Chapter 4: Problem 26
Use the formal definition to find the derivative of $$ f(x)=\frac{1}{x+1} $$
Short Answer
Expert verified
The derivative of \( f(x) = \frac{1}{x+1} \) is \( f'(x) = \frac{-1}{(x+1)^2} \).
Step by step solution
01
Understand the Formal Definition of a Derivative
The formal definition of a derivative of a function \( f(x) \) at a point \( x = a \) is given by \( f'(a) = \lim_{{h \to 0}} \frac{{f(a + h) - f(a)}}{h} \). In this case, our function is \( f(x) = \frac{1}{x+1} \) and we want to find \( f'(x) \).
02
Substitute the Function into the Derivative Formula
Substitute \( f(x) = \frac{1}{x+1} \) into the derivative formula to find \( f'(x) \). Thus, \( f'(x) = \lim_{{h \to 0}} \frac{{f(x + h) - f(x)}}{h} = \lim_{{h \to 0}} \frac{{\frac{1}{x+h+1} - \frac{1}{x+1}}}{h} \).
03
Simplify the Expression
To simplify, find a common denominator for \( \frac{1}{x+h+1} - \frac{1}{x+1} \). The common denominator is \( (x+h+1)(x+1) \). Thus, \( \frac{1}{x+h+1} - \frac{1}{x+1} = \frac{x+1 - (x+h+1)}{(x+h+1)(x+1)} = \frac{-h}{(x+h+1)(x+1)} \).
04
Simplify the Derivative Expression Further
Substitute the simplified difference into the limit expression: \( f'(x) = \lim_{{h \to 0}} \frac{-h}{h (x+h+1)(x+1)} \). Simplify the fraction by canceling \( h \) from the numerator and the denominator, which results in \( f'(x) = \lim_{{h \to 0}} \frac{-1}{(x+h+1)(x+1)} \).
05
Evaluate the Limit
Now, evaluate the limit as \( h \) approaches zero: \( f'(x) = \lim_{{h \to 0}} \frac{-1}{(x+h+1)(x+1)} = \frac{-1}{(x+1)^2} \). Thus, the derivative is \( f'(x) = \frac{-1}{(x+1)^2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Formal Definition of a Derivative
The formal definition of a derivative is a fundamental concept in calculus that helps us understand how a function changes at any given point. It is expressed as:
- \( f'(a) = \lim_{{h \to 0}} \frac{{f(a + h) - f(a)}}{h} \)
Limit Process
When calculating a derivative using the formal definition, the limit process is essential. The idea is to consider what happens as the difference between two points on the function, \( h \), becomes very small, approaching zero. In our context, this means calculating:
- \( \lim_{{h \to 0}} \frac{{\frac{1}{x+h+1} - \frac{1}{x+1}}}{h} \)
Simplifying Expressions
Simplifying mathematical expressions is crucial in calculations involving the derivative, as it makes the problem easier to solve. For our given function \( f(x) = \frac{1}{x+1} \), we initially have the expression:
- \( \frac{{\frac{1}{x+h+1} - \frac{1}{x+1}}}{h} \)
- \( \frac{-h}{(x+h+1)(x+1)} \)