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Suppose that \(f(x)=\frac{1}{x}, x \neq 0\), and \(g(x)=\sqrt{x}, x \geq 0\). (a) Find \((f \circ g)(x)\) together with its domain. (b) Find \((g \circ f)(x)\) together with its domain.

Short Answer

Expert verified
(a) \((f \circ g)(x) = \frac{1}{\sqrt{x}}\), domain: \((0, \infty)\). (b) \((g \circ f)(x) = \sqrt{\frac{1}{x}}\), domain: \((0, \infty)\).

Step by step solution

01

Understand the Composition of Functions

To compose functions, we substitute one function into another. For the composition \((f \circ g)(x)\), we substitute \(g(x)\) into \(f(x)\). Similarly, for \((g \circ f)(x)\), we substitute \(f(x)\) into \(g(x)\). This means we'll need to evaluate each composition individually.
02

Find \((f \\circ g)(x)\)

The composition \((f \circ g)(x)\) means we replace \(x\) in \(f(x)\) with \(g(x)\). Since \(f(x) = \frac{1}{x}\) and \(g(x) = \sqrt{x}\), we have: \[ (f \circ g)(x) = f(g(x)) = f(\sqrt{x}) = \frac{1}{\sqrt{x}}. \]
03

Determine the Domain for \((f \\circ g)(x)\)

The domain of \((f \circ g)(x)\) is determined by the domains of \(f(x)\) and \(g(x)\). \(g(x) = \sqrt{x}\) requires \(x \geq 0\). Also, \(f(x) = \frac{1}{\sqrt{x}}\) requires \(\sqrt{x} eq 0\), which means \(x eq 0\). Thus, the domain is all non-negative \(x\) such that \(x > 0\). Therefore, the domain is \((0, \infty)\).
04

Find \((g \\circ f)(x)\)

The composition \((g \circ f)(x)\) means we replace \(x\) in \(g(x)\) with \(f(x)\). Since \(f(x) = \frac{1}{x}\) and \(g(x) = \sqrt{x}\), we have: \[ (g \circ f)(x) = g(f(x)) = g\left(\frac{1}{x}\right) = \sqrt{\frac{1}{x}}. \]
05

Determine the Domain for \((g \\circ f)(x)\)

The domain of \(g(x) = \sqrt{x}\) requires that its input is non-negative. Thus, for \(g(\frac{1}{x})\) to exist, \(\frac{1}{x} > 0\), meaning \(x > 0\) (since \(x\) cannot be zero). Therefore, the domain of \((g \circ f)(x)\) is \((0, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domains of Functions
In mathematics, the domain of a function is the complete set of possible values of the independent variable (usually represented as "x") for which the function is defined. Understanding a function's domain is critical when performing operations like function composition because it determines where the function can take on real values.

When functions are composed, the domain of the resulting function is often impacted by the domains of the individual functions being used. For example, if we have two functions, say \(f(x)\) and \(g(x)\), and wanted to find \((f \circ g)(x)\), the domain would include all values of \(x\) that are valid in \(g(x)\), and whose outputs \(g(x)\) are in the domain of \(f(x)\).

Therefore, always start by identifying the domain constraints for each function and apply these constraints thoughtfully when determining the domain of their composition. It might help to write down the restrictions from each function with respect to real numbers and make sure those restrictions are maintained in the composed function.
Square Root Function
The square root function, usually denoted as \(g(x) = \sqrt{x}\), is defined only for non-negative values of \(x\). This is because the square root of a negative real number is not a real number. Hence, the domain of the basic form of this square root function is \(x \geq 0\).

Let's discuss its use with composition of functions. If \(g(x) = \sqrt{x}\) has to be composed with another function, such as \(f(x)\), then \(g(f(x))\) requires that \(f(x)\) provides non-negative outputs. For example, if we are considering \(g(f(x))\) like in the exercise \((g \circ f)(x)\), the input to the square root function (which in this case is \(f(x)\)) must always be \(\geq 0\) for the composition to be valid.

Anytime you're working with square root functions, you have to ensure the maintenance of non-negativity on the inside values, so be cautious and check where the inputs satisfy \( \geq 0\). This is crucial in maintaining the real-number outcomes of your expressions.
Rational Function
A rational function is a type of function expressed as the ratio of two polynomials, usually in the form \(f(x) = \frac{p(x)}{q(x)}\), where \(q(x)eq 0\). The domain of a rational function is all real numbers except those that make the denominator zero, since division by zero is undefined in mathematics.

For instance, the function \(f(x) = \frac{1}{x}\) is a simple rational function. Its domain is all real numbers except zero, because zero in the denominator would make the function undefined. When evaluating composed functions like \((f \circ g)(x)\), you need to consider this undefined nature at particular values.

Think about the domain conflicts that might arise when your composed outputs make the denominator zero. In our example, with \((f \circ g)(x) = \frac{1}{\sqrt{x}}\), understanding that \(\sqrt{x} eq 0\) is necessary keeps the function defined. Therefore, it's avoided by setting conditions such as \(x > 0\) to ensure that every aspect satisfies the domain requirements allowing rational operations without undefined results.

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Most popular questions from this chapter

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