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Explain how the following functions can be obtained from \(y=\ln x\) by basic transformations: (a) \(y=\ln (x-1)\) (b) \(y=-\ln x+1\) (c) \(y=\ln (x+3)-1\)

Short Answer

Expert verified
(a) Shift right, (b) Reflect and shift up, (c) Shift left and down.

Step by step solution

01

Understanding the Parent Function

The parent function given is \(y = \ln x\). This is the natural logarithm function with base \(e\), whose graph is defined for \(x > 0\) and passes through the point \((1, 0)\). The graph is an increasing curve situated in the first quadrant, with a vertical asymptote at \(x = 0\).
02

Step A: Horizontal Shift for y = \ln(x-1)

The function \(y = \ln(x-1)\) indicates a horizontal shift of the graph of \(y = \ln x\). The subtraction inside the logarithm, \(x - 1\), moves the graph to the right by 1 unit. This means the vertical asymptote shifts to \(x = 1\), and the point \((1, 0)\) shifts to \((2, 0)\).
03

Step B: Reflection and Vertical Shift for y = -\ln x + 1

The function \(y = -\ln x + 1\) can be broken down into two transformations: reflection and vertical shift. The negative sign in front of \(\ln x\) reflects the graph across the x-axis, resulting in a decreasing graph. The addition of 1 shifts the entire graph vertically up by 1 unit. If the vertical asymptote is \(x = 0\) and it remains so, the key point \((1, 0)\) is transformed to \((1, 1)\).
04

Step C: Horizontal and Vertical Shift for y = \ln(x+3) - 1

For \(y = \ln(x+3) - 1\), observe both a horizontal and a vertical transformation. The addition inside the logarithm, \(x + 3\), moves the graph to the left by 3 units. This adjusts the asymptote to \(x = -3\), and moves the point \((1, 0)\) left to \((-2, 0)\). The subtraction of 1 moves the graph vertically downward by 1 unit, resulting in the point becoming \((-2, -1)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graph Shifting
Graph shifting is a basic transformation that involves moving the graph of a function either horizontally or vertically. This is done by changing the values inside the function or altering the function value itself. Let’s break down these two types of shifts in simple terms.

**Horizontal Shifting**
When changing the value inside a function, it results in a horizontal shift. For example, given the function \(y = \ln(x-1)\), the \(x - 1\) part indicates that the graph of \(y = \ln x\) shifts to the right by 1 unit. This shift causes the previously existing vertical features to move accordingly. For instance, the vertical asymptote originally at \(x = 0\) will now be at \(x = 1\). Similarly, key points on the graph also shift, such as \(\(1, 0\)\) moving to \(\(2, 0\)\).

**Vertical Shifting**
Vertical shifts occur when a constant is added or subtracted directly to the output of the function. For example, the function \(y = \ln x - 1\) suggests a downward shift of the graph by 1 unit. It does not affect the vertical asymptote but transforms the value of each point on the graph downwards, turning \(\(1, 0\)\) into \(\(1, -1\)\).

These graph shifting techniques help understand how a small alteration in a function equation can entirely change the position of its graph in the coordinate plane.
Vertical Asymptote
A vertical asymptote is essentially an invisible boundary on a graph where the function approaches but never quite reaches or crosses. For the natural logarithm function \(y = \ln x\), there is a vertical asymptote at \(x = 0\). This is important because it sets the domain restriction for the function, meaning that \(x\) must remain positive at all times.

When transformations, such as horizontal shifts, are applied to the logarithmic function, the vertical asymptote also shifts. In the case of \(y = \ln (x-1)\), for instance, the subtraction inside the logarithm \(x-1\) moves the asymptote from \(x = 0\) to \(x = 1\).

However, some transformations do not affect the vertical asymptote. For example, a vertical shift like \(y = \ln x + 1\) or a reflection like in \(y = -\ln x\) leaves the asymptote unchanged. It's significant to know how these asymptotes move because they help in understanding the domain and behavior of transformed functions.
Natural Logarithm Function
The natural logarithm function is an important mathematical function often denoted as \(y = \ln x\). This function is the logarithm to the base \(e\), where \(e\) is an irrational constant approximately equal to 2.71828. It’s uniquely characterized by continuously growing along the x-axis as it passes through the point \(\(1, 0\)\).

Its graphical representation is a smooth curve that starts near the vertical asymptote at \(x = 0\) and rises towards the right, passing through significant points such as \(\(1, 0\)\).

The natural logarithm function is often modified with transformations for different applications, maintaining the same vertical asymptote when only vertical transformations like reflections or shifts are applied. With thorough understanding, students can analyze and graph its transformations readily. These adjustments in the natural logarithm allow for modelling and solving real-world exponential growth or decay problems.

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Most popular questions from this chapter

Explain how the following functions can be obtained from \(y=1 / x^{2}\) by basic transformations: (a) \(y=\frac{1}{x^{2}}+1\) (b) \(y=-\frac{1}{(x+1)^{2}}\) (c) \(y=-\frac{1}{x^{2}}-2\)

Use a logarithmic transformation to find \(a\) linear relationship between the given quantities and graph the \mathrm{\\{} r e s u l t i n g ~ l i n e a r ~ r e l a t i o n s h i p ~ o n ~ a ~ l o g - l i n e a r ~ p l o t . ~ $$ y=3 \times 10^{-2 x} $$

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Use a logarithmic transformation to find a linear relationship between the given quantities and determine whether a log-log or log-linear plot should be used to graph the resulting linear relationship. $$ f(x)=3 x^{1} $$

Find the following numbers on a number line that is on a logarithmic scale (base 10): \(0.03,0.7,1,2,5,10,17,100,150\), and \(2000 .\)

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