Chapter 1: Problem 8
Determine the equation of the line that satisfies the stated requirements. Put the equation in standard form. The line passing through \((1,-2)\) with slope 2
Short Answer
Expert verified
The standard form of the line is \(2x - y = 4\).
Step by step solution
01
Understand the Problem
We need to find the equation of a line with a known slope that passes through a given point. We will put this equation in the standard form, which is generally written as \(Ax + By = C\).
02
Use Point-Slope Formula
Recall that the point-slope form of a line is \(y - y_1 = m(x - x_1)\), where \(m\) is the slope, and \((x_1, y_1)\) is the point the line passes through. For this problem, the slope \(m\) is 2, and the point is \((1, -2)\). Substitute these values into the formula.
03
Substitute Values into Point-Slope Formula
Substitute the slope \(m = 2\) and the point \((x_1, y_1) = (1, -2)\) into the point-slope formula: \[y - (-2) = 2(x - 1)\]Simplify this to get:\[y + 2 = 2x - 2\]
04
Convert to Standard Form
The standard form of a line is \(Ax + By = C\). Start by simplifying \(y + 2 = 2x - 2\) to convert it:\[y = 2x - 4\]Subtract \(2x\) from both sides to rearrange terms:\[-2x + y = -4\]Multiply the entire equation by -1 to ensure \(A\) is positive:\[2x - y = 4\]Now, the equation is in standard form.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
In algebra, understanding the different forms of a line's equation is pivotal in analyzing linear relationships. One such form is the point-slope form, useful in constructing an equation when you're given a point and a slope. This form is expressed as:\[ y - y_1 = m(x - x_1) \]In this equation, \( m \) represents the slope, and \( (x_1, y_1) \) is a specific point on the line.
The point-slope form is particularly handy because it directly incorporates both a point and the slope to begin constructing the line's equation.
The point-slope form is particularly handy because it directly incorporates both a point and the slope to begin constructing the line's equation.
- The slope, \( m \), tells us how steep the line is.
- The point \((x_1, y_1)\) ensures that the line passes through a specific location on the graph.
Slope
The slope is a crucial concept in understanding the characteristics of a line. It is essentially a measure of how a line inclines or declines on a graph. Mathematically, the slope is denoted by \( m \) and is calculated as the 'rise' over the 'run,' represented by the formula:\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]where \((x_1, y_1)\) and \((x_2, y_2)\) are any two points on the line.
The slope can be interpreted in several ways:
The slope can be interpreted in several ways:
- If \( m > 0 \), the line ascends as it moves from left to right.
- If \( m < 0 \), the line descends as it moves from left to right.
- If \( m = 0 \), the line is horizontal, indicating no vertical change as \( x \) increases.
Equation of a Line
In geometry and algebra, understanding the different forms of a line's equation helps interpret the line's behavior on a graph. One common form is the standard form, but initially, lines are often expressed in point-slope or slope-intercept forms before converting.The conversion process begins with simplifying the equation originated from the point-slope or slope-intercept form. After arranging terms, the equation can transition into the standard form:\[ Ax + By = C \]Here, \( A \), \( B \), and \( C \) are integers, with \( A \) typically being positive.
To convert to standard form:
To convert to standard form:
- Begin with isolating terms involving \( y \) and \( x \) on different sides.
- Adjust the equation, multiplying as necessary, to ensure \( A \) is positive.