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Chapter 12: Q. 30 (page 328)

Use the probability method to calculate the genotypes and genotypic proportions of a cross between AABBCc and Aabbcc parents

Short Answer

Expert verified

As a result, the ratios are 1:1:1:1.

Step by step solution

01

Step. 1 Introduction

A genotype is a series of genes that encode in a particular individual's genetic characteristics. The genotypic ratio refers to the ratio that depicts the various genotypes of children out of a test cross.

02

Step. 2 Explanation

You fully understand the genomes of the parents, where you need to differentiate into pair of alleles, both genes, for the cross. AABBCc is divided similarly to ABC and ABc. Aabbcc is divided similarly to Abc and abc. You can now cross them, and the probabilities are: AABbCc, AaBbCc, AABbcc, & AaBbcc. So, 25% of the progeny would be AaBbCc, 25% would be AaBbcc, 25% would be AABbCc, and 25% will be AABbcc.

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Most popular questions from this chapter

A heterozygous pea plant produces violet flowers and yellow, round seeds. Describe the expected genotypes of the gametes produced by Mendelian inheritance. If all three genes are found on the same arm of one chromosome should a scientist predict that inheritance patterns will follow Mendelian genetics?

Use a Punnett square to predict the offspring in a cross between a dwarf pea plant (homozygous recessive) and a tall pea plant (heterozygous). What is the phenotypic ratio of the offspring?

Which is one of the seven characteristics that Mendel observed in pea plants?

a. flower size

b. seed texture

c. leaf shape

d. stem color

Describe one of the reasons why the garden pea was an excellent choice of model system for studying inheritance.

Why is it more efficient to perform a test cross with a homozygous recessive donor than a homozygous dominant donor? How could the same information still be found with a homozygous dominant donor?
See all solutions

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