/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 A solution of $$ \frac{\part... [FREE SOLUTION] | 91Ó°ÊÓ

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A solution of $$ \frac{\partial c(x, t)}{\partial t}=D \frac{\partial^{2} c(x, t)}{\partial x^{2}} $$ is the function $$ c(x, t)=\frac{1}{\sqrt{4 \pi D t}} \exp \left[-\frac{x^{2}}{4 D t}\right] $$ for \(x \in \mathbf{R}\) and \(t>0\). (a) Show that, as a function of \(x\) for fixed values of \(t>0, c(x, t)\) is (i) positive for all \(x \in \mathbf{R}\), (ii) is increasing for \(x<0\) and decreasing for \(x>0\), (iii) has a local maximum at \(x=0\), and (iv) has inflection points at \(x=\pm \sqrt{2 D t}\). (b) Graph \(c(x, t)\) as a function of \(x\) when \(D=1\) for \(t=0.01\), \(t=0.1\), and \(t=1\).

Short Answer

Expert verified
c(x, t) is positive, increases for x<0 and decreases for x>0, peaks at x=0, has inflection at x=±√(2Dt). Graph shows diffusion over time.

Step by step solution

01

Show c(x, t) is Positive for All x

To prove that the function \(c(x, t)\) is positive for any \(x\in \mathbf{R}\) and \(t>0\), we note that \(\exp[-\frac{x^2}{4Dt}]\) is an exponential function which is always positive. Also, \(\frac{1}{\sqrt{4\pi Dt}}\) is positive because \(t>0\) and \(D>0\). Therefore, the product of positive terms yields a positive value for any \(x\).
02

Show c(x, t) is Increasing for x0

To determine where \(c(x, t)\) is increasing or decreasing, find \(\frac{\partial c(x, t)}{\partial x}\). The derivative is:\[ \frac{\partial c}{\partial x} = \frac{1}{\sqrt{4\pi Dt}} \cdot \frac{-x}{2Dt} \cdot \exp\left[-\frac{x^2}{4Dt}\right] = -\frac{x}{2Dt} c(x, t) \]For \(x<0\), \(\frac{\partial c}{\partial x}>0\), making \(c(x, t)\) increasing. For \(x>0\), \(\frac{\partial c}{\partial x}<0\), making \(c(x, t)\) decreasing.
03

Local Maximum at x=0

At \(x=0\), the derivative \(\frac{\partial c}{\partial x} = 0\), suggesting a critical point. For a local maximum, \(\frac{\partial^2 c}{\partial x^2}\) should be negative at this point. Based on the expression obtained for the first derivative, the second derivative analysis for sign shows that \(\frac{\partial^2 c}{\partial x^2}\) is indeed negative at \(x=0\), confirming a local maximum.
04

Inflection Points at x=±√(2Dt)

Inflection points occur where \(\frac{\partial^2 c}{\partial x^2} = 0\). Further differentiate \(\frac{\partial c}{\partial x}\) to find \(\frac{\partial^2 c}{\partial x^2}\), and set it to zero:\[ \frac{\partial^2 c}{\partial x^2} = c(x, t) \left( \frac{x^2 - 2Dt}{(2Dt)^2} \right) \]Solving \(\frac{\partial^2 c}{\partial x^2} = 0\) gives \(x = \pm \sqrt{2Dt}\). These are inflection points when the concavity changes.
05

Graphing c(x, t) for Various t Values

Use the values \(D=1\) and graph the function for the specified \(t\) values \(t=0.01, 0.1, 1\). For each \(t\), plot \(c(x, t) = \frac{1}{\sqrt{4\pi t}} \exp\left[-\frac{x^2}{4t}\right]\) against \(x\). Observe that as \(t\) increases, the peak of the graph becomes lower and wider, reflecting a diffusion process over time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Differential Equation
The equation \( \frac{\partial c(x, t)}{\partial t}=D \frac{\partial^{2} c(x, t)}{\partial x^{2}} \) is an example of a partial differential equation (PDE). PDEs involve unknown functions of multiple variables and their partial derivatives. This particular PDE is known as the heat equation, which models the distribution of heat (or variation in temperature) in a given region over time.

A key feature of PDEs is their ability to describe continuous systems and phenomena. They are widely used in fields like physics, engineering, and finance.
  • Variables: In this heat equation, \(c(x, t)\) is the temperature at point \(x\) and time \(t\).
  • Parameters: \(D\) is a constant that represents the diffusivity of the medium.
  • Nature: The equation shows how the rate of temperature change with respect to time (left side) is affected by the curvature of temperature in space (right side).
This kind of equation helps us predict how temperature evolves in space over time, essential for practical applications such as thermal engineering and climate modeling.
Gaussian Function
The function \( c(x, t)=\frac{1}{\sqrt{4 \pi D t}} \exp \left[-\frac{x^{2}}{4 D t}\right] \) is an example of a Gaussian function, which is characterized by its bell-shaped curve. Gaussian functions are extremely important in probability and statistics as they describe normal distributions.

The specific Gaussian in this problem is a solution to the heat equation, representing how heat diffuses over time starting from a point source. Important traits include:
  • Normalization: The prefactor \( \frac{1}{\sqrt{4 \pi D t}} \) ensures the total heat (area under the curve) remains constant.
  • Exponent: The term \( \exp \left[-\frac{x^2}{4 D t}\right] \) ensures the concentration decreases with distance \(x\) from the origin, but gets spread out over time \(t\).
  • Symmetry: The function is symmetric around \(x=0\), showing equal diffusion in both directions from the source.
This function's properties make it very useful in modeling various physical processes beyond just heat, such as diffusion and signal processing.
Derivative
Derivatives are a fundamental tool in calculus used to determine how a function changes. When dealing with the function \( c(x, t) \), we look at its first derivative \( \frac{\partial c}{\partial x} \) and second derivative \( \frac{\partial^2 c}{\partial x^2} \) to understand the behavior of the solution.

Why derivatives are important:
  • First Derivative: The first derivative helps us identify where the function is increasing or decreasing. For \(c(x,t)\), we find that:
    • \(\frac{\partial c}{\partial x} = -\frac{x}{2Dt} c(x, t)\), which means the function increases for \(x < 0\) and decreases for \(x > 0\).
  • Second Derivative: The second derivative indicates the curvature or concavity of the function. This tells us about local maxima, minima, or inflection points:
    • \(\frac{\partial^2 c}{\partial x^2}\) is used to confirm that \(x=0\) is a local maximum and that inflection points occur where \(\frac{\partial^2 c}{\partial x^2} = 0\), at \(x = \pm \sqrt{2Dt}\).
In conclusion, derivatives help us fully describe how \(c(x, t)\) behaves at different points, vital for understanding the diffusion process.
Inflection Point
An inflection point is where the graph of a function changes concavity, shifting from concave up (convex) to concave down (concave) or vice versa. In the context of the function \( c(x, t) \), inflection points occur at \(x = \pm \sqrt{2Dt}\).

Understanding inflection points:
  • At these points, the second derivative \( \frac{\partial^2 c}{\partial x^2} \) equals zero, indicating a potential change in the graph's curvature.
  • For \(c(x, t)\), this tells us that the diffusion's intensity changes, transitioning from regions with negative (concave down) to positive curvature (concave up) and vice versa.
  • These points are crucial in understanding how quantities like concentration spread out over time, showing areas where spreading speeds change.
Inflection points are useful in analyzing the balance and stability of processes such as heat diffusion. They provide insight into where transitions occur in the behavior of the function.

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Most popular questions from this chapter

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