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Assume that the discrete logistic equation is used with parameters \(R_{8}\) and \(b .\) Write the equation in the dimensionless form \(x_{t+1}=R_{0} x_{t}\left(1-x_{t}\right)\), and determine \(x_{t}\) in terms of \(\bar{N}_{t}\) \(R_{0}=2, b=\frac{1}{20}\)

Short Answer

Expert verified
The dimensionless form is already \(x_{t+1}=2x_{t}(1-x_{t})\), with \(x_t = \frac{\bar{N}_t}{K}\) given by simplification.

Step by step solution

01

Express the Original Equation

The discrete logistic equation in dimensional form is given by \( \bar{N}_{t+1} = \bar{N}_t + R_0 \bar{N}_t \left( 1 - \frac{\bar{N}_t}{K} \right) - b \bar{N}_t \). However, for simplicity, if we're converting to dimensionless form and the equation given in the task starts as \( x_{t+1}=R_{0} x_{t}(1-x_{t}) \), we interpret it directly with these parameters, focusing on given \(R_0\) and finding the relationship to \(x_t\), using provided parameters.
02

Dimensionless Substitution

To express the system in terms of a dimensionless parameter \(x_t\), let \(x_t = \frac{\bar{N}_t}{K}\) where \(K\) is the carrying capacity. Given the equation, the dimensionless form is \(x_{t+1} = R_{0} x_{t} (1 - x_{t})\), implying replacement in terms of \(\bar{N}_t\). The dimensionless equation can be rewritten as \(x_{t+1} = 2x_{t}(1-x_{t})\) with \(R_0 = 2\).
03

Determine \(x_t\) in Terms of \(\bar{N}_t\)

Given the parametrization \(x_t = \frac{\bar{N}_t}{K}\) and transforming the logistic equation in dimensionless form, you compare both forms, knowing \(R_0\) relates directly with absence of additional parameters (used already), and express where simplification leads. Here, this simple relationship already results in \(x_t = 1\) at carrying capacity, as given equation does.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dimensionless Form
The concept of the "Dimensionless Form" within mathematical models, such as the discrete logistic equation, aims to simplify equations by removing units and scales. In this approach, variables and parameters of the original equation are recalculated in a way that their units cancel out, leaving a simplified form that is easier to analyze. This typically involves normalizing variables by dividing them with a characteristic scale or carrying capacity.

For instance, in the logistic growth equation, the population variable \(\bar{N}_t\) is replaced with \(x_t\) by normalizing it with the carrying capacity, \(K\). Thus, \(x_t = \frac{\bar{N}_t}{K}\). This substitution transforms the original population equation into a dimensionless form:

\[x_{t+1} = R_0 x_t (1 - x_t)\]

This simplifies the equation and helps in identifying universal behaviors or patterns across different systems without dealing with their specific sizes or units. It's a common practice in mathematics and science to aid in the understanding and comparison of dynamics across different contexts.
Carrying Capacity
The term "Carrying Capacity" is pivotal within the logistic growth model. It represents the maximum population size (\(K\)) that an environment can sustain indefinitely, given the available resources like food, habitat, and water. The carrying capacity acts as a ceiling in the logistic equation, beyond which the population cannot grow.

Within the logistic model, as the population nears carrying capacity, growth rate decreases, stabilizing the population size. This is captured mathematically in the equation structure:

- As \(\bar{N}_t \rightarrow K\), \(\frac{\bar{N}_t}{K} \rightarrow 1\), which means the growth essentially halts as the term \(1 - \frac{\bar{N}_t}{K}\) tends to zero.

The logistic model assumes that the environment can support only a specific number of individuals. Hence, growth is initially exponential but eventually flattens out when approaching the carrying capacity.
Logistic Growth Model
The "Logistic Growth Model" is a fundamental concept in understanding population dynamics and its limits. Originally proposed by Pierre-François Verhulst, this model is widely used to describe populations that rapidly grow when numbers are low and slow down as they approach a limit imposed by environmental factors.

