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The forked line and probability methods make use of what probability rule?

a. test cross

b. product rule

c. monohybrid rule

d. sum rule

Short Answer

Expert verified

The correct answer is (b). product rule

Step by step solution

01

Introduction

The fork line method can be used by figuring the occurrence of each gene or set of genes to be found in the gamete and then multiplying them together. This can be multiplied by figuring each trait or combination of traits separate for both the male and female or each gene individually regardless of sex.

The product rule states that the probability of two independent events occurring together can be calculated by multiplying the individual probabilities of each event occurring alone.

02

Explanation for the correct answer

While the forked-line method is a diagrammatic approach to keeping track of probabilities in a cross, the probability method gives the proportions of offspring expected to exhibit each phenotype (or genotype) without the added visual assistance. Both methods make use of the product rule and consider the alleles for each gene separately. Hence, option (b) is the correct answer.

03

Explanation for the incorrect options

a. test cross

Test cross is the cross between F1individual and the recessive parent. This cross is used to check the purity of the genotype, and to know the genotype of the organism. It is not a probability rule. Hence, option (a) is the incorrect option.

c. monohybrid rule

Monohybrid rule is the cross between individuals differing in a single characteristic, that is having different alleles at a single locus. The forked line and probability methods do not make use of the monohybrid rule. Hence, option (c) is the incorrect option

d. sum rule

According to sum rule, of the two mutually exclusive events, the probability of the occurrence of at least one event is the sum of their probabilities individually. The sum rule is not applied to two independently occurring events as in forked line method. Hence, option (d) is the incorrect answer.

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Most popular questions from this chapter

The ABO blood groups in humans are expressed as the I A , I B , and i alleles. The I A allele encodes the A blood group antigen, I B encodes B, and i encodes O. Both A and B are dominant to O. If a heterozygous blood type A parent (I A i) and a heterozygous blood type B parent (I B i) mate, one quarter of their offspring will have AB blood type (I A I B ) in which both antigens are expressed equally. Therefore, ABO blood groups are an example of:

a. multiple alleles and incomplete dominance

b. codominance and incomplete dominance

c. incomplete dominance only

d. multiple alleles and codominance

Use a Punnett square to predict the offspring in a cross between a dwarf pea plant (homozygous recessive) and a tall pea plant (heterozygous). What is the phenotypic ratio of the offspring?

In Section 12.3, 鈥淟aws of Inheritance,鈥 an example of epistasis was given for the summer squash. Cross white WwYy heterozygotes to prove the phenotypic ratio of 12 white:3 yellow:1 green that was given in the text.

The ABO blood groups in humans are expressed as the IA, IB, and i alleles. The IA allele encodes the A blood group antigen, IB encodes B, and i encodes O. Both A and B are dominant to O. If a heterozygous blood type A parent (IAi) and a heterozygous blood type B parent (IBi) mate, one-quarter of their offspring will have AB blood type (IAIB) in which both antigens are expressed equally. Therefore, ABO blood groups are an example of:

  1. multiple alleles and incomplete dominance

  2. codominance and incomplete dominance

  3. incomplete dominance only

  4. multiple alleles and codominance

Figure 12.12 What ratio of offspring would result from a cross between a white-eyed male and a female that is heterozygous for red eye color?

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