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In Problems 39-56, use the limit laws to evaluate each limit. $$ \lim _{x \rightarrow-5}\left(4+2 x^{2}\right) $$

Short Answer

Expert verified
The limit is 54.

Step by step solution

01

Understand the expression

The expression to evaluate the limit of is \(4 + 2x^2\) as \(x\) approaches \(-5\). Here, \(4\) is a constant, and \(2x^2\) is a polynomial. We will use the limit laws to evaluate the limit of this entire expression.
02

Apply the Direct Substitution Property

According to the limit laws, if a function \(f(x)\) is a polynomial, the limit as \(x\) approaches a value \(c\) is simply \(f(c)\). Since \(4 + 2x^2\) is a polynomial, we can directly substitute \(x = -5\) into the expression.
03

Substitute \(x = -5\)

Substitute \(x = -5\) into the expression: \[4 + 2(-5)^2\]. Calculate the square of \(-5\) which is 25, and then multiply by 2.
04

Calculate the value of the expression

Calculate \(2(-5)^2 = 2 imes 25 = 50\). Now add the constant 4 to get the limit value: \(4 + 50 = 54\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Limit Laws
Limit laws are fundamental principles in calculus that help simplify and evaluate limits. They provide a set of rules to break down complex expressions into manageable pieces, making it easier to find limits.
The most common limit laws include the sum, difference, product, and quotient laws:
  • The sum law states that if you have a limit of the sum of two functions, it can be separated into the sum of their limits.
  • The difference law allows you to find the limit of the difference of two functions by calculating the difference of their individual limits.
  • The product and quotient laws work similarly, dealing with multiplication and division of functions, respectively.
In the example given, we applied these laws implicitly to solve for the limit. By identifying the structure as a polynomial, we can directly apply the Direct Substitution Property without further breaking down the terms. These laws are crucial for efficiently evaluating limits in various forms.
The Direct Substitution Property
The direct substitution property is a powerful tool for evaluating limits, especially when dealing with polynomials. This property tells us that if a function is continuous at a point and does not have any ill-behaved features like holes or vertical asymptotes, you can find the limit by simply substituting the value of the limit into the function.
For polynomials, which are continuous everywhere in their domain, this property is particularly useful. It allows us to bypass more complex methods and substitute directly.
For example, in the expression \(4 + 2x^2\) as \(x\) approaches \(-5\), the direct substitution method says we can substitute \(x = -5\) directly, given that our expression is a simple polynomial. Thus, \(4 + 2(-5)^2\) becomes straightforward to compute.
This property makes calculating limits of polynomials easy and fast, requiring minimal computation.
Characteristics of Polynomials
Polynomials are a class of mathematical expressions consisting of variables and coefficients, constructed using only addition, subtraction, multiplication, and non-negative integer exponents of variables. They are some of the simplest and most versatile functions in mathematics due to their unique properties.
Polynomials can take many forms, from simple constants like 4 to more complex expressions like \(2x^2\). They are continuous everywhere over the real numbers, meaning their graphs have no breaks, jumps, or holes. This continuity is what makes the direct substitution property applicable.
When working with limits, any polynomial function can have its limit calculated as \(x\) approaches any real number by simply substituting that number for \(x\). This is much easier compared to functions that may not be defined at certain points or have asymptotic behavior.
Understanding these characteristics helps us recognize when we can apply certain calculus rules efficiently, as was done in evaluating the limit \(\lim _{x \rightarrow-5}\left(4+2 x^{2}\right)\), giving us a clear path to a solution.

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Most popular questions from this chapter

Fungal Growth As a fungus grows, its rate of growth changes. Young fungi grow exponentially, while in larger fungi growth slows, and the total dimensions of the fungus increase as a linear function of time. You want to build a mathematical model that describes the two phases of growth. Specifically if \(R(t)\) is the rate of growth given as a function of time, \(t\), then you model $$ R(t)=\left\\{\begin{array}{ll} 2 e^{t} & \text { if } 0 \leq t \leq t_{c} \\ a & \text { if } t>t_{c} \end{array}\right. $$ where \(t_{c}\) is the time at which the fungus switches from exponential to linear growth and \(a\) is a constant. (a) For what value of \(a\) is the function \(R(t)\) continuous at \(t=t_{c}\) ? (Your answer will include the unknown constant \(t_{c}\) ). (b) Assume that \(t_{c}=2 .\) Draw the graph of \(R(t)\) as a function of \(t\)

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