Chapter 1: Problem 5
sketch the graph of each function. Do not use a graphing calculator. (Assume the largest possible domain.) $$ y=-2 x^{2}-3 $$
Short Answer
Expert verified
The graph is a downward-opening parabola with vertex (0, -3). Plot additional points for accuracy.
Step by step solution
01
Identify the Function
The given function is a quadratic function in the form \( y = -2x^2 - 3 \), where the coefficient of \( x^2 \) is negative, indicating it is a downward-opening parabola.
02
Determine the Vertex
For the quadratic \( y = ax^2 + bx + c \), the vertex's x-coordinate can be found using \( x = -\frac{b}{2a} \). In this function, \( a = -2 \), \( b = 0 \), and \( c = -3 \), giving \( x = 0 \). Substituting \( x = 0 \) into the function gives \( y = -3 \). Thus, the vertex is at \( (0, -3) \).
03
Find the Axis of Symmetry
The axis of symmetry for a parabola in the form \( y = ax^2 + bx + c \) is the vertical line \( x = -\frac{b}{2a} \). For this function, it is \( x = 0 \), which corresponds to the x-coordinate of the vertex.
04
Find the Y-intercept
The y-intercept is found by setting \( x = 0 \). Substituting gives \( y = -3 \), so the y-intercept is \( (0, -3) \), which coincides with the vertex.
05
Calculate Additional Points
To better sketch the graph, find additional points. Let's choose \( x = 1 \) and \( x = -1 \). For \( x = 1 \), \( y = -2(1)^2 - 3 = -5 \). For \( x = -1 \), \( y = -2(-1)^2 - 3 = -5 \). Therefore, we have points \( (1, -5) \) and \( (-1, -5) \).
06
Sketch the Parabola
Plot the vertex \( (0, -3) \), y-intercept \( (0, -3) \), and additional points \( (1, -5) \) and \( (-1, -5) \). Draw a smooth curve through these points, making sure the parabola opens downward due to the negative sign of the coefficient \( -2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a critical point that provides key information about the graph of a quadratic function. In any quadratic function given by the general form \( y = ax^2 + bx + c \), the vertex is the point where the parabola reaches its maximum or minimum value. This depends on whether the parabola opens upwards or downwards.
- For a parabola that opens downwards, the vertex is the highest point, called the maximum point.
- For a parabola that opens upwards, the vertex is the lowest point, known as the minimum point.
Axis of Symmetry
The axis of symmetry of a parabola is a vertical line that divides the parabola into two mirror-image halves. This line passes through the vertex of the parabola, ensuring that one side is a reflected version of the other. The symmetrical nature of the parabola means that for any point \((x, y)\) on one side of the axis of symmetry, there is a corresponding point \((-x, y)\) on the opposite side. For any quadratic function in the form \( y = ax^2 + bx + c \), the equation for the axis of symmetry is given by:\( x = -\frac{b}{2a} \). This formula is derived from the coordinate of the vertex and is identical to the calculation for the x-coordinate of the vertex. In our case with the function \( y = -2x^2 - 3 \), the axis of symmetry coincides with \( x = 0 \), aligning with the vertex's x-coordinate. This means that the line \( x = 0 \) is the axis of symmetry, which means the left side and right side of the parabola on either side of \( x = 0 \) are mirror images of each other.
Y-intercept
A y-intercept is a specific point on the graph where the curve crosses the y-axis. At the y-intercept, the x-coordinate is always zero. Finding the y-intercept of a quadratic function is straightforward: simply substitute \( x = 0 \) into the equation and solve for \( y \). In the provided exercise with the function \( y = -2x^2 - 3 \), plugging \( x = 0 \) into the equation yields \( y = -3 \). Therefore, the y-intercept is \((0, -3)\). It is noteworthy that in a parabola, the vertex and y-intercept can sometimes be the same point, particularly when the axis of symmetry is \( x = 0 \), which centers the parabola over the y-axis, as seen in the exercise.
- The y-intercept gives us a concrete point through which we start plotting the parabola.
- It helps in visualizing the graph since it's part of the most basic framework used to sketch the parabola.