/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 A man who is color-blind marries... [FREE SOLUTION] | 91Ó°ÊÓ

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A man who is color-blind marries a woman who has normal color vision and does not carry the trait for color blindness. What statement will be true of their children? (A) All their sons will be normal, and all their daughters will be carriers. (B) All their sons will be normal, and all their daughters will be color- blind. (C) All their sons will be color-blind, and all their daughters will be normal. (D) All their sons will be color-blind, and all their daughters will be carriers. (E) All their daughters will be carriers, but the genotype of the sons cannot be determined.

Short Answer

Expert verified
(A) All their sons will be normal, and all their daughters will be carriers.

Step by step solution

01

Understanding the Genetics

Color blindness is an X-linked recessive condition. This means that the gene responsible is located on the X chromosome. Men (XY) inherit one X chromosome from their mother and one Y chromosome from their father, while women (XX) inherit one X chromosome from each parent.
02

Genotype Analysis for the Parents

The man is color-blind, which means his X chromosome contains the color-blind allele ( X^c ). The woman has two normal X chromosomes ( X^N X^N ) because she does not carry the trait for color blindness.
03

Determine Sons' Genotypes

Sons inherit the Y chromosome from their father and one X chromosome from their mother. Thus, each son will have the genotype ( X^N Y ), where X^N is the normal vision gene from the mother.
04

Determine Daughters' Genotypes

Daughters inherit one X chromosome from each parent. Thus, each daughter will have the genotype ( X^N X^c ). They will have one normal vision gene from their mother and one color-blind gene from their father, making them carriers of color blindness.
05

Conclusion Based on Genotypes

Analyzing the genotypes: All sons will have normal vision ( X^N Y ), and all daughters will be carriers ( X^N X^c ) of color blindness. This matches the statement of option A.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

X-linked recessive inheritance
X-linked recessive inheritance is a way that certain genetic traits or conditions can be passed down through families. These traits are linked to genes found on the X chromosome.

Since males have one X chromosome and one Y chromosome (XY), they will express the trait if the recessive gene is present on their X chromosome, because they do not have another X chromosome that could potentially carry a normal allele to mask it. Therefore, males are more likely to exhibit X-linked recessive traits.

Females have two X chromosomes (XX), so they can be carriers if the trait is present on only one of their X chromosomes. It requires both X chromosomes to carry the recessive trait for the female to express the condition. Being a carrier means that while they do not show symptoms of the trait, they can still pass the allele on to their offspring.

In conclusion, X-linked recessive inheritance often results in more males being affected, while females are more often carriers. This understanding is key when predicting the inheritance of such traits in families.
color blindness
Color blindness is a common genetic condition where an individual has difficulty distinguishing between certain colors. This is due to a variation in one of the genes that produces the photopigments in the eye.

Most commonly, color blindness affects the ability to see red and green colors, and it is more prevalent in males because the responsible gene is located on the X chromosome. Because women have two X chromosomes, they are less likely to be color-blind themselves but can carry and pass the color-blind gene to their children.

The gene that causes color blindness is recessive, which means it is typically masked by a dominant normal vision allele. This factor plays a crucial role in determining how the condition is passed on and who may express it. In families where color blindness is present, understanding these genetic patterns is essential for predicting how likely children are to be affected.
genotype analysis
Genotype analysis involves studying the genetic constitution of an individual in order to understand what traits they might express and pass on to their offspring. Genotype is represented by letters: one for each allele inherited from each parent.

In the context of X-linked recessive conditions like color blindness, examining the X chromosome is particularly important. For example, when analyzing a couple's potential offspring, the father can pass either an X or Y chromosome, whereas the mother can pass only one of her two X chromosomes.

By analyzing genotypes, you can determine whether a transmitted allele is responsible for color blindness or not. This involves looking at whether an X chromosome from either parent carries the normal vision allele ( X^N ) or the color-blind allele ( X^c ). Through such analysis, we can predict the presence of traits in a family's next generation and understand why certain family members may exhibit a trait while others do not.
inheritance patterns
Inheritance patterns explain how genetic traits are transmitted from one generation to the next. For X-linked recessive traits like color blindness, these patterns have distinct characteristics.

When a mother is a carrier and a father has the trait, there are predictable outcomes for their children. Sons receive their X chromosome from their mother and the Y chromosome from their father. Therefore, if the mother has a normal vision gene to pass, the sons are not color-blind. Daughters receive one X chromosome from each parent, making them carriers if they receive the recessive X-linked gene from their father who has the trait.

In our specific scenario, with a color-blind father and a mother with normal vision, all sons will have normal vision since they inherit the Y from the father and a normal X from the mother. All daughters will be carriers, receiving one normal X from the mother and the recessive color-blind X from the father. This type of pattern helps predict the presence and absence of certain conditions and guides many aspects of genetic counseling and family planning.

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