/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 In Problems , find the populatio... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems , find the population sizes for \(t=0,1\), 2, \(\ldots, 5\) for each recursion. Then write the equation for \(N_{t}\) as a function of \(t\). $$ N_{t+1}=\frac{1}{3} N_{t} \text { with } N_{0}=2430 $$

Short Answer

Expert verified
\( N_{t} = 2430 \times (\frac{1}{3})^{t} \), with \( N_{0} = 2430, N_{1} = 810, N_{2} = 270, N_{3} = 90, N_{4} = 30, N_{5} = 10 \).

Step by step solution

01

Understanding the Problem

We need to find the size of the population at several time intervals using a given recursive formula. The recursion provided is \( N_{t+1} = \frac{1}{3} N_{t} \) and we know that the initial population size \( N_{0} = 2430 \).
02

Calculate \( N_{1} \)

Substitute \( N_{0} \) into the recursive formula. This gives \( N_{1} = \frac{1}{3} \times 2430 = 810 \).
03

Calculate \( N_{2} \)

Use the value of \( N_{1} \) to find \( N_{2} \). \( N_{2} = \frac{1}{3} \times 810 = 270 \).
04

Calculate \( N_{3} \)

Apply the recursion again using \( N_{2} \). \( N_{3} = \frac{1}{3} \times 270 = 90 \).
05

Calculate \( N_{4} \)

Use \( N_{3} \) for the next calculation. \( N_{4} = \frac{1}{3} \times 90 = 30 \).
06

Calculate \( N_{5} \)

Finally, use \( N_{4} \) to determine \( N_{5} \). \( N_{5} = \frac{1}{3} \times 30 = 10 \).
07

Write \( N_{t} \) as a Function of \( t \)

From the recursion, we infer that \( N_{t} \) is reduced by a factor of \( \frac{1}{3} \) for each increase of 1 in \( t \). Thus, \( N_{t} = 2430 \times \left( \frac{1}{3} \right)^{t} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Growth Modeling
Population growth modeling helps us understand how a population changes over time. In our particular problem, we have a unique twist because instead of growth, we are observing a decrease in population. This might represent a scenario where resources are diminishing, leading to a reduced population size each year.

The model we're using is one of exponential decay for its simplicity and applicability to many real-world problems. The recursive formula shows that the population decreases to one-third of its previous size each year. Such a model could be useful in predicting population size in contexts like bacterial culture decline due to antibiotics. In natural populations, similar models can help in understanding the effects of habitat changes or overpopulation correction.

To accurately predict future population sizes, we start by setting an initial population value, then apply our recursive rule repeatedly. The choice of model and parameters depends on empirical data and theoretical considerations relevant to the specific study.
Difference Equations
A difference equation is a mathematical formula used to express recursive relations and analyze sequences that evolve over time. In our problem, we used the difference equation \( N_{t+1} = \frac{1}{3}N_{t} \), where \( N_{t} \) denotes the population at time \( t \). This type of equation is particularly powerful because it describes how the population transitions from one time period to the next.

These equations are similar to differential equations but are used in contexts where changes occur at discrete time intervals (e.g., yearly, monthly). To solve a difference equation, we typically start with an initial condition, like \( N_{0} = 2430 \), and apply the recursive formula iteratively:
  • Calculate \( N_{1} \) using \( N_{0} \).
  • Use \( N_{1} \) to find \( N_{2} \).
  • Continue this calculation up to the desired \( N_{t} \).
The general solution for \( N_{t} \) is expressed in terms of \( t \), which can easily be derived from the recursive process. For our problem, the expression becomes \( N_{t} = 2430 \times \left( \frac{1}{3} \right)^{t} \). This formula gives us a direct way to compute the population at any time \( t \).
Discrete Mathematics
Discrete mathematics deals with structures that are fundamentally discrete rather than continuous. It encompasses topics such as graph theory, logic, set theory, and of course, sequences and series. In our case, the study of recursive sequences through difference equations fits right into this domain.

When working with recursive sequences, the focus is often on how these sequences evolve step by step, observing changes at each discrete stage. The recursive sequence in our population model is characterized by discrete time steps (years, in this example). At each step, the population size is calculated independently, based on its previous value and the rule \( N_{t+1} = \frac{1}{3}N_{t} \).

Understanding discrete mathematics is crucial for modeling real-world processes that occur in distinct steps, such as economic evaluations, computer algorithms, or resource allocation tasks. It provides the foundation for designing calculations and solutions that require precision when steps cannot blend but instead stay distinctly measurable, as shown in population studies with recursive sequences.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Because of complex interactions with other drugs, some drugs have zeroth order elimination kinetics in some circumstances, and first order kinetics in other circumstances, depending on what other drugs are in the patient's system, as well as on age and preexisting medical conditions. Use the data on how concentration varies with time to determine whether the drug has zeroth or first order kinetics. Given the following sequence of measurements for drug concentration, determine whether the drug has zeroth or first order kinetics. $$ \begin{array}{lcccc} \hline \boldsymbol{t} \text { (Hours) } & 0 & 2 & 4 & 6 \\ \hline \boldsymbol{c}_{t}(\mathbf{m g} / \mathbf{m l}) & 40 & 36 & 32.4 & 29.16 \\ \hline \end{array} $$

Investigate the advantage of dimensionless variables. You are studying a population that obeys the discrete logistic equation. You know that \(b=\frac{1}{10} .\) One year you measure \(N_{t}=15\). The next year you measure that \(N_{t+1}=20\). What value of \(R_{0}\) is needed in the model to fit these data?

In Problems 79-90, use the limit laws to determine \(\lim _{n \rightarrow \infty} a_{n}=a .\) $$ \lim _{n \rightarrow \infty}\left(\frac{1}{n}+\frac{2}{n^{2}}\right) $$

A drug has first order elimination kinetics. At time \(t=0\) an amount \(a_{0}=20 \mathrm{mg}\) is present in the blood. One hour later, at \(t=1\), an amount \(a_{1}=14 \mathrm{mg}\) is present. (a) Assuming that no drug is added to the blood between \(t=0\) and \(t=1\), calculate the percentage of drug that is removed each hour. (b) Write a recursion relation for the amount of drug \(a_{t}\) present at time \(t\). Assume no extra drug. (c) Find an explicit formula for \(a_{t}\) as a function of \(t\). (d) Will the amount of drug present ever drop to 0 according to vour model?

The sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=2 a_{n}^{2}, a_{0}=1 $$

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.