/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 In Problems 29-48, find the limi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems 29-48, find the limits. $$ \lim _{x \rightarrow 1} \frac{1}{\sqrt{3-2 x^{2}}} $$

Short Answer

Expert verified
The limit is 1.

Step by step solution

01

Analyze the Function

The function given is \( f(x) = \frac{1}{\sqrt{3-2x^2}} \). We need to find \( \lim_{x \to 1} f(x) \). First, check if the function is defined at \( x = 1 \). Substitute \( x = 1 \) into the expression inside the square root: \( 3-2(1)^2 = 3-2 = 1 \). Since the square root of 1 is defined, \( f(x) \) is defined at \( x=1 \).
02

Substitute the Limit Point

Now substitute \( x = 1 \) into the function to find the limit: \[ \lim_{x \to 1} \frac{1}{\sqrt{3-2x^2}} = \frac{1}{\sqrt{3-2(1)^2}} = \frac{1}{\sqrt{1}}. \]
03

Simplify the Expression

Simplify the expression found in Step 2. \( \sqrt{1} = 1 \), so the expression becomes \( \frac{1}{1} = 1 \).
04

Finalize the Limit

Conclude that the limit of \( f(x) \) as \( x \) approaches 1 is 1. Therefore, \( \lim_{x \to 1} \frac{1}{\sqrt{3-2x^2}} = 1 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Evaluation
Evaluating a limit helps us understand the behavior of a function as it approaches a particular point. In this exercise, we calculate the limit \( \lim_{x \to 1} \frac{1}{\sqrt{3-2x^2}} \). Often, the first step in limit evaluation is to analyze if the function is defined at the limit point.
For our case, we substitute \( x = 1 \) into the expression under the square root: \( 3-2(1)^2 = 1 \). The square root is defined here (since \( \sqrt{1} = 1 \)), allowing us to proceed.
Once we determine the function is defined, we substitute \( x = 1 \) into the entire function:
  • Evaluate: \( \frac{1}{\sqrt{3-2(1)^2}} = \frac{1}{1} \)

  • Simplify: \( \frac{1}{1} = 1 \)

This process confirms that the limit exists and equals 1, showcasing the simplicity and beauty behind evaluating limits.
Square Roots
The square root function appears in many mathematical contexts and is crucial to understanding this problem. When dealing with square roots, especially within limits, it's essential to ensure the expression under the root is non-negative, as square roots of negative numbers are not defined in the real number system.
In our exercise, the expression within the square root is \( 3-2x^2 \). At \( x=1 \), this simplifies to \( 1 \), confirming that the square root is valid since it's a non-negative number. If at any point, this expression becomes less than zero, the function would be undefined, which would significantly alter our approach to finding the limit.
Always remember that understanding how a function behaves is vital. In cases where the expression under the root approaches zero, the limit might involve more nuanced mathematical techniques. However, for our function, the square root simplifies directly to an integer at \( x=1 \), making the process straightforward.
Function Analysis
Analyzing a function involves understanding its components and behavior as various inputs approach certain values. Here, we look at the rational function \( f(x) = \frac{1}{\sqrt{3-2x^2}} \). To perform a comprehensive function analysis, consider:
  • The domain: Ensure all values under the square root are non-negative (i.e., solve \( 3-2x^2 \geq 0 \)).
  • Continuity: Check if the function behaves smoothly at and around the point of interest, \( x=1 \).

  • Asymptotic behavior: Observe if the function approaches a finite value (e.g., \( \frac{1}{1} = 1 \) near \( x=1 \)).

Through function analysis, we verify that our approach for evaluating the limit is appropriate. We identify the behavior and continuity at critical points. Understanding these principles assists in predicting behaviors and solving such problems accurately in calculus.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the values of \(x\) such that $$ \left|x^{2}-9\right|<0.1 $$

For each of the following equations show that the equation has a \mathrm{\\{} \text { root in the given interval. Then use the bisection search method, } implemented as a spreadsheet, to find this root to an accuracy of \(10^{-5}\). \(x^{3}-2 x+1=0 \quad(-2,-1)\)

(a) Show that $$ f(x)=\sqrt{x-1}, \quad x \geq 1 $$ is continuous from the right at \(x=1\). (b) Graph \(f(x)\). (c) Does it make sense to look at continuity from the left at \(x=1 ?\)

Panting in Animals Animals use different strategies to control their internal temperature depending on how hot they are. When the core temperature of a dog, duck, or cat exceeds a critical value, it will start to pant (make quick, gasping breaths that increase evaporation of water from the tongue and mouth). Vieth (1989) studied heat loss as a function of the ducks' core temperature, \(T\). She found that different functions described heat loss below the temperature at which the ducks started to pant and above this temperature. If \(H(T)\) is the rate of heat loss: $$ H(T)=\left\\{\begin{array}{ll} 0.6 & \text { if } T \leq T_{c} \\ 4.3 T-183 & \text { if } T>T_{c} \end{array}\right. $$ (here \(T\) is measured in \({ }^{\circ} \mathrm{C}\) and \(H(T)\) in watts per \(\mathrm{kg}\) of body mass \()\) (a) Calculate the value of \(T_{c}\) that makes \(H(T)\) continuous for all \(T\). (b) Draw the graph of the function \(H(T)\) over the normal body temperature range for ducks: \(41^{\circ} \mathrm{C} \leq T \leq 44^{\circ} \mathrm{C}\).

In Problems 29-48, find the limits. $$ \lim _{x \rightarrow 0} \frac{5-\sqrt{25+x^{2}}}{2 x^{2}} $$

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.