/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Differentiate the functions with... [FREE SOLUTION] | 91Ó°ÊÓ

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Differentiate the functions with respect to the independent variable. \(f(x)=3^{\sqrt{x+1}}\)

Short Answer

Expert verified
The derivative is \( f'(x) = \frac{3^{\sqrt{x+1}} \ln(3)}{2\sqrt{x+1}} \).

Step by step solution

01

Introduce the problem

We are asked to differentiate the function \( f(x) = 3^{\sqrt{x+1}} \) with respect to \( x \). This involves finding the derivative \( f'(x) \).
02

Recognize the form of the function

The function \( f(x) = 3^{\sqrt{x+1}} \) is an exponential function where the base is different from \( e \), and the exponent is a function of \( x \). We'll need to use the chain rule for differentiation.
03

Utilize the chain rule and exponential differentiation

The derivative of \( a^{u(x)} \) with respect to \( x \) is \( a^{u(x)} \cdot \ln(a) \cdot u'(x) \). Here, \( a = 3 \), and \( u(x) = \sqrt{x+1} \). We'll differentiate \( u(x) \) next.
04

Differentiate the inner function \( u(x) = \sqrt{x+1} \)

The function \( u(x) = (x+1)^{1/2} \). Its derivative with respect to \( x \) is \( u'(x) = \frac{1}{2}(x+1)^{-1/2} \cdot 1 = \frac{1}{2\sqrt{x+1}} \).
05

Apply the chain rule to find \( f'(x) \)

Using the derivative formula from Step 3, we find:\[ f'(x) = 3^{\sqrt{x+1}} \cdot \ln(3) \cdot \frac{1}{2\sqrt{x+1}} \]
06

Simplify the expression

Combine the terms to simplify the expression for the derivative:\[ f'(x) = \frac{3^{\sqrt{x+1}} \ln(3)}{2\sqrt{x+1}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental tool in calculus for differentiating composite functions. It's essential because many functions that we encounter aren't basic polynomials or simple mathematical expressions. They involve layers of computation, making direct differentiation quite challenging.

When we speak about the chain rule, picture it as peeling layers off an onion. To differentiate a function within a function, we start by identifying the outer function and then consider the inner function which forms its core. The chain rule asserts that the derivative of a composite function can be found by:
  • Differentiating the outer function, while keeping the inner function unchanged.
  • Multiplying by the derivative of the inner function.
In mathematical terms, if we have a composite function denoted as \( y = f(g(x)) \), its derivative would be \( y' = f'(g(x)) \cdot g'(x) \).

This strategy helps us deal with complex differentiation tasks more easily and accurately.
Exponential Function
Exponential functions are unique because, unlike polynomial functions, they involve a constant raised to the power of a variable. In the expression \( f(x) = a^{u(x)} \), the base \( a \) is constant, and the exponent \( u(x) \) is a function of the variable, \( x \).

Exponential functions grow rapidly and are characterized by their distinctive property where the rate of change of the function is proportional to its current value. This is why mastery over differentiation of these functions is critical for understanding growth patterns in economics, biology, and many other fields.

To find the derivative of an exponential function, we use the formula:
  • For a constant base \( a \), the derivative of \( a^{u(x)} \) is \( a^{u(x)} \cdot \ln(a) \cdot u'(x) \).
Logarithmic differentiation plays a crucial role here, as the natural log \( \ln(a) \) emerges in the differentiation process, accounting for the exponential base not being \( e \).
Derivative
The concept of the derivative is at the heart of calculus, representing the instantaneous rate of change of a function with respect to its variable. Simply put, it's the slope of the function's graph at any given point.

To derive a function means to calculate its derivative, which involves finding how the function value changes as its input changes. It's a powerful tool used to solve physical, biological, and economic problems.
  • To find a derivative, you often utilize differentiation rules such as the chain rule, product rule, and quotient rule.
  • The differentiation of the function often provides insights into its behavior, such as its increasing or decreasing nature and possible local extrema.
In the exercise, taking the derivative of \( f(x) = 3^{\sqrt{x+1}} \), led us to an expression \( f'(x) \), which reveals how \( f(x) \) changes as \( x \) changes. Understanding derivatives thus equips you with the means to tackle various real-world changes analytically.

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Most popular questions from this chapter

Use the quotient rule to show that $$ \frac{d}{d x} \csc x=-\csc x \cot x $$

Use the formula $$f(x) \approx f(a)+f^{\prime}(a)(x-a)$$ to approximate the value of the given function. Then compare your result with the value you get from a calculator. \(\sqrt[3]{124}\)

Find the derivatives of the following functions: $$ f(x)=\sin 2 x+\sin ^{2} x $$

Suppose that a certain plant is grown along a gradient ranging from nitrogen- poor to nitrogen-rich soil. Experimental data show that the average mass per plant grown in a soil with a total nitrogen content of \(1000 \mathrm{mg}\) nitrogen per \(\mathrm{kg}\) of soil is \(2.7 \mathrm{~g}\) and the rate of change of the average mass per plant at this nitrogen level is \(1.05 \times 10^{-3} \mathrm{~g}\) per mg change in total nitrogen per \(\mathrm{kg}\) soil. Use a linear approximation to predict the average mass per plant grown in a soil with a total nitrogen content of \(1100 \mathrm{mg}\) nitrogen per \(\mathrm{kg}\) of soil.

Suppose that the concentration of nitrogen in a lake exhibits periodic behavior. That is, if we denote the concentration of nitrogen at time \(t\) by \(c(t)\), then we assume that $$c(t)=2+\sin \left(\frac{\pi}{2} t\right)$$ (a) Find \(\frac{d c}{d t}\). (b) Use a graphing calculator to graph both \(c(t)\) and \(\frac{d c}{d t}\) in the same coordinate system. (c) By inspecting the graph in (b), answer the following questions: (i) When \(c(t)\) reaches a maximum, what is the value of \(d c / d t ?\) (ii) When \(d c / d t\) is positive, is \(c(t)\) increasing or decreasing? (iii) What can you say about \(c(t)\) when \(d c / d t=0 ?\)

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