Chapter 1: Problem 16
Sketch the graph of each function. Do not use a graphing calculator. (Assume the largest possible domain.) $$ y=\ln (x-3) $$
Short Answer
Expert verified
The graph is defined for \( x > 3 \), approaches negative infinity as \( x \to 3^+ \), and rises indefinitely as \( x \) increases.
Step by step solution
01
Understand the Domain
The function given is \( y = \ln(x-3) \). The natural logarithm function \( \ln(x) \) is only defined for positive values of \( x \). Therefore, \( x-3 > 0 \). Solving this inequality gives \( x > 3 \). Thus, the domain of this function is \( (3, \infty) \).
02
Determine Key Points
Since the domain starts at \( x=3 \) (but does not include 3), we want to find key points by plugging in values greater than 3 into the function. For example, when \( x = 4 \), \( y = \ln(4-3) = \ln(1) = 0 \). When \( x = 5 \), \( y = \ln(5-3) = \ln(2) \approx 0.69 \). Calculating these will help to sketch the curve.
03
Analyze Behavioral Trends
As \( x \to 3^+ \) (from the right), \( x-3 \to 0^+ \), and thus \( y = \ln(x-3) \to -\infty \). As \( x \to \infty \), \( x-3 \to \infty \), so \( y = \ln(x-3) \to \infty \). This indicates a vertical asymptote at \( x = 3 \) and that the graph increases without bound as \( x \) increases.
04
Sketch the Graph
Using the information from previous steps, begin the graph at \( x=3 \) (without including it), heading upwards past the point \( (4, 0) \) and continuing to rise as \( x \) increases. The graph sharply approaches negative infinity near the vertical asymptote at \( x=3 \). These points and trends allow us to draw the rough shape of the function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of Function
The domain of a function refers to the set of all possible input values for which the function is defined. Understanding this for the function \( y = \ln(x-3) \) is crucial before any graph sketching. The natural logarithm function, \( \ln(x) \), is only defined for positive values. For our function, you should solve \( x-3 > 0 \) to find where it is defined. This leads us to \( x > 3 \). Therefore, the domain of this function is \( (3, \infty) \).
This means the function doesn't exist at \( x = 3 \) but starts immediately after it. When defining the domain:
This means the function doesn't exist at \( x = 3 \) but starts immediately after it. When defining the domain:
- The interval \( (3, \infty) \) indicates that as \( x \) starts just after 3, going all the way to infinity, the function is valid.
- This can be visualized on a number line as everything to the right of 3, excluding 3 itself.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a logarithm to the base \( e \). The number \( e \) (approximately 2.718) is a fundamental constant in mathematics, similar to the value of \( \pi \) for circles. The natural logarithm possesses unique properties:
The behavior of \( \ln(x-3) \) can be further analyzed:
- \( \ln(1) = 0 \)
- \( \ln(e) = 1 \)
The behavior of \( \ln(x-3) \) can be further analyzed:
- As \( x \) gets very close to 3, \( x-3 \) approaches zero from the positive side, meaning \( y = \ln(x-3) \to -\infty \). This illustrates how the graph swoops deeply as it nears the vertical line \( x=3 \).
- As \( x \) increases further beyond any limit, \( x-3 \) grows larger, leading \( y = \ln(x-3) \to \infty \). This depicts the ever-rising trend of the graph.
Asymptotes
Asymptotes are crucial lines that a graph approaches but never touches or crosses. In the graph of \( y = \ln(x-3) \), a vertical asymptote is present at \( x=3 \).
Here's what this means:
Here's what this means:
- As \( x \) approaches 3 from the right (but never actually reaches or crosses 3), the value of \( y \) sharply drops to \(-\infty\).
- This vertical asymptote acts like a boundary that the function will always strive towards indefinitely without actually meeting it. It implies that the graph will steeply rise or fall near this line.