Chapter 5: Problem 10
Find the local maxima and minima of each of the functions. Determine whether each function has local maxima and minima and find their coordinates. For each function, find the intervals on which it is increasing and the intervals on which it is decreasing. \(y=\cos \left(\pi x^{2}\right),-1 \leq x \leq 1\)
Short Answer
Step by step solution
Find the Derivative
Find Critical Points
Evaluate Second Derivative
Determine Increasing/Decreasing Intervals
Summarize Findings
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Local Maxima and Minima
Critical points occur where the derivative of the function equals zero or does not exist. At these points, the function stops increasing and starts decreasing, or vice versa. For this specific function, critical points were found at \( x = 0, x = \pm 1 \) within the interval \([-1, 1]\).
Next, to determine whether these points are maxima or minima, we use the second derivative test. By calculating the second derivative and evaluating it at these critical points, we gain insights into the function's curvature at those points:
- If the second derivative is positive, the point is a local minimum.
- If the second derivative is negative, the point is a local maximum.
- If the second derivative is zero, the test is inconclusive, and more information is needed.
In this case, the second derivative at \( x = \pm 1 \) is negative, indicating these points are local maxima.
Derivative
The chain rule states that if you have a composite function, say \( f(g(x)) \), then its derivative is computed as the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. Applying this to our function, the derivative is calculated as:\[ \frac{dy}{dx} = -2\pi x \sin(\pi x^2) \]
This expression tells us how the value of \( y \) changes as \( x \) changes. Critical points arise where this derivative is zero or undefined, showcasing major shifts in the function's behavior.
Increasing and Decreasing Intervals
A function is:
- Increasing when the derivative is positive.
- Decreasing when the derivative is negative.
In this context, the derivative evaluates the slope or rate of change of the function at any point. Due to the periodic nature of the \( \sin \) function, the sign of \( \sin(\pi x^2) \) causes the derivative to alternate between positive and negative, contributing to an oscillating behavior rather than monotonically increasing or decreasing intervals.
This specific function often switches between increasing and decreasing, with complex behavior. The oscillating nature results in no straightforward increasing or decreasing intervals across \([-1, 1]\). Instead of clean-cut intervals, you're observing a back-and-forth zigzag-like behavior throughout.