(N_{t}^{2}\) if (i) \(N_{0}=0.5\) and (ii) \(N_{0}=2 ?\) (e) If \(N_{t+1}=N_{t}^{2}\), what are the possible behaviors of the population as \(t \rightarrow \infty\) ?

Find the general antiderivative of the given function. $$ f(x)=x^{-7}+3 x^{5}+\sin (2 x) $$

The Ricker model was introduced by Ricker (1954) as an alternative to the discrete logistic equation to describe the density-dependent growth of a population. Under the Ricker model the population \(N_{t}\) sampled at discrete times \(t=0,1,2, \ldots\) is modeled by a recurrence equation $$N_{t+1}=R_{0} N_{t} \exp \left(-a N_{t}\right)$$ where \(R_{0}\) and \(a\) are positive constants that will vary between different species and between different habitats. (a) Explain why you would expect \(R_{0}>1\) (Hint: consider the population growth when \(N_{t}\) is very small.) (b) Show that the recursion relation has two equilibria, a trivial equilibrium (that is, \(N=0\) ) and another equilibrium, which you should find. (c) Show that if \(R_{0}>1\) then use the stability criterion for equilibria to show that the trivial equilibrium point is unstable. (d) Use the stability criterion for equilibria to show that the nontrivial equilibrium point is stable if \(0<\ln R_{0}<2\). (e) If \(R_{0}>1\) then \(\ln R_{0}>0\), so most populations will meet the first inequality condition. What happens if \(\ln R_{0}>2 ?\) Let's try some explicit values: \(R_{0}=10, a=1, N_{0}=1 .\) Calculate the first ten terms of the sequence, and describe in words how the sequence behaves.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.