Chapter 4: Problem 31
Differentiate the functions in Problems 1-52 with respect to the independent variable. $$ f(x)=-3 e^{x^{2}+\tan x} $$
Short Answer
Expert verified
The derivative is \( f'(x) = -6xe^{x^2 + \tan x} - 3\sec^2 xe^{x^2 + \tan x} \).
Step by step solution
01
Identify the Function Type
The function is an exponential function where the base is the constant \( e \) and the exponent is \( x^2 + \tan x \). The function is given by \( f(x) = -3e^{x^2 + \tan x} \).
02
Apply the Exponential Function Derivative Rule
Recall that the derivative of \( e^u \) with respect to \( x \) is \( e^u \cdot \frac{du}{dx} \), where \( u \) is a function of \( x \). Here, \( u = x^2 + \tan x \).
03
Differentiate the Exponent
Differentiate the exponent \( x^2 + \tan x \) with respect to \( x \). This gives \( \frac{d}{dx}(x^2) = 2x \) and \( \frac{d}{dx}(\tan x) = \sec^2 x \).
04
Combine the Derivatives
The derivative of the exponent \( u \) is \( \frac{du}{dx} = 2x + \sec^2 x \).
05
Differentiate the Function
Using the derivative rule from Step 2, the derivative of \( f(x) = -3e^{x^2 + \tan x} \) is: \[ f'(x) = -3e^{x^2 + \tan x} \cdot (2x + \sec^2 x) \].
06
Simplify the Expression
Distribute the \( -3 \) across the terms inside the parentheses: \[ f'(x) = -3(2x + \sec^2 x)e^{x^2 + \tan x} = -6xe^{x^2 + \tan x} - 3\sec^2 xe^{x^2 + \tan x} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Function
An exponential function is a type of mathematical expression where a constant base is raised to a variable exponent. In our exercise, the base is the mathematical constant \( e \), approximately equal to 2.71828. Exponential functions are characterized by their rapid growth or decay, depending on the sign of the exponent.
- Standard form: \( e^x \)
- Our function: \( f(x) = -3e^{x^2 + \tan x} \)
Derivative Rules
Derivative rules simplify the process of finding the derivative of a function, telling us the rate of change. The main rule we use here is for exponential functions:
- The derivative of \( e^u \) is \( e^u \cdot \frac{du}{dx} \) where \( u \) is a function of \( x \).
Chain Rule
The chain rule is a fundamental technique in calculus used for differentiating composite functions. It states that if a function \( y = g(f(x)) \) is composed of two functions \( f(x) \) and \( g(u) \), then its derivative with respect to \( x \) is:
- \( \frac{dy}{dx} = g'(u) \cdot f'(x) \)
Differentiation Steps
Differentiating a complex function requires systematically applying calculus rules in a sequence of steps. Here is a concise breakdown of our problem:1. **Identify and express components**: We identify \( f(x) = -3e^{x^2 + \tan x} \).2. **Differentiate the inner function**: \( \frac{du}{dx} = 2x + \sec^2 x \) as the derivative of \( x^2 + \tan x \).3. **Apply the exponential function rule**: The derivative rule gives us \( -3e^{x^2 + \tan x} \cdot (2x + \sec^2 x) \).4. **Simplify the result**: Simplifying leads to \( -6xe^{x^2 + \tan x} - 3\sec^2 xe^{x^2 + \tan x} \).Systematically following these differentiation steps helps in tackling derivatives step by step, ensuring nothing is overlooked.