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Approximate \(f(x)\) at a by the linear approximation $$L(x)=f(a)+f^{\prime}(a)(x-a)$$ $$ f(x)=\frac{1}{(1+x)^{2}} \text { at } a=0 $$

Short Answer

Expert verified
The linear approximation of \( f(x) \) at \( a=0 \) is \( L(x) = 1 - 2x \).

Step by step solution

01

Identify given function and point

We are given the function \( f(x) = \frac{1}{(1+x)^2} \) and we are asked to find the linear approximation at the point \( a = 0 \). The goal is to approximate \( f(x) \) near \( x = 0 \) using the linear approximation formula.
02

Evaluate \( f(a) \)

Calculate the value of the function at \( x = a = 0 \).\[f(a) = f(0) = \frac{1}{(1+0)^2} = 1\]
03

Find the derivative \( f'(x) \)

Differentiate the given function. Using the chain rule, we have:\[f'(x) = \frac{d}{dx} \left( (1+x)^{-2} \right) = -2(1+x)^{-3}\]
04

Evaluate \( f'(a) \)

Calculate the derivative at \( x = a = 0 \).\[f'(0) = -2(1+0)^{-3} = -2\]
05

Apply linear approximation formula

Substitute the values of \( f(a) \) and \( f'(a) \) into the linear approximation formula:\[L(x) = f(a) + f'(a)(x-a) = 1 + (-2)(x-0) = 1 - 2x\]
06

Write the final linear approximation

We find that the linear approximation of \( f(x) \) at \( a = 0 \) is:\[L(x) = 1 - 2x\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Derivatives
A derivative is a mathematical concept that represents the rate at which a function changes at any point. It provides a way to analyze how a function's output varies as the input changes by an infinitesimally small amount. In this exercise, we are interested in the derivative of the function \( f(x) = \frac{1}{(1+x)^2} \), which tells us how quickly \( f(x) \) is changing around a specific point.
  • The derivative can be thought of as the slope of the tangent line to the function at a given point.
  • It is symbolized as \( f'(x) \) or \( \frac{df}{dx} \), indicating that it is a function of the input variable \( x \).
By finding the derivative at \( a = 0 \), we are determining the slope of the tangent line to \( f(x) \) at this point, which helps us create the linear approximation. This approximation, \( L(x) = 1 - 2x \), is an excellent way to estimate function values close to \( x = 0 \).
The Chain Rule
The chain rule is an essential technique in differentiation, especially when dealing with composite functions like \( f(x) = \frac{1}{(1+x)^2} \). It allows us to find the derivative of a function composed of two or more simpler functions.
To use the chain rule, we identify two functions, an "outer" function and an "inner" function. Here:
  • The outer function is \( u^{-2} \) where \( u = 1+x \).
  • The inner function is \( 1+x \).
Using the chain rule involves differentiating the outer function with respect to the inner function, and then multiplying by the derivative of the inner function:\[ \frac{d}{dx} (1+x)^{-2} = -2(1+x)^{-3} \times 1 = -2(1+x)^{-3} \]This step is crucial for determining \( f'(x) \), enabling us to find the linear approximation.
Differentiation Process
Differentiation is the process of finding the derivative of a function. It is a fundamental operation in calculus used to study how functions change. The linear approximation technique requires differentiation to approximate function values near a specific point, helping us develop an understanding of more complex behaviors through simpler linear models.
In this exercise, we differentiated the function \( f(x) = \frac{1}{(1+x)^2} \) by applying rules of differentiation such as:
  • Power Rule: Used to handle the form \( (1+x)^{-2} \).
  • Chain Rule: As previously explained, applies to composite functions.
These rules work together to give us the derivative, \( f'(x) = -2(1+x)^{-3} \). By evaluating this derivative at \( a = 0 \), we can effectively apply it in the linear approximation formula, ultimately achieving a simpler expression that estimates the behavior of the original function around the given point.

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