Chapter 4: Problem 45
In Problems , find the tangent line, in standard form, to \(y=\) \(f(x)\) at the indicated point. $$ y=2 x^{4}-5 x, \text { at } x=1 $$
Short Answer
Expert verified
The tangent line in standard form is \( 3x - y = 6 \).
Step by step solution
01
Find the derivative
To find the derivative, which gives the slope of the tangent line, we differentiate the function. The function is given by \( y = f(x) = 2x^4 - 5x \). The derivative \( f'(x) \) is calculated as follows: \[ f'(x) = \frac{d}{dx}(2x^4 - 5x) = 8x^3 - 5. \]
02
Evaluate the derivative at the point
Now, we need to find the slope of the tangent line at \( x = 1 \). Substitute \( x = 1 \) into the derivative: \[ f'(1) = 8(1)^3 - 5 = 8 - 5 = 3. \]The slope of the tangent line at \( x = 1 \) is 3.
03
Find the y-coordinate of the point
Substitute \( x = 1 \) into the original function to find the y-coordinate of the point:\[ y = 2(1)^4 - 5(1) = 2 - 5 = -3. \]The point is \( (1, -3) \).
04
Use point-slope form to find the equation of the tangent line
With the slope from Step 2, and the point from Step 3 \( (1, -3) \), use the point-slope form of a line: \[ y - y_1 = m(x - x_1) \]where \( m = 3 \), \( x_1 = 1 \), and \( y_1 = -3 \):\[ y + 3 = 3(x - 1). \]
05
Convert the equation to standard form
Simplify the equation from Step 4 and convert it to the standard form by expanding and rearranging:\[ y + 3 = 3x - 3 \]\[ y = 3x - 6 \]Write it in standard form (Ax + By = C):\[ 3x - y = 6. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
The derivative is a fundamental concept in calculus that helps us understand how a function changes at any given point. Simply put, it measures the rate at which a function's output value changes concerning changes in its input value. When we talk about the tangent line to a curve, its slope at any point is given by the derivative.
To find the derivative of a function, we apply the rules of differentiation. In the context of our exercise, the function is given by \( y = 2x^4 - 5x \). Differentiating this function with respect to \( x \) gives us the derivative \( f'(x) = 8x^3 - 5 \).
Let's break down why knowing this derivative helps in finding the tangent line:
To find the derivative of a function, we apply the rules of differentiation. In the context of our exercise, the function is given by \( y = 2x^4 - 5x \). Differentiating this function with respect to \( x \) gives us the derivative \( f'(x) = 8x^3 - 5 \).
Let's break down why knowing this derivative helps in finding the tangent line:
- The derivative tells us the exact steepness or slope of the curve at any point.
- For the tangent line at \( x = 1 \), we used the derivative to find \( f'(1) = 3 \), meaning the slope here is 3.
Point-Slope Form
The point-slope form is a valuable tool for writing the equation of a line when you're given a point on the line and the slope. It puts the complexity of a line equation into a manageable format. The general form of the point-slope equation is:
\[ y - y_1 = m(x - x_1) \]
Here:
\[ y + 3 = 3(x - 1) \]
This format is particularly handy because:
\[ y - y_1 = m(x - x_1) \]
Here:
- \( m \) is the slope of the line.
- \( (x_1, y_1) \) is the point through which the line passes.
\[ y + 3 = 3(x - 1) \]
This format is particularly handy because:
- It clearly shows the slope and how the y-value changes as we move along the x-axis from the specific point \( (x_1, y_1) \).
- Provides a straightforward method to convert into other forms like the standard form.
Standard Form of a Line
The standard form of a line equation is a formal way of writing linear equations that has the format \( Ax + By = C \). Here, \( A \), \( B \), and \( C \) are integers, where \( A \) and \( B \) should not both be zero simultaneously.
Changing from point-slope to standard form helps present the equation in a neat and organized style, often preferred in mathematical and geometric scenarios. From the previous point-slope equation:
\[ y + 3 = 3(x - 1) \]
We expand and rearrange to simplify:
Changing from point-slope to standard form helps present the equation in a neat and organized style, often preferred in mathematical and geometric scenarios. From the previous point-slope equation:
\[ y + 3 = 3(x - 1) \]
We expand and rearrange to simplify:
- First distribute: \( y + 3 = 3x - 3 \).
- Move all terms to one side to form: \( 3x - y = 6 \).
- Makes it easy to quickly identify and compare lines and their intercepts.
- Useful in solutions that require precise, integer-based calculations, such as certain graphing techniques or when integrating algebra problems.