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Chapter 12: Q. 4 (page 326)

Figure 12.16 In pea plants, purple flowers (P) are dominant to white flowers (p) and yellow peas (Y) are dominant to green peas (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares do you need to do a Punnett square analysis of this cross?

Short Answer

Expert verified

PyYY (purple flower and yellow peas), PpYy (purple flower and yellow peas), ppYY (white flower and yellow peas), and ppYy (white flower and yellow peas)

Step by step solution

01

Step 1. Given introduction

According to the question in a pea plant, white flower (p) is recessive to purple flowers (P) and green peas (y) are recessive to yellow peas (Y). PpYY is crossed with ppYy.

02

Step 2. Explanation  

When PpYY is crossed with ppYy, the possible genotypes of the offspring are PyYY, PpYy, ppYY, and ppYy.

PyYY genotype plant will show yellow peas and purple flowers.

PpYy genotype plant will also show yellow peas and purple flowers.

ppYY genotype plant will have white flowers and yellow peas.

ppYy genotype plant will also have white flowers and yellow peas.

So the ratio of each phenotype will be 1:1 (white flower and yellow peas to purple flower and yellow peas).

In this total 2 x 2 punnet squares will be required for this analysis because two of the alleles are homozygous.

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