Chapter 4: Problem 12
In Problems \(1-58\), find the derivative with respect to the independent variable. $$ f(x)=\cot (2-3 x) $$
Short Answer
Expert verified
The derivative is \( 3\csc^2(2 - 3x) \).
Step by step solution
01
Recall the Derivative of Cotangent Function
The derivative of the cotangent function is given by the formula \( \frac{d}{dx}[\cot(u)] = -\csc^2(u) \cdot \frac{du}{dx} \), where \( u \) is an expression dependent on \( x \). We will use this formula to find the derivative.
02
Identify the Inner Function
For the function \( f(x) = \cot(2 - 3x) \), the inner function \( u \) is \( u = 2 - 3x \). We next need to find the derivative of this inner function with respect to \( x \).
03
Differentiate the Inner Function
The derivative of \( u = 2 - 3x \) with respect to \( x \) is \( \frac{du}{dx} = \frac{d}{dx}[2 - 3x] = -3 \).
04
Apply the Chain Rule
Using the derivative formula for the cotangent, we substitute \( u = 2 - 3x \) and \( \frac{du}{dx} = -3 \): \[\frac{d}{dx}[\cot(2 - 3x)] = -\csc^2(2 - 3x) \cdot (-3) = 3\csc^2(2 - 3x). \]
05
Write the Final Result
Putting it all together, the derivative of \( f(x) = \cot(2 - 3x) \) with respect to \( x \) is \( 3\csc^2(2 - 3x) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The Chain Rule is a crucial tool in calculus for finding derivatives of composite functions. Suppose a function is defined as \( f(g(x)) \), where \( f \) is an outer function and \( g \) is an inner function. The Chain Rule states that the derivative of \( f(g(x)) \) with respect to \( x \) is given by the product of the derivative of \( f \) with respect to \( g \), and the derivative of \( g \) with respect to \( x \): \[ \frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x) \]
- Outer Function: This is the function on the outside; in this case, \( \cot(u) \).
- Inner Function: This is the expression inside the outer function; for this example, \( u = 2 - 3x \).
Trigonometric functions
Trigonometric functions are fundamental in calculus and often appear in differentiation exercises. Functions like sine and cosine have their derivatives memorized due to their frequent usage in problems:
Understanding these formulas enables you to differentiate faster and tackle more complex expressions with confidence.
- The derivative of \( \sin(x) \) is \( \cos(x) \).
- The derivative of \( \cos(x) \) is \( -\sin(x) \).
- For the cotangent function, the derivative is \( -\csc^2(x) \).
Understanding these formulas enables you to differentiate faster and tackle more complex expressions with confidence.
Differentiation techniques
Differentiation is the process of finding a function's derivative, which reveals the rate of change. There are several rules and techniques to keep in mind depending on the type of function:
- Power Rule: Differentiates power functions. For \( x^n \), the derivative is \( n \times x^{n-1} \).
- Product Rule: Useful for the product of two functions \( u(x) \) and \( v(x) \). The derivative is \( u'v + uv' \).
- Quotient Rule: For the quotient of two functions \( u \div v \), use \( (u'v - uv')/v^2 \).
- Chain Rule: Essential for functions within other functions, as explained above.