/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Use a logarithmic transformation... [FREE SOLUTION] | 91Ó°ÊÓ

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Use a logarithmic transformation to find a linear relationship between the given quantities and determine whether a log-log or log-linear plot should be used to graph the resulting linear relationship. $$ R(t)=3.6 t^{1.2} $$

Short Answer

Expert verified
Use a log-log plot to graph the linear relationship.

Step by step solution

01

Understand the Equation

We need to transform the given equation \( R(t) = 3.6 t^{1.2} \) using logarithms to linearize it. Our goal is to find a linear relationship that can easily be graphed.
02

Apply the Logarithm Transformation

Apply the natural logarithm to both sides of the equation. Start with \( R(t) = 3.6 t^{1.2} \). Applying the logarithm, we have: \( \ln(R(t)) = \ln(3.6 t^{1.2}) \).
03

Simplify the Logarithmic Expression

Using logarithm properties, \( \ln(ab) = \ln(a) + \ln(b) \) and \( \ln(b^c) = c\ln(b) \), we can simplify: \( \ln(R(t)) = \ln(3.6) + 1.2\ln(t) \).
04

Determine the Linear Form

The equation \( \ln(R(t)) = \ln(3.6) + 1.2\ln(t) \) is now in the linear form \( y = mx + c \) where \( y = \ln(R(t)) \), \( x = \ln(t) \), \( m = 1.2 \), and \( c = \ln(3.6) \).
05

Decide the Plot Type

Since both \( y \) and \( x \) are logarithms (\( \ln(R(t)) \) vs \( \ln(t) \)), this setup uses a log-log plot. The relationship between \( \ln(R(t)) \) and \( \ln(t) \) is linear.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Relationship
In mathematics, a linear relationship refers to a type of connection between two variables where the change in one variable is proportional to the change in another. This concept is fundamental because it simplifies the analysis of complex relationships by making them easier to understand and graph.

When addressing the initial problem involving the formula \( R(t) = 3.6 t^{1.2} \), we aim to transform this equation so that it fits the linear equation format \( y = mx + c \). In this format, \( y \) and \( x \) are variables, \( m \) represents the slope, and \( c \) is the y-intercept.

To create a linear relationship out of a function like \( R(t) \), where one term is raised to a power, a logarithmic transformation is often utilized. By converting the function's components using logarithms, we return a straight line graph representation, which is much simpler to interpret. In this transformed equation, the coefficients and constants still provide meaningful insights into the nature of the relationship, just as the slope and intercept do in standard linear equations.
Log-Log Plot
A log-log plot is useful when both the dependent and independent variables in an equation are best expressed on a logarithmic scale, leading to a straight line when graphed.

After applying the logarithm to the equation \( R(t) = 3.6 t^{1.2} \), we derived \( \ln(R(t)) = \ln(3.6) + 1.2\ln(t) \). This transformation aligned the given function into a linear format with:
  • \( y = \ln(R(t)) \)
  • \( x = \ln(t) \)
  • \( m = 1.2 \) representing the slope
  • \( c = \ln(3.6) \) as the y-intercept

The log-log plot comes into play because both the variables \( \ln(R(t)) \) and \( \ln(t) \) are in a logarithmic form. Thus, when graphed on a log-log plot, the relationship between these two will appear as a straight line. This transformation helps in understanding how changes in the independent variable proportionally affect the dependent variable on a multiplicative scale. The slope of the line on a log-log plot directly informs us how the percentage change in \( t \) affects \( R(t) \).
Log-Linear Plot
In contrast to a log-log plot, a log-linear plot is used when only one of the variables in an equation is expressed on a logarithmic scale. In such cases, a transformation is applied to the exponential function for either the dependent or the independent variable, but not both.

For the problem \( R(t) = 3.6 t^{1.2} \), the need for a log-log plot was established. However, if this had involved transforming \( R(t) \) without needing to transform \( t \), a log-linear plot might have been appropriate.

Essentially, this kind of plot is ideal for visualizing data that changes at an exponential rate. By using a logarithmic scale for only one axis, such linearity can be achieved for relationships that might otherwise appear nonlinear. For example, exponentials involving interest rates or population growth often fit a log-linear model.
This transformation indicates how one variable changes proportionally to exponential changes in another, simplifying the understanding of growth or decay processes and aiding in predictive modeling.

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Most popular questions from this chapter

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sketch the graph of each function. Do not use a graphing calculator. (Assume the largest possible domain.) $$ y=-2 \cos (\pi x / 4) $$

Use a logarithmic transformation to find \(a\) linear relationship between the given quantities and graph the \mathrm{\\{} r e s u l t i n g ~ l i n e a r ~ r e l a t i o n s h i p ~ o n ~ a ~ l o g - l i n e a r ~ p l o t . ~ $$ y=3 \times 5^{-1.3 x} $$

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