/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 Simple cuboidal epithelial cells... [FREE SOLUTION] | 91Ó°ÊÓ

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Simple cuboidal epithelial cells line the ducts of certain human exocrine glands. Various materials are transported into or out of the cells by diffusion. (The formula for the surface area of a cube is 6 × S2, and the formula for the volume of a cube is S3, where S = the length of a side of a cube.) Which of the following cubeshaped cells would be most efficient in removing waste by diffusion? a. 10 µm b. 20 µm c. 30 µm d. 40 µm

Short Answer

Expert verified
The 10 µm cell is the most efficient in removing waste by diffusion.

Step by step solution

01

Identify the surface area formula

The surface area of a cube is given by the formula: \[ \text{Surface Area} = 6 \times S^2 \] where \( S \) is the length of a side of the cube.
02

Identify the volume formula

The volume of a cube is given by the formula: \[ \text{Volume} = S^3 \] where \( S \) is the length of a side of the cube.
03

Calculate the surface area for each cell size

Calculate the surface area for each given side length: \( S = 10 \text{ µm} \) \[ \text{Surface Area} = 6 \times 10^2 = 600 \text{ µm}^2 \] \( S = 20 \text{ µm} \) \[ \text{Surface Area} = 6 \times 20^2 = 2400 \text{ µm}^2 \] \( S = 30 \text{ µm} \) \[ \text{Surface Area} = 6 \times 30^2 = 5400 \text{ µm}^2 \] \( S = 40 \text{ µm} \) \[ \text{Surface Area} = 6 \times 40^2 = 9600 \text{ µm}^2 \]
04

Calculate the volume for each cell size

Calculate the volume for each given side length: \( S = 10 \text{ µm} \) \[ \text{Volume} = 10^3 = 1000 \text{ µm}^3 \] \( S = 20 \text{ µm} \) \[ \text{Volume} = 20^3 = 8000 \text{ µm}^3 \] \( S = 30 \text{ µm} \) \[ \text{Volume} = 30^3 = 27000 \text{ µm}^3 \] \( S = 40 \text{ µm} \) \[ \text{Volume} = 40^3 = 64000 \text{ µm}^3 \]
05

Calculate the surface area-to-volume ratio for each cell size

Calculate the surface area-to-volume ratio for each side length: \( S = 10 \text{ µm} \) \[ \text{Ratio} = \frac{600 \text{ µm}^2}{1000 \text{ µm}^3} = 0.6 \] \( S = 20 \text{ µm} \) \[ \text{Ratio} = \frac{2400 \text{ µm}^2}{8000 \text{ µm}^3} = 0.3 \] \( S = 30 \text{ µm} \) \[ \text{Ratio} = \frac{5400 \text{ µm}^2}{27000 \text{ µm}^3} = 0.2 \] \( S = 40 \text{ µm} \) \[ \text{Ratio} = \frac{9600 \text{ µm}^2}{64000 \text{ µm}^3} = 0.15 \]
06

Determine the most efficient cell size for diffusion

Cells with a higher surface area-to-volume ratio are more efficient in removing waste by diffusion. Comparing the ratios calculated in Step 5, the cell with \( S = 10 \text{ µm} \) has the highest ratio of 0.6.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

surface area-to-volume ratio
Understanding the surface area-to-volume ratio is crucial for grasping how efficiently cells can exchange materials. This ratio compares a cell's surface area (how much of it is exposed to the environment) to its volume (how much it needs to support internally). For a cube, the formulas are: \[ \text{Surface Area} = 6 \times S^2 \ \text{Volume} = S^3 \] where \( S \) is the side length of the cube. Smaller cells have a higher surface area-to-volume ratio, meaning more surface area relative to their volume. This is vital for processes like diffusion because larger ratios allow for more efficient material exchange per unit of volume. For instance, a cell with a side length of 10 µm has a surface area-to-volume ratio of 0.6, while one with a side length of 40 µm has a ratio of only 0.15. Hence, smaller cells are typically more efficient in such exchanges.
diffusion
Diffusion is a passive transport method where molecules move from an area of higher concentration to an area of lower concentration. This process does not require energy and relies heavily on the surface area-to-volume ratio of cells. In smaller cells with a high ratio, diffusion occurs more efficiently because there's more surface area available for the molecules to pass through, relative to the cell's volume. For example, cuboidal epithelial cells in exocrine glands can efficiently remove waste due to their small size and high surface area-to-volume ratios. This efficient material exchange is essential for maintaining cellular function and overall tissue health.
exocrine glands
Exocrine glands play a pivotal role in secreting substances like enzymes, sweat, and saliva through ducts to various body surfaces. These glands are lined with simple cuboidal epithelial cells, which are well-suited for their secretory functions. The efficiency of these cells in material transport via diffusion is critical. Because these cells can be relatively small, they often have high surface area-to-volume ratios. This structural feature enables them to rapidly move waste products out and essential substances in, supporting the gland's overall function. An example is the pancreas, an exocrine gland that secretes digestive enzymes, relying on efficient cell activity for timely enzyme release.
cell biology
In cell biology, understanding the structure and function relationship is fundamental. Cells vary in shape, size, and structures, such as cuboidal epithelial cells, which line exocrine gland ducts. These cells adapt to their roles through structural features like high surface area-to-volume ratios. The smaller the cell, the higher this ratio, aiding in efficient diffusion for nutrient uptake and waste removal. This efficiency is vital for maintaining cellular health and functionality. For students, grasping these concepts helps in understanding how cells interact with their environment and maintain homeostasis, emphasizing the significance of cell size and shape in biological processes.

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Most popular questions from this chapter

Which of the following statements about digestion is true? a. Pepsin is converted to pepsinogen with the help of hydrochloric acid. b. Starch digestion begins in the mouth. c. Wave-like muscle movements called peristalsis move food from the stomach to the mouth. d. Amino acids are absorbed through the intestinal lining of the ileum.

In protein digestion, what happens in the stomach? a. Amino peptidase and dipeptidase break peptides into amino acids. b. Pepsin breaks proteins into peptides. c. Trypsin, elastase, and chymotrypsin break proteins into peptides. d. Carboxypeptidase breaks peptides into amino acids and peptides.

Explain how villi and microvilli aid in absorption. a. Villi and microvilli increase the surface area of the small intestines, which aids in the absorption of bile salts and vitamin B12. b. Villi and microvilli increase the surface area of the small intestine, which increases the absorption of nutrients by diffusion. c. Villi and microvilli form the inner layer of epithelial tissue in the small intestine and increase the absorption of nutrients from chyme. d. Villi and microvilli absorb food through the small intestine via smooth muscle contractions called peristalsis.

Certain organs control the release of hormones that have vital roles in digestion. Which of the following controls hunger and satiety signals? a. thymus b. adrenal cortex c. thyroid d. hypothalamus

Birds have several unique physical differences from other vertebrates, and several pertain to how birds process food. Some differences are obvious, such as the presence of a beak and no teeth, whereas other differences can be observed in their internal features. For example, birds have a monogastric digestive system like most other vertebrates, but their digestive system structure differs from that of most other monogastric vertebrates. Which of the following is true about how birds process food? a. Beak emergence coincided with insect inclusion in the bird diet. b. The gizzard is the primary site of mechanical digestion. c. Birds excrete nitrogenous waste and feces through separate openings. d. Birds digest plant material more slowly than ruminants.

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