Chapter 1: Problem 9
Determine the equation of the line that satisfies the stated requirements. Put the equation in standard form. The line passing through \((0,-2)\) with slope \(-3\)
Short Answer
Expert verified
The equation in standard form is \( 3x + y = -2 \).
Step by step solution
01
Use point-slope form
To find the equation of a line, we can start with the point-slope form of a line's equation, which is \( y - y_1 = m(x - x_1) \). Here, \( m \) is the slope and \( (x_1, y_1) \) is a point on the line. We are given the slope \( m = -3 \) and the point \( (0, -2) \).
02
Plug values into point-slope form
Substitute the slope and point into the point-slope form: \( y - (-2) = -3(x - 0) \). This simplifies to \( y + 2 = -3x \).
03
Simplify to slope-intercept form
Rearrange the equation to isolate \( y \): \( y = -3x - 2 \). This is the slope-intercept form of the equation, where \( y = mx + b \).
04
Convert to standard form
The standard form of a linear equation is \( Ax + By = C \). To convert \( y = -3x - 2 \) to standard form, we rearrange it to \( 3x + y = -2 \).
05
Verify standard form
Check to ensure that the standard form equation \( 3x + y = -2 \) satisfies the original point and slope requirements. Substitute \( x = 0 \) into the equation to find \( y \) and confirm the slope. This shows the equation is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
The point-slope form of a linear equation is a flexible way to describe a line using the slope and a single point on the line. The formula is written as:\[ y - y_1 = m(x - x_1) \]where:
This form highlights the rate of change (the slope) directly, so it's very informative for understanding how steep or shallow a line is relative to the axes.
- \( m \) is the slope of the line.
- \( (x_1, y_1) \) is a known point on the line.
This form highlights the rate of change (the slope) directly, so it's very informative for understanding how steep or shallow a line is relative to the axes.
Slope-Intercept Form
The slope-intercept form is the most straightforward way to express a linear equation. It is written as:\[ y = mx + b \]where:
This method is most useful for understanding linear behavior. It shows how fast \( y \) changes with \( x \) (the slope), and where the line crosses the y-axis (the intercept). Using this form, you can swiftly sketch a graph since it directly gives two critical components: the slope and the intercept.
- \( m \) represents the slope of the line.
- \( b \) is the y-intercept, where the line cuts the y-axis.
This method is most useful for understanding linear behavior. It shows how fast \( y \) changes with \( x \) (the slope), and where the line crosses the y-axis (the intercept). Using this form, you can swiftly sketch a graph since it directly gives two critical components: the slope and the intercept.
Standard Form
The standard form of a linear equation is another method to express linear relationships. The general look is:\[ Ax + By = C \]where:
To convert a slope-intercept form equation to standard form, rearrange the terms to place all variables on one side. This transformation often involves ensuring that the leading coefficient \( A \) is positive and that all coefficients are integers. This form is particularly useful for solving systems of equations. It provides a neat format for equation manipulation, making it easier to substitute and solve.
- \( A \), \( B \), and \( C \) are integers.
- \( A \) should be a non-negative integer.
To convert a slope-intercept form equation to standard form, rearrange the terms to place all variables on one side. This transformation often involves ensuring that the leading coefficient \( A \) is positive and that all coefficients are integers. This form is particularly useful for solving systems of equations. It provides a neat format for equation manipulation, making it easier to substitute and solve.