Chapter 10: Problem 36
Let $$f(x, y)=2 x^{2}+3 y^{2}$$ Use the \(\epsilon-\delta\) definition of limits to show that $$\lim _{(x, y) \rightarrow(0,0)} f(x, y)=0$$
Short Answer
Expert verified
The limit is 0, using the \( \epsilon-\delta \) definition of limits.
Step by step solution
01
Understanding the Limit Statement
We want to show that \( \lim_{(x, y) \rightarrow (0,0)} f(x, y) = 0 \). This means we need to prove that for any \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that whenever \( \sqrt{x^2 + y^2} < \delta \), it follows that \( |f(x, y) - 0| < \epsilon \).
02
Expressing the Function in Terms of \( (x, y) \)
The function is given as \( f(x, y) = 2x^2 + 3y^2 \). We need \( |f(x, y)| = |2x^2 + 3y^2| \) to be less than \( \epsilon \).
03
Bounding \( |f(x, y)| \) with \( x^2 + y^2 \)
Observe that \( |f(x, y)| = |2x^2 + 3y^2| \leq 2x^2 + 3y^2 \leq 2(x^2 + y^2) + 3(x^2 + y^2) = 5(x^2 + y^2) \).
04
Expressing \( (x, y) \) in Polar Coordinates
Convert \( (x, y) \) to polar coordinates where \( x = r\cos(\theta) \) and \( y = r\sin(\theta) \), thus \( x^2 + y^2 = r^2 \).
05
Establishing a Relationship Between \( \delta \) and \( \epsilon \)
Now, \( 5(x^2 + y^2) = 5r^2 \). We want \( 5r^2 < \epsilon \), hence \( r^2 < \frac{\epsilon}{5} \). If \( r = \sqrt{x^2 + y^2} < \delta \), we choose \( \delta = \sqrt{\frac{\epsilon}{5}} \).
06
Concluding the \( \epsilon-\delta \) Proof
Therefore, for any \( \epsilon > 0 \), choosing \( \delta = \sqrt{\frac{\epsilon}{5}} \) ensures that \( \sqrt{x^2 + y^2} < \delta \) implies \( 5r^2 < \epsilon \), thus \( |f(x, y)| < \epsilon \). This satisfies the \( \epsilon-\delta \) definition of the limit, proving the limit statement.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Epsilon-Delta Definition of Limits
The epsilon-delta definition of limits is crucial in understanding continuity and the behavior of functions at specific points. It mathematically formalizes the intuitive idea of a limit. For a multivariable function like \( f(x, y) \), this definition extends from the single-variable case to two variables. In this setting, our goal is to show that as \((x, y)\) approaches \((0, 0)\), the function \(f(x, y)\) approaches a particular value, typically zero.
Formally, for \( \lim_{(x, y) \to (a, b)} f(x, y) = L \), it means for every \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that if \( \sqrt{(x-a)^2 + (y-b)^2} < \delta \), then \( |f(x, y) - L| < \epsilon \). For our specific function \( f(x, y) = 2x^2 + 3y^2 \), this translates into proving the closeness of \( f(x, y) \) to zero whenever \( (x, y) \) is sufficiently close to \( (0, 0) \) within a certain radius.
This approach gives an exact method to evaluate limits and is fundamental for ensuring a function's closeness to a particular value at a given point.
Formally, for \( \lim_{(x, y) \to (a, b)} f(x, y) = L \), it means for every \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that if \( \sqrt{(x-a)^2 + (y-b)^2} < \delta \), then \( |f(x, y) - L| < \epsilon \). For our specific function \( f(x, y) = 2x^2 + 3y^2 \), this translates into proving the closeness of \( f(x, y) \) to zero whenever \( (x, y) \) is sufficiently close to \( (0, 0) \) within a certain radius.
This approach gives an exact method to evaluate limits and is fundamental for ensuring a function's closeness to a particular value at a given point.
Limits in Two Variables
Limits in two variables can be more complicated than in single-variable calculus because they require consideration of the point's approach direction. As \((x, y)\) approaches a target point, \((0, 0)\) in this problem, it can do so from infinitely many directions. This attribute makes verifying the existence of a limit more intricate.
The function \( f(x, y) = 2x^2 + 3y^2 \) must satisfy the limit condition from any path converging to \((0, 0)\). A common way to handle this is by bounding the function by expressions of \( x \) and \( y \). We derived that \(|2x^2 + 3y^2| \leq 5(x^2 + y^2)\), helping to connect the \( \epsilon \) and \( \delta \) directly.
Conclusively, analyzing how close \( (x, y) \) need to be to \( (0, 0) \) for \( |f(x, y) - 0| < \epsilon \) leads us to choose a suitable \( \delta \). This ensures the function's limit evaluation is both precise and consistent regardless of the path taken.
The function \( f(x, y) = 2x^2 + 3y^2 \) must satisfy the limit condition from any path converging to \((0, 0)\). A common way to handle this is by bounding the function by expressions of \( x \) and \( y \). We derived that \(|2x^2 + 3y^2| \leq 5(x^2 + y^2)\), helping to connect the \( \epsilon \) and \( \delta \) directly.
Conclusively, analyzing how close \( (x, y) \) need to be to \( (0, 0) \) for \( |f(x, y) - 0| < \epsilon \) leads us to choose a suitable \( \delta \). This ensures the function's limit evaluation is both precise and consistent regardless of the path taken.
Polar Coordinates
Polar coordinates offer a powerful tool to simplify complex limit problems, especially in multivariable calculus. By converting Cartesian coordinates \((x, y)\) into polar form using the transformations \( x = r\cos(\theta) \) and \( y = r\sin(\theta) \), the analysis often becomes more manageable. Here, \( r \) represents the radial distance from the origin, and \( \theta \) the angle from the positive x-axis.
In this problem, noticing that \( x^2 + y^2 = r^2 \) allows us to rewrite the function \( f(x, y) = 2x^2 + 3y^2 \) as a function of \( r \). The expression \( 5(x^2 + y^2) = 5r^2 \) clearly shows the direct dependence of the function value on the radial distance \( r \) from the origin.
This simplification highlights the direct relationship inherent in the \( \epsilon \)-\( \delta \) proof, simplifying the process of finding an appropriate \( \delta \) given \( \epsilon \). Using polar coordinates is a staple technique when exploring limits in a two-dimensional context, offering clearer insights and often reducing algebraic complexity.
In this problem, noticing that \( x^2 + y^2 = r^2 \) allows us to rewrite the function \( f(x, y) = 2x^2 + 3y^2 \) as a function of \( r \). The expression \( 5(x^2 + y^2) = 5r^2 \) clearly shows the direct dependence of the function value on the radial distance \( r \) from the origin.
This simplification highlights the direct relationship inherent in the \( \epsilon \)-\( \delta \) proof, simplifying the process of finding an appropriate \( \delta \) given \( \epsilon \). Using polar coordinates is a staple technique when exploring limits in a two-dimensional context, offering clearer insights and often reducing algebraic complexity.