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Chapter 4: Problem 25

Differentiate $$ f(x)=a x^{2}-2 a $$ with respect to \(x\). Assume that \(a\) is a constant.

Short Answer

Expert verified
The derivative of \( f(x) = a x^{2} - 2a \) is \( 2ax \).

Step by step solution

01

Identify the Function

The function given is \( f(x) = a x^{2} - 2a \). We need to differentiate this function with respect to \( x \). Remember that \( a \) is a constant.
02

Differentiate Each Term

Differentiate the first term \( a x^{2} \). Use the power rule which states that \( \frac{d}{dx}(x^n) = nx^{n-1} \). Thus, the derivative of \( a x^{2} \) is \( 2ax \).
03

Differentiate the Constant Term

The second term \(-2a\) is a constant with respect to \( x \). The derivative of any constant is 0, so the derivative of \(-2a\) is 0.
04

Combine Derivatives

Combine the results from the previous steps. The derivative of \( f(x) = a x^{2} - 2a \) with respect to \( x \) is \( 2ax + 0 \), which simplifies to \( 2ax \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Power Rule in Differentiation
The power rule is a fundamental technique for finding derivatives. It comes in handy when differentiating terms that involve powers of a variable. In essence, the power rule tells us how to take derivatives of expressions like \(x^n\). It states:
  • \( \frac{d}{dx}(x^n) = nx^{n-1} \)
This means you multiply the power \(n\) by the coefficient of the term and then reduce the power of \(x\) by one.
For example, in the term \(a x^2\), the exponent \(n\) equals 2. Applying the power rule, \(2 \times ax^{2-1} = 2ax\). Here, the variable \(a\) remains because it acts as a coefficient鈥攊t's just there to scale the function.
The Role of Constant Terms in Differentiation
Constant terms are simply numbers that don't change no matter what the variable is. In differentiation, dealing with constants is straightforward. For instance, consider the term \(-2a\) in the function. Since \(a\) is a constant, \(-2a\) behaves as one.
When you differentiate a constant, the result is always zero no matter what the constant is. This is because constants have no rate of change with respect to the variable we are differentiating. Hence, in this function, the derivative of the constant term \(-2a\) becomes 0.
So, no matter how complex the rest of your function gets, you can always rely on this rule to simplify the process at any stage of differentiation.
Derivative Computation Simplified
Once you understand how to differentiate terms using the power rule and recognize constant terms, putting it all together to compute a derivative becomes a task of follow-through.
Here鈥檚 a recap with our function \(f(x) = ax^2 - 2a\):
  • First, apply the power rule to \(ax^2\), resulting in \(2ax\).
  • Next, recognize \(-2a\) as a constant term, resulting in a derivative of 0.
  • Combine these results to find the overall derivative, \(2ax + 0\).

This simplifies to the neatly compact form of \(2ax\). By taking each part of a function, applying the right rule, and combining the results, you can simplify even the most complex-looking problems into manageable steps.

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Most popular questions from this chapter

Calculate the linear approximation for \(f(x)\) : $$f(x) \approx f(a)+f^{\prime}(a)(x-a)$$ \(f(x)=\log \left(1+x^{2}\right)\) at \(a=0\)

Find the derivative at the indicated point from the graph of \(y=f(x)\). \(f(x)=-5 x+1 ; x=0\)

The following limit represents the derivative of a function \(f\) at the point \((a, f(a))\) : $$\lim _{h \rightarrow 0} \frac{\sin \left(\frac{\pi}{6}+h\right)-\sin \frac{\pi}{6}}{h}$$ Find \(f\) and \(a\).

Find the derivatives of the following functions: $$ f(x)=\sin 2 x+\sin ^{2} x $$

A measurement error in \(x\) affects the accuracy of the value \(f(x) .\) In each case, determine an interval of the form $$[f(x)-\Delta f, f(x)+\Delta f]$$ that reflects the measurement error \(\Delta x .\) In each problem, the quantities given are \(f(x)\) and \(x=\) true value of \(x \pm|\Delta x| .\) \(f(x)=1-3 x, x=-2 \pm 0.3\)
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