/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 102 The sequence \(\left\\{a_{n} \mi... [FREE SOLUTION] | 91Ó°ÊÓ

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The sequence \(\left\\{a_{n} \mid\right.\) is recursively defined. Find all fixed points of \(\left[a_{n}\right\\} .\) $$ a_{n+1}=\frac{1}{3} a_{n}+\frac{4}{3} $$

Short Answer

Expert verified
The fixed point of the sequence is \(a_f = 2\).

Step by step solution

01

Understanding Fixed Points

Fixed points of a sequence are values such that if you input the value into the sequence formula, the output will be the same as the input. In mathematical terms, for the sequence defined by the recursion \(a_{n+1} = \frac{1}{3}a_n + \frac{4}{3}\), a fixed point is a value \(a_f\) which satisfies \(a_f = \frac{1}{3}a_f + \frac{4}{3}\).
02

Set Up the Fixed Point Equation

For the given recursive formula \(a_{n+1} = \frac{1}{3}a_n + \frac{4}{3}\), set \(a_{n+1} = a_n = a_f\). This gives us the equation: \[ a_f = \frac{1}{3}a_f + \frac{4}{3} \]
03

Solve for the Fixed Point

To solve the equation from Step 2, start by eliminating the fraction: - Multiply all terms by 3: \[ 3a_f = a_f + 4 \]- Simplify by subtracting \(a_f\) from both sides: \[ 2a_f = 4 \]- Divide each side by 2 to solve for \(a_f\): \[ a_f = 2 \]
04

Verify the Fixed Point Solution

Substitute \(a_f = 2\) back into the original equation to ensure it satisfies the recursion: \[ a_{n+1} = \frac{1}{3}(2) + \frac{4}{3} = \frac{2}{3} + \frac{4}{3} = \frac{6}{3} = 2 \]This confirms that \(a_f = 2\) is indeed a fixed point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fixed Points
A fixed point in a sequence is truly a fascinating concept. Think of it as a number that when plugged into a sequence formula, doesn't change. It's like pushing the same value into a calculator and always getting the same result back. In mathematical terms, if you have a recursive sequence defined by a formula like \(a_{n+1} = \frac{1}{3}a_n + \frac{4}{3}\), a fixed point, \(a_f\), satisfies the condition \(a_f = F(a_f)\). This means that when \(a_f\) is used in the formula, the output remains \(a_f\) itself. Fixed points are important because they can reveal stability in sequences or systems. They're like calm spots in a stormy sea. **To find fixed points**:
  • Set the sequence equation so that the next term equals the current term, \(a_{n+1} = a_n\).
  • Solve this equation for the fixed value, \(a_f\).
  • Verify by substituting back to ensure the input and output remain equal.
In the case of the exercise above, when solving \(a_f = \frac{1}{3}a_f + \frac{4}{3}\), we find our fixed point at \(a = 2\). This means 2 stays the same, calmly flowing through the sequence formula without a change.
Sequence Formula
The sequence formula serves as the engine dictating how a sequence progresses. It's like a set of instructions where each term in the series is determined based on certain rules. In the provided recursive sequence, the formula is \(a_{n+1} = \frac{1}{3}a_n + \frac{4}{3}\). Each term, \(a_{n+1}\), is derived by taking the previous term, \(a_n\), multiplying it by \(\frac{1}{3}\), then adding \(\frac{4}{3}\). You can envision these actions like programmed steps that guide the sequence’s evolution.**Why is this formula crucial?**
  • The sequence formula provides the pattern or rule that defines the series.
  • It's the mathematical model describing the behavior of sequence over time.
  • Understanding this rule gives insight into how values transform and helps predict future terms.
Think of it as the GPS for a road trip, telling you exactly where the sequence goes next by indicating the path laid out from any starting point.
Mathematical Recursion
Mathematical recursion is a process where a sequence or calculation is defined in terms of itself. Essentially, it's a way to "revisit" previous stages to determine future outcomes. In our sequence \(a_{n+1} = \frac{1}{3}a_n + \frac{4}{3}\), recursion means that each term builds directly on the one before it. **How does recursion work in sequences?**
  • In recursion, the current term relies on previous terms—a dependency chain.
  • Each step forward in the sequence leans on recalculating using the recursive formula.
  • It's both a repetition and an evolution, taking past values to inform future ones.
Recursive sequences like this can easily model complex systems or patterns arising naturally in various domains. By understanding recursion, you unveil how a component of a system relates to its prior ones, forming a bridge to future behavior. Such insights are fundamental in mathematics and computer science, where recursion forms a key concept in designing algorithms that mimic real-world processes.

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Most popular questions from this chapter

Assume that the population growth is described by the Beverton-Holt recruitment curve with parameters \(R_{0}\) and a. Find the population sizes for \(t=1,2, \ldots, 5\) and find \(\lim _{t \rightarrow \infty} N_{t}\) for the given initial value \(N_{0} .\) \(R_{0}=3, a=1 / 10, N_{0}=3\)

Write each sum in expanded form. $$ \sum_{k=2}^{6} 3^{k} $$

Model painkillers that are absorbed into the blood from a slow release pill. Ourmathematical model for the amount, \(a_{t}\), of drug in the blood t hours after the pill is taken must include the amount absorbed from the pill each hour. Our model starts with the word equation. $$ \begin{array}{c} a_{t+1}=a_{t}+\begin{array}{l} \text { amount absorbed } \\ \text { from the pill } \end{array}-\begin{array}{l} \text { amount eliminated } \\ \text { from the blood } \end{array} \end{array} $$ Assume the amount absorbed from the pill between time \(t\) and time \(t+1\) is \(10 \cdot(0.4)^{t}\). (a) The drug has first order elimination kinetics. \(10 \%\) of the drug is eliminated from the blood each hour. Write down the recursion relation for \(a_{t+1}\) in terms of \(a_{t}\) (b) Assuming that \(a_{0}=0\), meaning that no drug is present in the blood initially, calculate the amount of drug present at times \(t=1,2, \ldots, 6\) (c) What is the maximum amount of drug present at any time in this interval? At what time is this maximum amount reached? (d) Use a spreadsheet to calculate the amount of drug present in hourly intervals from \(t=0\) up to \(t=24\). (e) Show when \(t\) is large, the amount of drug present in the blood decreases approximately exponentially with \(t .\) Hint: Plot the values that you computed for \(a_{t}\) against \(t\) on semilogarithmic axes.

Assume that the population growth is described by the Beverton-Holt recruitment curve with parameters \(R_{0}\) and a. Find the population sizes for \(t=1,2, \ldots, 5\) and find \(\lim _{t \rightarrow \infty} N_{t}\) for the given initial value \(N_{0} .\) \(R_{0}=4, a=1 / 40, N_{0}=2\)

In Problems 91-100, the sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=2 a_{n}, a_{0}=1 $$

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