Initially, the model reflects exponential growth, capturing how populations can increase rapidly when resources are plentiful. The equation for a basic logistic growth model is:

- \(\bar{N}_{t+1} = \bar{N}_t + R_0 \bar{N}_t (1 - \frac{\bar{N}_t}{K})\)

In simple terms, till the population remains under the carrying capacity, it experiences growth proportional to its size. But unlike perpetual exponential growth, the logistic model incorporates a slowdown as populations near this ceiling. The rate of growth depends on various factors summed as the intrinsic growth rate \(R_0\).

Logistic growth is more realistic than exponential growth for most real-world situations where resource limitations are a critical factor.

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Most popular questions from this chapter

Mountain Gorilla Conservation You are trying to build a mathematical model for the size of the population of mountain gorillas in a national park in Uganda. The data in this question are taken from Robbins et al. (2009). (a) You start by writing a word equation relating the population of gorillas \(t\) years after the study begins, \(N_{t}\), to the population \(N_{t+1}\) in the next year: \(N_{t+1}=N_{t}+\begin{array}{l}\text { number of gorillas } \\ \text { born in one year }\end{array}-\begin{array}{l}\text { number of gorillas } \\\ \text { that die in one yeai }\end{array}\) We will derive together formulas for the number of births and the number of deaths. (i) Around half of gorillas are female, \(75 \%\) of females are of reproductive age, and in a given year \(22 \%\) of the females of reproductive age will give birth. Explain why the number of births is equal to: \(\quad 0.5 \cdot 0.75 \cdot 0.22 \cdot N_{t}=0.0825 \cdot N_{t}\) (ii) In a given year \(4.5 \%\) of gorillas will die. Write down a formula for the number of deaths. (iii) Write down a recurrence equation for the number of gorillas in the national park. Assuming that there are 300 gorillas initially (that is \(N_{0}=300\) ), derive an explicit formula for the number of gorillas after \(t\) years. (iv) Calculate the population size after \(1,2,5\), and 10 years. (v) According to the model, how long will it take for population size to double to 600 gorillas? (b) In reality the population size is almost totally stagnant (i.e., \(N_{t}\) changes very little from year to year). Robbins et al. (2009) consider three different explanations for this effect: (i) Increased mortality: Gorillas are dying sooner than was thought. What percentage of gorillas would have to die each year for the population size to not change from year to year? (ii) Decreased female fecundity: Gorillas are having fewer offspring than was thought. Calculate the female birth rate (percentage of reproductive age females that give birth) that would lead to the population size not changing from year to year. Assume that all other values used in part (a) are correct. (iii) Emigration: Gorillas are leaving the national park. What number of gorillas would have to leave the national park each year for the population to not change from year to year?

Assume that the population growth is described by the Beverton-Holt model. Find all fixed points. \(N_{t+1}=\frac{3 N_{t}}{1+N_{t} / 30}\)

Assume that the population growth is described by the Beverton-Holt model. Find all fixed points. \(N_{t+1}=\frac{3 N_{t}}{1+N_{t} / 100}\)

Assume that \(\lim _{n \rightarrow \infty} a_{n}\) exists. Find all fixed points of \(\left\\{a_{n}\right\\}\), and use a table or other reasoning to guess which fixed point is the limiting value for the given initial condition. $$ a_{n+1}=2 a_{n}\left(1-a_{n}\right), a_{0}=0.1 $$

Investigate the behavior of the discrete logistic equation $$ x_{t+1}=R_{0} x_{t}\left(1-x_{t}\right) $$ Compute \(x_{t}\) for \(t=0,1,2, \ldots, 20\) for the given values of \(r\) and \(x_{0}\), and graph \(x_{t}\) as a function of \(t .\) \(R_{0}=2, x_{0}=0\)

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