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Transform the second-order differential equation $$ \frac{d^{2} x}{d t^{2}}-2 \frac{d x}{d t}=\frac{x}{2} $$ into a system of first-order differential equations.

Short Answer

Expert verified
The system is: \( \frac{dx}{dt} = v \) and \( \frac{dv}{dt} = \frac{x}{2} + 2v \).

Step by step solution

01

Identify the original second-order differential equation

Given the original second-order differential equation: \( \frac{d^{2} x}{d t^{2}} - 2 \frac{d x}{d t} = \frac{x}{2} \). It involves the second derivative of \( x \) with respect to \( t \). To transform it into a system of first-order equations, we need to define new variables.
02

Define new variables

Let \( v(t) = \frac{dx}{dt} \) represent the first derivative of \( x \) with respect to \( t \). This substitution reduces the second-order differential equation to a system involving \( v(t) \). So, we now have two variables: \( x(t) \) and \( v(t) = \frac{dx}{dt} \).
03

Express second derivative using new variables

The second derivative \( \frac{d^{2} x}{d t^{2}} \) can now be expressed in terms of the derivative of \( v(t) \): \( \frac{d^{2} x}{d t^{2}} = \frac{d}{dt} \left( \frac{dx}{dt} \right) = \frac{dv}{dt} \).
04

Create a system of first-order differential equations

Substitute \( v(t) = \frac{dx}{dt} \) and \( \frac{d^{2} x}{d t^{2}} = \frac{dv}{dt} \) into the original equation:\( \frac{dv}{dt} - 2v = \frac{x}{2} \).Now we have the system of first-order differential equations:1. \( \frac{dx}{dt} = v \)2. \( \frac{dv}{dt} = \frac{x}{2} + 2v \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Second-Order Differential Equations
Differential equations are mathematical expressions that relate a function with its derivatives. A second-order differential equation specifically involves the second derivative.\\
A typical form of a second-order differential equation is \( \frac{d^2x}{dt^2} + a\frac{dx}{dt} + bx = f(t) \), where \( a \) and \( b \) are constants, and \( f(t) \) is a function of \( t \). The presence of \( \frac{d^2x}{dt^2} \) is what makes it second-order.\\
Second-order differential equations are widely used in physics, engineering, and other sciences to model real-world behaviors. They are essential in situations where acceleration (the second derivative of position) must be considered, like in mechanics or wave propagation.\
    \
  • For example, the motion of a pendulum can imply a second-order differential equation, integrating variables of acceleration and velocity.
  • \
  • Other practical examples include electronic circuits and spring-mass-damper systems.
  • \
"},{"concept_headline":"Exploring Systems of Equations","text":"A system of equations is a collection of two or more equations with a set of variables. Systems of equations allow us to express systems involving multiple interrelated quantities.
For differential equations, converting a higher-order equation into a system of first-order equations can simplify the process of solving them. This approach is particularly useful with numerical methods since many numerical algorithms are naturally expressed using first-order equations.
Converting a single second-order differential equation into two first-order equations, as seen in the exercise, helps in applying various solution techniques like matrix methods or software tools.
  • In our exercise, the second-order equation is expressed as a system using two variables: \( x(t) \) and \( v(t) \).
  • The resulting system is better suited for computational solving, enhancing conceptual understanding and numerical analysis.
"},{"concept_headline":"The Transformation Process Simplified","text":"The transformation process involves re-expressing complex differential equations into simpler forms. Converting a second-order differential equation into a system of first-order equations is a common technique to simplify the analysis.
In our example, the original equation \( \frac{d^{2} x}{d t^{2}} - 2 \frac{dx}{dt} = \frac{x}{2} \) involves the second derivative. To convert it into a system of first-order equations, follow these steps:
  • **Define a new variable:** We introduce \( v(t) = \frac{dx}{dt} \), representing the first derivative of \( x \).
  • **Express the second derivative:** Replace \( \frac{d^{2} x}{d t^{2}} \) with the derivative of \( v \), giving us \( \frac{dv}{dt} \).
  • **Form the system:** Substitute \( v(t) \) and \( \frac{dv}{dt} \) in the original equation to form:
    1. \( \frac{dx}{dt} = v \)
    2. \( \frac{dv}{dt} = \frac{x}{2} + 2v \)
By following the steps of creating new variables and substitutions, the transformation efficiently sets us up for easier solutions using well-established mathematical methods."}]} 攵勳渼旮 uso: goledningclient testimonials: [ {" quote":"The exercises were amazing. The detailed articles helped me really grasp the difficult concept of differential equations.", "By": "Emily S.", "occupation":" student "}, {" quote":"The breakdown makes it feel fool-proof, it's a life saver before finals!", "By": "James T.", "occupation":" student "}] 鞓る姌鞚 靸堧鞖 觳儛 鞝曤炒 - 雮犾 : 旮堨殧鞚 鞚茧皹 頃橃澊敫岇磮 - 10:飒 瓴届毎 雿办澊韯 Google Russia & Co ... 鞀ろ儉韸胳梾 鞛レ勾毵岉晿氅 氇╈爜歆鞐愱矊 氙胳硱鞎 頃滊嫟 launching 鞀ろ儉韸胳梾 鞛レ勾毵岉晿氅 氇╈爜歆鞐愱矊 氙胳硱鞎 頃滊嫟 鞛 旃措頃橂┐ 氇╈爜歆鞐愱矊 氙胳硱鞎 頃滊嫟 氚 Lo net Vegetarian climate 鞚检瀽 須岇偓 韱淀暅 瓴冹瀰雼堧嫟 氚 鞙勴暅 旮绊泟 搿滊摐毵奠潉 鞐 霃勲嫭 臧曥“頄堨姷雼堧嫟. -Vegeterian climate 鞝勲 頂岆灚韽 鞚挫澋 鞝曤炒鞐 雽鞁 鞝勲 strong eco 瓴瀰雼堧嫟. 旮 啶嗋お啶曕 啶呧げ啶距さ啶, client testimonials: [{

