Chapter 6: Problem 12
Find \(\frac{d y}{d x} .\) $$ y=\int_{-1}^{x} \frac{2}{2+u^{2}} d u $$
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Chapter 6: Problem 12
Find \(\frac{d y}{d x} .\) $$ y=\int_{-1}^{x} \frac{2}{2+u^{2}} d u $$
These are the key concepts you need to understand to accurately answer the question.
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Use Leibniz's rule to find \(\frac{d y}{d x}\). $$ y=\int_{2+x^{2}}^{2} \cot t d t $$
Compute the indefinite integrals. $$ \int \csc ^{2}(2 x) d x $$
Suppose that $$\int_{0}^{x} f(t) d t=2 x^{2}$$ Find \(f(x)\).
Compute the indefinite integrals. $$ \int(x-1)^{2} d x $$
Use Leibniz's rule to find \(\frac{d y}{d x}\). $$ y=\int_{x^{3}}^{x^{4}} \ln \left(1+t^{2}\right) d t, x>0 $$
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