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Explain why X-rays and ultraviolet light wavelengths are dangerous to living tissues. a. UV and X-rays are high energy waves that penetrate the tissues and damage cells. b. UV and X-rays are low energy waves that penetrate the tissues and damage cells. c. UV and X-rays cannot penetrate tissues and thus damage the cells. d. UV and X-rays can penetrate tissues and thus do not damage the cells.

Short Answer

Expert verified
a. UV and X-rays are high energy waves that penetrate the tissues and damage cells.

Step by step solution

01

Understand the properties of UV and X-rays

Ultraviolet (UV) and X-rays are part of the electromagnetic spectrum. Both types of radiation have higher energy compared to visible light.
02

Energy level of the waves

High energy waves, such as UV and X-rays, can penetrate living tissues effectively. This is due to their shorter wavelengths and higher frequency.
03

Effect on living tissues

When high energy waves such as UV and X-rays penetrate living tissues, they can ionize atoms and molecules within the cells. This ionization process can cause damage to the DNA and other critical components of the cells, leading to mutations, cell malfunction, or cell death.
04

Conclusion

Based on the facts that UV and X-rays are high energy waves and their ability to penetrate tissues and cause cellular damage, the correct answer is option a.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

electromagnetic spectrum
The electromagnetic spectrum is a collection of all types of electromagnetic waves arranged by wavelength and frequency. It ranges from long-wavelength radio waves to short-wavelength gamma rays. Each type of wave on the spectrum carries a different amount of energy.

Visible light, which we see every day, is a part of this spectrum. However, UV (ultraviolet) light and X-rays are also part of this spectrum, but they are invisible to the human eye because they have shorter wavelengths and higher frequencies. This higher energy allows them to penetrate living tissues more effectively than visible light. Understanding where UV and X-rays fit into the electromagnetic spectrum helps us appreciate their potential dangers.
high energy waves
High energy waves such as UV and X-rays have much shorter wavelengths and higher frequencies compared to visible light. This means they carry more energy, which enables them to penetrate deep into tissues.

The penetration ability of these high energy waves allows them to reach and interact with the molecules and cells inside the body. This is one reason why medical imaging like X-rays can show bones and other structures within the body. However, this same ability to penetrate deep into tissues also explains why these waves can cause harm by damaging cellular structures.
DNA damage
When UV and X-rays penetrate living tissues, they can ionize atoms and molecules in the cells. This ionization process means that electrons are stripped away from atoms or molecules, creating ions. These ions can then interact with other cellular components.

One of the most critical components at risk is DNA. UV and X-rays can cause direct damage to the DNA strands by breaking bonds, leading to mutations. These mutations can cause the cell to malfunction or die. In worst-case scenarios, prolonged or intense exposure can lead to serious health issues, such as cancer. This is why UV and X-ray exposure is tightly regulated in medical settings and why protective measures like sunscreen and lead aprons are used.

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Most popular questions from this chapter

Metabolic pathways both produce and use energy to perform their reactions. How does the Calvin cycle help to harness, store, and use energy in its pathway? a. The Calvin cycle harnesses energy in the form of 6 ATP and 6 NADPH that are used to produce Fructose- 3 - phosphate (F3P) molecules. These store the energy captured from photosynthesis. The cycle uses this energy to regenerate RuBP. b. The Calvin cycle harnesses energy in the form of 6 ATP and 6 NADPH that are used to produce Glyceraldehyde-3- phosphate (GA3P) molecules. These store the energy captured from photosynthesis. The cycle uses this energy to regenerate RuBP. c. The Calvin cycle harnesses energy in the form of 3 ATP and 3 NADPH that are used to produce Glyceraldehyde-3- phosphate (GA3P) molecules. These store the energy captured from photosynthesis. The cycle uses this energy to regenerate the RuBP. d. The Calvin cycle harnesses energy in the form of 6 ATP and 3 NADPH that are used to produce Glyceraldehyde-3- phosphate (GA3P) molecules. These store energy captured from photosynthesis. The cycle uses this energy to regenerate RuBP.

What cellular features and processes are similar in both photosynthesis and cellular respiration? a. Both processes are contained in organelles with single membranes, and both use a version of the cytochrome complex. b. Both processes are contained in organelles with double membranes, and neither use a version of the cytochrome complex. c. Both processes are contained in organelles with double membranes, and use a version of the cytochrome complex. d. Both processes are contained in organelles with single membranes, and neither use a version of the cytochrome complex.

What is the overall outcome of the light reactions in photosynthesis? a. NADPH and ATP molecules are produced during the light reactions and are used to power the light independent reactions. b. NADPH and ATP molecules are produced during the light reactions, which are used to power the light dependent reactions. c. Sugar and ATP are produced during the light reactions, which are used to power the light independent reactions. d. Carbon dioxide and NADPH are produced during the light reactions, which are used to power the light dependent reactions.

Why does it take three turns of the Calvin cycle to produce G3P, the initial product of photosynthesis? a. To fix enough carbon to export one G3P molecule. b. To fix enough oxygen to export one G3P molecule. c. To produce RuBisCO as an end product. d. To produce ATP and NADPH for fixation of G3P.

On a hot, dry day, plants close their stomata to conserve water. Explain the connection between the oxidation of water in photosystem II of the light- dependent reactions and the synthesis of glyceraldehyde-3-phosphate (G3PA) in the light-independent reactions. Predict the effect of closed stomata on the synthesis of G3PA and justify the prediction.

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