Chapter 11: Problem 5
Use the graphical approach to classify the following Lotka-Volterra models of interspecific competition according to "coexistence," "founder control," "species 1 excludes species 2," or "species 2 excludes species 1." \(\frac{d N_{1}}{d t}=N_{1}\left(1-\frac{N_{1}}{20}-\frac{N_{2}}{5}\right)\) \(\frac{d N_{2}}{d t}=2 N_{2}\left(1-\frac{N_{2}}{15}-\frac{N_{1}}{3}\right)\)
Short Answer
Step by step solution
Identify the Carrying Capacities
Determine the Zero-Growth Isoclines
Graph the Isoclines on a Coordinate Plane
Analyze the Feasibility of the Equilibrium Points
Classify Based on Graphical Interactions
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interspecific Competition
- A higher value indicates more intense competition.
- The coefficients beside population sizes in the differential equations represent the strength of competition.
Zero-Growth Isoclines
- For species 1, the isocline is where the rate of change is zero, expressed as: \( N_{1} = 20 - 4N_{2} \).
- The same goes for species 2: \( N_{2} = 15 - 0.75N_{1} \).
Carrying Capacity
For the Lotka-Volterra interspecific competition model, carrying capacities are derived from setting the rate of change \( \frac{dN}{dt} = 0 \) while assuming no interspecies competition. In our example:
- Species 1 has a carrying capacity of 20.
- Species 2 has a carrying capacity of 15.
Equilibrium Points
In the context of our Lotka-Volterra model, finding this equilibrium involves solving the system of equations provided by the zero-growth isoclines:
- The intersection of the isoclines determines where equilibrium may occur.
- The point is feasible when it yields positive population sizes for both species.