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Imagine if there were 200 commonly occurring amino acids instead of 20. Given what you know about the genetic code, what would be the shortest possible codon length? Explain. a. Four b. Five c. Two d. Three

Short Answer

Expert verified
a. Four

Step by step solution

01

Understand the Genetic Code

The genetic code uses codons, which are sequences of nucleotides in RNA, to specify amino acids. Each codon is made up of a sequence of nucleotides.
02

Recognize the Four Nucleotides

There are four different nucleotides in RNA: adenine (A), cytosine (C), guanine (G), and uracil (U).
03

Calculate the Number of Combinations for Codons

To determine the number of potential codons for a given codon length, use the formula: \[ \text{Number of possible codons} = (\text{Number of nucleotides})^{\text{Codon length}} \]
04

Determine the Shortest Codon Length for 200 Amino Acids

Let's calculate the number of combinations for different codon lengths:- For codon length 2: \[ 4^2 = 16 \]- For codon length 3: \[ 4^3 = 64 \]- For codon length 4: \[ 4^4 = 256 \]- For codon length 5: \[ 4^5 = 1024 \]Clearly, codon length 4 is the minimum length that gives at least 200 possible combinations.
05

Conclude the Answer

The shortest possible codon length that allows for at least 200 different amino acids is 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

codon length
The concept of codon length is essential to understanding how genetic information is translated into proteins. Codons are sequences of nucleotides in RNA that determine which amino acid will be added next during protein synthesis.
  • A codon consists of a specific sequence of nucleotides.
  • Typically, a codon is made up of three nucleotides, but this can vary depending on the number of amino acids that need to be encoded.

  • To calculate the total number of possible codons for a given codon length, use the formula: \ \[ \text{Number of possible codons} = (\text{Number of nucleotides})^{\text{Codon length}} \ \]
    This formula allows us to see how increasing the length of the codon can exponentially increase the number of possible combinations. For example, if there were 200 amino acids instead of 20, a minimum codon length of four nucleotides would be necessary because \ \[ 4^4 = 256 \ \]. This ensures that there are enough unique codons to represent each amino acid uniquely.
RNA nucleotides
RNA nucleotides are the building blocks of RNA, which include adenine (A), cytosine (C), guanine (G), and uracil (U). These four nucleotides pair up to form the sequences that make up codons.
  • Adenine (A) pairs with uracil (U)
  • Cytosine (C) pairs with guanine (G)

Each codon in RNA is composed of a set of three nucleotides that corresponds to a specific amino acid. The structure and pairing of these nucleotides are crucial because any changes can lead to different amino acids being encoded. Given four nucleotides, if the codon length is three, the number of possible codons is \ \[ 4^3 = 64 \ \], which is more than enough for 20 amino acids. However, for 200 amino acids, you would need longer codon sequences.

The redundancy in the genetic code means that multiple codons can code for the same amino acid, which provides a buffer against mutations that might otherwise result in harmful changes to proteins.
amino acids
Amino acids are the building blocks of proteins and play numerous roles in the structure and function of cells. Proteins are formed by amino acids linked together in specific sequences determined by the genetic code.
There are 20 common amino acids found in most organisms, but in this exercise, we imagine there being 200.
  • Amino acids consist of a central carbon atom, an amino group, a carboxyl group, and a unique side chain that determines its properties.
  • The side chains of amino acids can be positively charged, negatively charged, polar, or nonpolar, affecting how they interact with other molecules.

Given 200 amino acids, the complexity of the genetic code would increase significantly. Codons would need to be longer to provide enough unique combinations. Typically, three-nucleotide codons are sufficient for 20 amino acids, but for 200, a four-nucleotide codon would be the minimum required to cover all possible amino acids, as it provides \ \[ 4^4 = 256 \ \] unique combinations.
This ensures that each amino acid can be translated from its respective codon without confusion, allowing proteins to be constructed accurately.

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Most popular questions from this chapter

If mRNA is complementary to the DNA template strand and the DNA template stand is complementary to the DNA non-template strand, why are base sequences of mRNA and the DNA non- template strand not identical? Could they ever be? a. No, they cannot be identical because the T nucleotide in DNA is replaced with U nucleotide in RNA and AUG is the start codon. b. No, they cannot be identical because the T nucleotide in RNA is replaced with U nucleotide in DNA. c. They can be identical if methylation of the U nucleotide in RNA occurs and gives T nucleotide. d. They can be identical if de-methylation of the U nucleotide in RNA occurs and gives T nucleotide.

Explain the initiation of transcription in prokaryotes. Include all proteins involved. a. In prokaryotes the polymerase is composed of five polypeptide subunits, two of which are identical. Four of these subunits, denoted \(\alpha, \alpha\),\(\beta,\) and \(\beta^{\prime}\) comprise the polymerase core enzyme. The fifth subunit, \(\sigma\), involved only in transcription initiation. The polymerase comprised of all five subunits is called the holoenzyme. b. In prokaryotes the polymerase is composed of four polypeptide subunits, two of which are identical. These subunits, denoted \(\alpha, \alpha\),\(\beta,\) and \(\beta^{\prime}\) comprise the polymerase core enzyme. There is a fifth subunit that is involved in translation initiation. The polymerase comprised of all four subunits is called the holoenzyme. c. In prokaryotes the polymerase is composed of five polypeptide subunits, two of which are identical. Four of these subunits, denoted \(\alpha, \alpha\),\(\beta,\) and \(\beta^{\prime}\) comprise the polymerase holoenzyme. The fifth subunit, \(\sigma\), is involved only in transcription initiation. The polymerase comprised of all five subunits is called the core enzyme. d. In prokaryotes the polymerase is composed of five polypeptide subunits, two of which are identical. Four of these subunits, denoted \(\alpha, \alpha\),\(\beta,\) and \(\beta^{\prime}\) comprise the polymerase core enzyme. The fifth subunit, \(\sigma\), is involved only in termination. The polymerase comprised of all five subunits is called the holoenzyme.

What is often the first amino acid added to a polypeptide chain? a. adenine b. leucine c. methionine d. thymine

Which of the following features distinguishes eukaryotic transcription from bacterial transcription? a. Eukaryotic transcription does not start at a consensus sequence. b. Eukaryotic transcription does not require an initiation complex. c. Eukaryotic transcription and translation do not take place at the same time. d. Eukaryotic transcription does not require a termination sequence.

What would happen if the 5’ methyl guanosine was not added to an mRNA? a. The transcript would degrade when the mRNA moves out of the nucleus to the cytoplasm. b. The mRNA molecule would stabilize and start the process of translation within the nucleus of the cell. c. The mRNA molecule would move out of the nucleus and create more copies of the mRNA molecule. d. The mRNA molecule would not be able to add the poly-A tail on its strand at the 5’ end.

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