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Roll two fair dice, one after the other, and find the probability that the first number is larger than the second number.

Short Answer

Expert verified
The probability is \( \frac{5}{12} \).

Step by step solution

01

Identify Total Outcomes

When rolling two dice, each die has 6 sides. The total number of possible outcomes is calculated by multiplying the possibilities for each die: \[ 6 \times 6 = 36 \]Thus, there are 36 total outcomes.
02

List Favorable Outcomes

For each face of the first die, list the faces of the second die that are smaller: - If the first die shows a 2, there is 1 possibility for the second die (1). - If the first die shows a 3, there are 2 possibilities for the second die (2, 1). - If the first die shows a 4, there are 3 possibilities for the second die (3, 2, 1). - If the first die shows a 5, there are 4 possibilities for the second die (4, 3, 2, 1). - If the first die shows a 6, there are 5 possibilities for the second die (5, 4, 3, 2, 1).
03

Calculate Total Favorable Outcomes

Add up the number of possible outcomes for all cases:\[ 1 + 2 + 3 + 4 + 5 = 15 \]There are 15 outcomes where the first number is larger than the second.
04

Calculate the Probability

The probability is calculated by dividing the number of favorable outcomes by the total number of outcomes:\[ \frac{15}{36} \]Simplify the fraction by dividing the numerator and the denominator by their greatest common divisor, which is 3:\[ \frac{15 \div 3}{36 \div 3} = \frac{5}{12} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dice Outcomes
In probability, the term 'dice outcomes' refers to the possible results when rolling a die. When dealing with two dice, each die has six faces, numbered from 1 to 6. This results in a total of 6 outcomes for each individual die.

When rolling two dice, the outcome set is greatly expanded. To find the total possible outcomes when rolling two dice, we multiply the number of outcomes for the first die by the number of outcomes for the second die. Therefore, the total number of outcomes when rolling two dice is calculated as follows:
  • 6 outcomes for the first die
  • 6 outcomes for the second die
Thus, the total number of possible outcomes is \(6 \times 6 = 36 \).

This means there are 36 different combinations of results when rolling two dice. Understanding these outcomes is crucial in determining the probability of various scenarios when playing games that involve dice.
Favorable Outcomes
When seeking to calculate probability, identifying which outcomes are considered 'favorable' is key. Favorable outcomes are those that meet the criteria or event you are interested in, such as achieving a higher roll on the first die compared to the second.

For this problem, we need to find out when the number on the first die is greater than the number on the second die. Let's consider each face of the first die:
  • For a 2 on the first die, only a roll of 1 on the second die is favorable.
  • For a 3 on the first die, favorable rolls on the second die are 1 and 2.
  • For a 4 on the first die, the second die can be 1, 2, or 3.
  • For a 5 on the first die, the second die can be 1, 2, 3, or 4.
  • For a 6 on the first die, all rolls (1 to 5) on the second die are favorable.
By summing these favorable outcomes, we find a total of \(1 + 2 + 3 + 4 + 5 = 15 \) favorable cases where the first number is larger than the second. Identifying favorable outcomes helps in determining the likelihood of winning in a dice game.
Probability Calculation
Calculating the probability of an event involves dividing the number of favorable outcomes by the total number of possible outcomes. This provides a numerical value that represents the likelihood of the event occurring.

The formula for probability is:\[\text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \]In our case, we've identified that there are 15 favorable outcomes and 36 possible outcomes. So, the probability that the number on the first die is larger than the second is:\[\frac{15}{36} \]This fraction can be simplified by dividing both the numerator and the denominator by their greatest common divisor:
  • 15 and 36 both divide evenly by 3.
Thus, the simplified probability is:\[\frac{15 \div 3}{36 \div 3} = \frac{5}{12} \]

This means that in any game where two dice are rolled, you have a 5 out of 12 chance that the number on the first die will be larger than the number on the second. Probability calculations help predict outcomes in games and real-world scenarios, making them an essential part of mathematics.

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