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Which set of results was found in the Meselson and Stahl’s experiments? a. The original chromosome was kept intact and a duplicate was made. b. The original chromosome was split and half went to each duplicate. c. The original chromosome was mixed with new material and each duplicate strand contained both old and new. d. The original chromosome was used as a template for two new chromosomes and discarded.

Short Answer

Expert verified
The original chromosome was split and half went to each duplicate.

Step by step solution

01

- Understand the context

Meselson and Stahl conducted experiments on DNA replication to understand how it duplicates. Their experiments showed how DNA is copied in cells.
02

- Comprehend the Models of DNA Replication

There are three proposed models of DNA replication: Conservative (option a), Semi-conservative (option b), and Dispersive (option c). Meselson and Stahl's experiments focused on determining which of these models is correct.
03

- Review Meselson and Stahl's Methods

Meselson and Stahl used nitrogen isotopes (15N and 14N) to distinguish between original and new DNA strands. They grew E. coli in a medium containing 15N and then shifted them to a 14N medium, allowing them to observe the subsequent generations of DNA.
04

- Assess the Experimental Results

After one round of replication, they found DNA with intermediate density, suggesting that it contained one old and one new strand. After two rounds, they found both intermediate and light DNA, confirming that each new DNA molecule consisted of one old and one new strand.
05

- Conclusion

The results supported the semi-conservative model of DNA replication. Therefore, each DNA molecule consists of one original strand and one new strand.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

DNA replication models
There are three main models of DNA replication proposed by scientists: Conservative, Semi-Conservative, and Dispersive. Each model describes a different way of how DNA could potentially copy itself.

In the **Conservative model**, the original DNA molecule remains intact, and a completely new copy is made. Imagine making a photocopy of a piece of paper without changing the original. This means that after replication, one molecule would be all old DNA, and the other would be all new DNA.

In the **Semi-Conservative model**, the DNA molecule separates into two strands. Each original strand then serves as a template for a new strand. This results in two DNA molecules, each with one old and one new strand of DNA. This model is often compared to zippering.

In the **Dispersive model**, the original DNA molecule is cut into small pieces and mixed with new segments. Each resulting DNA molecule contains a mix of old and new DNA dispersed throughout. This would be like cutting a string into pieces, mixing in new segments, and then reassembling them.

Knowing these models helps us understand the intricate process of DNA replication better. Meselson and Stahl's experiments were pivotal in determining which of these models correctly explains DNA replication.
Semi-conservative replication
Meselson and Stahl's experiments provided strong evidence supporting the semi-conservative model of DNA replication. In this model, the double helix of DNA unwinds and each single strand then serves as a template for making a new complementary strand. Here’s how it works:

  • First, the double-stranded DNA molecule unwinds.
  • Each of the two single strands serves as a template for the formation of a complementary strand.
  • New nucleotides are added to the growing strand by complementary base pairing (A with T, and C with G).
  • This produces two DNA molecules, each composed of one original strand and one new strand.

Meselson and Stahl confirmed the semi-conservative model by using isotopes of nitrogen. They showed that after the first round of replication, DNA molecules had an intermediate density, meaning each DNA molecule had one old and one new strand. This finding was consistent with the semi-conservative model and not with the other models.
Nitrogen isotopes in DNA
Nitrogen isotopes, specifically \(^{15}N\) (heavy nitrogen) and \(^{14}N\) (light nitrogen), played a crucial role in Meselson and Stahl's experiments. DNA contains nitrogen atoms, primarily in its bases, making these isotopes perfect for distinguishing between old and new DNA strands.

Here’s how they did it:
  • They grew E. coli bacteria in a medium containing \(^{15}N\), so that all the bacterial DNA incorporated this heavy nitrogen, making it denser.
  • Next, they transferred these bacteria to a \(^{14}N\) medium and allowed them to replicate.
  • After one round of replication, they extracted the DNA and used a technique called density gradient centrifugation to separate the heavy and light DNA. They found DNA with an intermediate density, indicating it was composed of one old (\(^{15}N\)) and one new (\(^{14}N\)) strand.
  • After a second round of replication, they found both intermediate and light DNA, supporting the semi-conservative model.

By tracking the nitrogen isotopes, Meselson and Stahl provided clear visual evidence of the semi-conservative mechanism of DNA replication. This method elegantly showed how each new DNA molecule is composed of one original strand and one newly synthesized strand.

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Most popular questions from this chapter

Which enzyme is only found in prokaryotic organisms? a. DNA gyrase b. helicase c. ligase d. telomerase

Discuss the significance of mutations in tRNA and rRNA. a. Mutations in tRNA and rRNA would lead to the production of defective proteins or no protein production. b. Mutations in tRNA and rRNA would lead to changes in the semi-conservative mode of replication of DNA. c. Mutations in tRNA and rRNA would lead to production of a DNA strand with a mutated single strand and normal other strand. d. Mutations in tRNA and rRNA would lead to skin cancer in patients of xeroderma pigmentosa

What is a purine? a. a double ring structure with a six-membered ring fused to a five-membered ring b. a single six-membered ring c. a six-membered ring d. three phosphates covalently bonded by phosphodiester bonds

What is bacterial transformation? a. The transformation of a bacterium occurs during replication. b. It is the transformation of a bacterium into a pathogenic form. c. Transformation of bacteria involves changes in its chromosome. d. Transformation is a process in which external DNA is taken up by a cell, thereby changing morphology and physiology.

How can Chargaff’s rules be used to identify different species? a. The amount of adenine, thymine, guanine, and cytosine varies from species to species and are not found in equal quantities. They do not vary between individuals of the same species and can be used to identify different species. b. The amount of adenine, thymine, guanine, and cytosine varies from species to species and is found in equal quantities. They do not vary between individuals of the same species and can be used to identify different species. c. The amount of adenine and thymine is equal to guanine and cytosine and is found in equal quantities. They do not vary between individuals of the same species and can be used to identify different species. d. The amount of adenine, thymine, guanine, and cytosine varies from species to species and they are not found in equal quantities. They vary between individuals of the same species and can be used to identify different species.

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