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The pea plants used in Mendel’s genetic inheritance studies were diploid, with 14 chromosomes in somatic cells. Assuming no crossing-over events occur, how many unique gametes could one pea plant produce?

a. 28

b. 128

c. 196

d. 16,384

Short Answer

Expert verified

The correct answer is option b

Step by step solution

01

Step 1. Introduction

Organisms can form 2nunique combinations of chromosomal compositions or gametes where n refers to number of homologous pairs.

02

Step 2. Explanation for the correct option

Option b is correct because organisms can form 2nunique combinations of chromosomal compositions where n refers to number of homologous pairs. Diploid organisms like pea carry two complete sets of homologous chromosomes. Pea makes 7 pairs of homologous chromosomes. So it forms 27 or 128 unique gametes.

03

Step 3. Explanation for the incorrect options

Option a is incorrect because pea forms 2n = 27 unique gametes. So 128 is correct instead of 28.

Option b is incorrect because pea forms 2n = 27 unique gametes. So 128 is correct instead of 196.

Option d is incorrect because pea forms 2n = 27 unique gametes. So 128 is correct instead of 16384.

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