Chapter 3: Problem 4
In Problems 1-4, show that each function is continuous at the given value. $$ f(x)=x^{2}+1, c=-1 $$
Short Answer
Expert verified
Function \( f(x) = x^2 + 1 \) is continuous at \( x = -1 \).
Step by step solution
01
Understand the Definition of Continuity
A function \( f(x) \) is continuous at a point \( c \) if three conditions are met: (1) \( f(c) \) is defined, (2) \( \lim_{{x \to c}} f(x) \) exists, and (3) \( \lim_{{x \to c}} f(x) = f(c) \). We need to verify these conditions for the function \( f(x) = x^2 + 1 \) at \( c = -1 \).
02
Check Whether the Function is Defined at \( c \)
Calculate \( f(-1) \). Substitute \( x = -1 \) into the function: \[ f(-1) = (-1)^2 + 1 = 1 + 1 = 2 \]. Since \( f(-1) = 2 \), \( f(x) \) is defined at \( x = -1 \).
03
Calculate the Limit of the Function as \( x \) Approaches \( c \)
Now, find the limit \( \lim_{{x \to -1}} f(x) \) using the same expression: \[ \lim_{{x \to -1}} (x^2 + 1) = (-1)^2 + 1 = 2 \]. This shows that the limit exists and is equal to 2.
04
Compare the Limit to the Function Value at \( c \)
Now confirm that \( \lim_{{x \to -1}} f(x) = f(-1) \). We found that both the limit and the function value are 2, i.e., \[ \lim_{{x \to -1}} f(x) = 2 = f(-1) \].
05
Conclusion on Continuity
Since all conditions of continuity are satisfied: \( f(-1) \) is defined, \( \lim_{{x \to -1}} f(x) \) exists and equals 2, and \( \lim_{{x \to -1}} f(x) = f(-1) \), the function \( f(x) = x^2 + 1 \) is continuous at \( x = -1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit of a Function
The concept of the limit of a function is essential in calculus and helps us understand the behavior of functions as the input approaches a specific value. In simpler terms, when we talk about the limit of a function, we are asking what happens to the value of the function as we get closer and closer to a certain point on the x-axis.
To determine the limit of a function, say for the function \( f(x) = x^2 + 1 \) as \( x \) approaches \( -1 \), we calculate how \( f(x) \) behaves as \( x \) gets very close to \( -1 \). We substitute values closer and closer to \( -1 \) and observe the trend of the function's output. If our calculated limit approaches a real number, we say that the limit exists.
For the given exercise, the limit was found to be 2 when \( x \) approaches \( -1 \). This tells us that as \( x \) gets infinitesimally close to \( -1 \), the value of \( f(x) \) nears 2. It is crucial for the limit to exist to consider whether a function is continuous at a point.
To determine the limit of a function, say for the function \( f(x) = x^2 + 1 \) as \( x \) approaches \( -1 \), we calculate how \( f(x) \) behaves as \( x \) gets very close to \( -1 \). We substitute values closer and closer to \( -1 \) and observe the trend of the function's output. If our calculated limit approaches a real number, we say that the limit exists.
For the given exercise, the limit was found to be 2 when \( x \) approaches \( -1 \). This tells us that as \( x \) gets infinitesimally close to \( -1 \), the value of \( f(x) \) nears 2. It is crucial for the limit to exist to consider whether a function is continuous at a point.
Function Evaluation
Function evaluation is the process through which we find the output of a function for a specific input value. This is typically done by substituting the input value into the function's formula.
For the function \( f(x) = x^2 + 1 \), evaluating the function at \( x = -1 \) means substituting \( -1 \) into the function, resulting in:
For the function \( f(x) = x^2 + 1 \), evaluating the function at \( x = -1 \) means substituting \( -1 \) into the function, resulting in:
- \( f(-1) = (-1)^2 + 1 \)
- \( f(-1) = 1 + 1 \)
- \( f(-1) = 2 \)
Polynomial Functions
Polynomial functions are sums of terms consisting of a variable raised to an exponent and multiplied by a coefficient. These functions are of the form \( f(x) = a_n x^n + a_{n-1} x^{n-1} + \, ... \, + a_1 x + a_0 \). For our function, \( f(x) = x^2 + 1 \), it is a simple polynomial of degree 2, often referred to as a quadratic function.
Polynomial functions, like \( f(x) = x^2 + 1 \), have many interesting properties:
Polynomial functions, like \( f(x) = x^2 + 1 \), have many interesting properties:
- They are smooth and continuous over all real numbers.
- They do not have any gaps, jumps, or infinite oscillations.
- They have a predictable behavior and can easily be evaluated for derivatives and integrals.