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Most popular questions from this chapter

We consider differential equations of the form \(\frac{d \mathbf{x}}{d t}=A \mathbf{x}(t)\) where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilib\mathrm{\\{} r i u m ~ a c c o r d i n g ~ t o ~ w h e t h e r ~ i t ~ i s ~ a ~ s i n k , ~ a ~ s o u r c e , ~ o r ~ a ~ s a d d l e ~ point. \(A=\left[\begin{array}{rr}-1 & 0 \\ 0 & 4\end{array}\right]\)

Assume that \(a>0\). Find all point equilibria of $$ \begin{array}{l} \frac{d x_{1}}{d t}=1-a x_{1} x_{2} \\ \frac{d x_{2}}{d t}=a x_{1} x_{2}-x_{2} \end{array} $$ and characterize their stability.

24\. Two Hot and Cold Lovers Imagine that Romeo and Juliet both behave in the same way Romeo does in Example \(4 ;\) that is, their affections are modeled by a system of equations $$ \begin{array}{l} \frac{d J}{d t}=-b R \\ \frac{d R}{d t}=-b J \end{array} $$ where \(b\) is a positive constant. (a) By writing the system (11.55) as a matrix equation classify the equilibrium \((0,0)\); i.e., is it a stable node, spiral, saddle point, and so on? (b) Find the eigenvector directions for the equilibrium. (c) Based on your answers to (a) and (b), what is the fate of Romeo and Juliet's relationship as \(t \rightarrow \infty\) ?

We consider differential equations of the form \(\frac{d \mathbf{x}}{d t}=A \mathbf{x}(t)\) where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilib\mathrm{\\{} r i u m ~ a c c o r d i n g ~ t o ~ w h e t h e r ~ i t ~ i s ~ a ~ s i n k , ~ a ~ s o u r c e , ~ o r ~ a ~ s a d d l e ~ point. \(A=\left[\begin{array}{rr}-2 & -3 \\ 1 & 3\end{array}\right]\)

Transform the second-order differential equation $$ \frac{d^{2} x}{d t^{2}}=-\frac{1}{2} x $$ into a system of first-order differential equations.

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