Chapter 4: Problem 57
Differentiate the functions with respect to the independent variable. (Note that log denotes the logarithm to base 10.) $$ f(x)=\log \left(x^{3}-3 x\right) $$
Short Answer
Expert verified
The derivative is \( f'(x) = \frac{3x^2 - 3}{x^3 - 3x} \).
Step by step solution
01
Identify the Function
The given function is \( f(x) = \log(x^3 - 3x) \). This is a composite function involving a logarithm and a polynomial.
02
Apply the Chain Rule
To differentiate \( f(x) \), use the chain rule. The chain rule states that \( \frac{d}{dx} \log(u) = \frac{1}{u} \cdot \frac{du}{dx} \), where \( u = x^3 - 3x \).
03
Differentiate the Inner Function
First, differentiate the inner function \( u = x^3 - 3x \). The derivative is \( \frac{du}{dx} = 3x^2 - 3 \).
04
Differentiate the Logarithmic Function
Now, apply the differentiation of \( \log(u) \). The derivative is \( \frac{1}{u} \times \frac{du}{dx} = \frac{1}{x^3 - 3x} \times (3x^2 - 3) \).
05
Simplify the Expression
Finally, simplify the expression to find the derivative \( f'(x) = \frac{3x^2 - 3}{x^3 - 3x} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The Chain Rule is a fundamental tool in calculus for differentiating composite functions. A composite function is a function made up of other functions; you can think of it like a function within a function.
When you differentiate composite functions, you use the chain rule to "unwrap" the layers. Imagine peeling an onion—each layer is like a function you need to differentiate.
The formal expression for the chain rule is:
When you differentiate composite functions, you use the chain rule to "unwrap" the layers. Imagine peeling an onion—each layer is like a function you need to differentiate.
The formal expression for the chain rule is:
- If given a composite function \( f(x) = g(h(x)) \), the derivative \( f'(x) \) is found by multiplying the derivatives of each function:
\( f'(x) = g'(h(x)) \, h'(x) \).
Logarithmic Differentiation
Logarithmic differentiation is a technique particularly useful when dealing with logarithmic functions. In the given exercise, the function is \( f(x) = \log(x^3 - 3x) \), where "log" represents the logarithm.
When differentiating a logarithm, the chain rule also comes into play.
The key part is that the derivative of \( \log(u) \), where \( u \) is a function of \( x \), is given by:
When differentiating a logarithm, the chain rule also comes into play.
The key part is that the derivative of \( \log(u) \), where \( u \) is a function of \( x \), is given by:
- \( \frac{d}{dx} \log(u) = \frac{1}{u} \cdot \frac{du}{dx} \)
- First, identify the argument of the log.
- Differentiate the argument.
- Apply the rule \( \frac{1}{u} \cdot \frac{du}{dx} \) to get the complete derivative.
Composite Functions
A composite function appears when one function is nested inside another, and mastering them requires identifying inner and outer functions. Consider the expression \( f(x) = \log(x^3 - 3x) \), where the outer function is the logarithm, and the inner function is the polynomial \( x^3 - 3x \).
To tackle a composite function, understand it as layers to be differentiated piece by piece.
To tackle a composite function, understand it as layers to be differentiated piece by piece.
- Outer Function: This is the "container" of the inner function. In our case, \( \log(u) \) where \( u = x^3 - 3x \).
- Inner Function: Found inside the outer function, this is what we first differentiate. For \( u = x^3 - 3x \), its derivative is \( 3x^2 - 3 \).
- Apply the chain rule to swap through the layers.
- Ensure each function and its associated derivative are recognized.