/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Explain how the following functi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain how the following functions can be obtained from \(y=\cos x\) by basic transformations: (a) \(y=1+2 \cos x\) (b) \(y=-\cos \left(x+\frac{\pi}{4}\right)\) (c) \(y=-\cos \left(\frac{\pi}{2}-x\right)\)

Short Answer

Expert verified
(a) Stretch by 2 and shift up by 1; (b) Reflect and shift left by \(\frac{\pi}{4}\); (c) Convert using angle identity and reflect.

Step by step solution

01

Identify Vertical Stretch and Shift for (a)

The function given is \( y = 1 + 2 \cos x \). Start by identifying the transformations applied to \( y = \cos x \). Here, the \( 2 \) represents a vertical stretch by a factor of 2. The \( +1 \) indicates a vertical shift upwards by 1 unit. Therefore, you multiply the cosine function by 2 and then add 1 to the result.
02

Determine Reflections and Phase Shift for (b)

For \( y = -\cos \left(x+\frac{\pi}{4}\right) \), the negative sign indicates a reflection over the x-axis. The term \( x+\frac{\pi}{4} \) indicates a phase shift to the left by \( \frac{\pi}{4} \). Thus, the original cosine function is reflected and then shifted left.
03

Identify Complementary Angle Identity for (c)

Rewrite \( y = -\cos \left(\frac{\pi}{2}-x\right) \) using the complementary angle identity. Recall that \( \cos(\frac{\pi}{2}-x) = \sin(x) \), so the function becomes \( y = -\sin x \). Thus, \( y = \cos x \) is transformed by first converting \( \cos \) to \( \sin \) (due to the identity) and then reflecting over the x-axis due to the negative sign.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Stretch and Shift
A vertical stretch changes the amplitude of a function, making it taller or shorter. When you multiply a function by a number greater than 1, the graph stretches vertically by that factor. In the given function, \[ y = 1 + 2 \cos x \] The number 2 causes this vertical stretch. It multiplies the original cosine values, making the peaks and troughs twice as far from the x-axis as in the original function, \( y = \cos x \).Additionally, a vertical shift is when the entire graph moves up or down without changing its shape. Here, the "\(+1\)" indicates that the whole function is moved upward by 1 unit. This signifies that every point on the graph of \( y = 2\cos x \) is lifted up one unit on the y-axis.

Quick summary:
  • Multiply the amplitude (vertical stretch) by 2.
  • Shift the graph up by 1 unit (vertical shift).
Phase Shift
A phase shift refers to moving the graph of a function left or right. In the expression for horizontal shifts within a trigonometric function, \[ y = -\cos \left(x+\frac{\pi}{4}\right) \]The term inside the cosine function, "\(x + \frac{\pi}{4}\)", highlights a shift in the opposite direction of the sign. Since it is a "\(+\)" sign, it causes a leftward shift. Moving left by \(\frac{\pi}{4}\) means that features like peaks, troughs, and zero-crossings occur earlier on the graph.

There is also a reflection over the x-axis which flips the graph upside down. This is indicated by the negative sign in front of the cosine function. Together:
  • Reflect the graph over the x-axis.
  • Shift the entire graph to the left by \(\frac{\pi}{4}\).
Reflection Over X-Axis
Reflection over the x-axis results in flipping the graph. For trigonometric functions, a negative sign in front of the function causes any positive value to become negative and vice versa. Consider the transformation:\[ y = -\cos \left(\frac{\pi}{2}-x\right) \]Initially, you can use the complementary angle identity, \( \cos(\frac{\pi}{2}-x) = \sin(x) \), to rewrite it as:\[ y = -\sin x \]Here, the negative sign indicates a reflection of \( \sin x \) over the x-axis. This flips all the points on the graph as if you’re looking at it in a mirror held along the x-axis. What was above the x-axis is now below, and what was below is now above.

Key points about reflection:
  • Negative sign means the function is upside down.
  • It affects both cosine and sine functions the same way.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.