Chapter 5: Problem 31
Graph $$ f(x)=|1-| x||, \quad-1 \leq x \leq 2 $$ and determine all local and global extrema on \([-1,2]\).
Short Answer
Expert verified
Global max is 1 at \(x = 0\) and \(x = 2\); global min is 0 at \(x = -1\) and \(x = 1\). No other local extrema.
Step by step solution
01
Understand the Function
The function given is \( f(x) = |1 - |x|| \). This is a composition of absolute value functions. We will analyze how this function behaves by breaking it into different expressions based on the value of \( x \).
02
Break Down the Absolute Values
The innermost absolute value \( |x| \) splits the domain into two cases: \( x \geq 0 \) and \( x < 0 \). - If \( x \geq 0 \), then \( |x| = x \), so the function simplifies to \( |1 - x| \).- If \( x < 0 \), then \( |x| = -x \), so the function becomes \( |1 + x| \).
03
Define the Cases and Simplify
Now defining the outer absolute value for each case:1. **Case 1:** \( x \geq 0 \). - The function is \( |1 - x| \): - If \( x \leq 1 \), then \( |1 - x| = 1 - x \). - If \( x > 1 \), then \( |1 - x| = x - 1 \).2. **Case 2:** \( x < 0 \). - The function is \( |1 + x| \): - If \( x \geq -1 \), then \( |1 + x| = 1 + x \). - If \( x < -1 \), the function is undefined as \( x \) is outside the given interval.
04
Graph the Function
We need to graph the piecewise function derived from the breakdown:- **For \( -1 \leq x < 0 \):** The function follows \( 1 + x \), a line with a slope of 1 starting at (0,1).- **For \( 0 \leq x \leq 1 \):** The function follows \( 1 - x \), a line with a slope of -1 starting at (0,1).- **For \( 1 < x \leq 2 \):** The function follows \( x - 1 \), a line with a slope of 1 starting at (1,0).
05
Determine Extrema
On the graph, identify turning points and endpoints:- The function is continuous from \( x = -1 \) to \( x = 2 \).- **Endpoints:** - At \( x = -1 \), \( f(-1) = 0 \). - At \( x = 2 \), \( f(2) = 1 \).- **Local Minimum at \( x = 1 \) and \( x = -1\):** - \( f(1) = 0 \) and \( f(-1) = 0 \).- **Global Maximum**: The highest value within the interval is \( f(0) = 1 \).
06
Finalize the Analysis of Extrema
Summarize the extrema as follows:- Global Maximum: \( f(x) = 1 \) at \( x = 0 \) and \( x = 2 \).- Global Minimum: \( f(x) = 0 \) at \( x = -1 \) and \( x = 1 \).- No other local extrema in the interval as the function is piecewise linear.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Absolute Value Function
An absolute value function is a special type of function that takes a real number and turns it into its non-negative counterpart. It is represented as \(|x|\), which means "the distance of \(x\) from zero on the number line without considering direction". For any real number \(x\), the absolute value function is defined as follows:
- If \(x \geq 0\), then \(|x| = x\).
- If \(x < 0\), then \(|x| = -x\).
Local and Global Extrema
In calculus, extrema refer to the minimum and maximum values of a function. These can be local or global:
- **Local extrema** are the highest or lowest points in a small neighborhood around a point.
- **Global extrema** are the highest or lowest points in the entire domain of the function.
- **Local Minimum**: Points where the graph's direction changes, found at \(x = -1\) and \(x = 1\) with \(f(-1) = f(1) = 0\).
- **Global Maximum**: The largest value of \(f(x)\) within the interval, occurring at \(x = 0\) and \(x = 2\), where \(f(0) = f(2) = 1\).
Piecewise Functions
A piecewise function is constructed from multiple sub-functions, each applying to a specific part of the domain. Each sub-function has its domain in which the function behaves differently. In our problem, after evaluating the nested absolute values, we define our function in parts:
- For \(-1 \leq x < 0\): \(f(x) = 1 + x\).
- For \(0 \leq x \leq 1\): \(f(x) = 1 - x\).
- For \(1 < x \leq 2\): \(f(x) = x - 1\).
Graphing Functions
Graphing a function involves plotting its behavior over a specified range. For our function \(f(x) = |1 - |x||\), graphing helps visualize its piecewise nature. We plot three segments that represent each sub-function over the given intervals:
- **From \(-1\) to 0**: The line \(1 + x\) starts at \(-1\) and ends at \(0, 1\).
- **From 0 to 1**: The line \(1 - x\) starts from \(0, 1\) and ends at \(1, 0\).
- **From 1 to 2**: The line \(x - 1\) begins from \(1, 0\) and ends at \(2, 1\).