Chapter 1: Problem 92
Simplify each expression and write it in the standard form \(a+b i\). \((-4-3 i)(4+3 i)\)
Short Answer
Expert verified
The expression simplifies to \(-7 - 24i\), which is the standard form.
Step by step solution
01
Identify the Expression Form
The expression \((-4-3i)(4+3i)\) is in the form of \((a+bi)(c+di)\). Our goal is to simplify this product.
02
Apply the FOIL Method
Use the FOIL method (First, Outer, Inner, Last) to expand the product:- First: \(-4 \cdot 4 = -16\)- Outer: \(-4 \cdot 3i = -12i\)- Inner: \(-3i \cdot 4 = -12i\)- Last: \(-3i \cdot 3i = -9i^2\)
03
Simplify \(i^2\) Term
Recall that \(i^2 = -1\). Thus, \(-9i^2 = -9(-1) = 9\).
04
Combine Like Terms
Add together the expanded components from Step 2:\(-16 - 12i - 12i + 9\).Combine like terms:- Real part: \(-16 + 9 = -7\)- Imaginary part: \(-12i - 12i = -24i\)
05
Write in Standard Form
The expression simplifies to \(-7 - 24i\), which is in the standard form \(a + bi\).
06
Final Answer Confirmation
Review each step to ensure calculations are correct, and confirm the final answer is in the form \(a+bi\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
FOIL Method
The FOIL method is a powerful tool for expanding the product of two binomials. This is particularly useful when dealing with complex numbers in the form \((a+bi)(c+di)\). FOIL stands for First, Outer, Inner, Last. Here’s how each step works with our original exercise example:
- First: Multiply the first terms in each binomial: \(-4 \cdot 4 = -16\).
- Outer: Multiply the outer most terms in the expression: \(-4 \cdot 3i = -12i\).
- Inner: Multiply the inner most terms: \(-3i \cdot 4 = -12i\).
- Last: Multiply the last terms in the binomials: \(-3i \cdot 3i = -9i^2\).
Imaginary Unit
The imaginary unit, denoted as \(i\), plays a critical role in complex numbers. It is defined by the property \(i^2 = -1\). Understanding this concept is key for simplifying expressions involving complex numbers.
In our exercise, the term \(-9i^2\) appears. By substituting \(i^2\) with \(-1\), the term simplifies to \(9\). This substitution transforms complex products into real numbers, highlighting why understanding \(i\) is essential.
Always remember:
In our exercise, the term \(-9i^2\) appears. By substituting \(i^2\) with \(-1\), the term simplifies to \(9\). This substitution transforms complex products into real numbers, highlighting why understanding \(i\) is essential.
Always remember:
- When you see \(i^2\), replace it with \(-1\).
- Pay attention to how imaginary terms interact with real terms in a product.
- Recognize \(i\) as the building block for creating and simplifying complex scenarios.
Standard Form
When working with complex numbers, it's important to express them in the standard form, \(a + bi\). This format consists of two parts:
After using the FOIL method on our exercise, our expression becomes \(-7 - 24i\). Here, \(-7\) is the real part, and \(-24i\) is the imaginary part. To express the result in standard form, simply combine these terms clearly, as we've done.
Why is standard form helpful?
- The real part, \(a\), a regular real number, easy to identify and isolated from any imaginary component.
- The imaginary part, \(bi\), which includes the imaginary unit \(i\).
After using the FOIL method on our exercise, our expression becomes \(-7 - 24i\). Here, \(-7\) is the real part, and \(-24i\) is the imaginary part. To express the result in standard form, simply combine these terms clearly, as we've done.
Why is standard form helpful?
- It provides a clear and organized way to present complex numbers.
- Makes addition, subtraction, and comparison of complex numbers simpler.
- Helps in easily identifying the magnitude and direction if represented on a complex plane.